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RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3

February 18, 2019 by Veer Leave a Comment

RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 is part of RBSE Solutions for Class 10 Maths. Here we have given Rajasthan Board RBSE Class 10 Maths Chapter 1 वैदिक गणित Exercise 1.3.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 10
Subject Maths
Chapter Chapter 1
Chapter Name वैदिक गणित
Exercise Exercise 1.3
Number of Questions Solved 20
Category RBSE Solutions

Rajasthan Board RBSE Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3

वैदिक विधियों द्वारा वर्गमूल ज्ञात कीजिए।

प्रश्न 1.
2116
हल:
भाग विधि से—
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 1

RBSE Solutions

प्रश्न 2.
4225 द्वन्द्व योगविधि द्वारा
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 2
द्वन्द्व योग विधि-

  1. संख्या में दो जोड़े हैं अतः वर्गमूल में 2 अंक होंगे।
  2. प्रथम वर्गमूल अंक = 6, शेषफल 42 – 36 = 6, इसे 2 से(RBSESolutions.com) पूर्व लिखां नया भाज्य 62 तथा संशोधित भाज्य = 62 है अतः 62 : 12 = 5 इसे 6 के आगे शेषफल = 2 जो 2 व 5 के मध्य लिखते हैं। नया भाज्य 25 तथा अन्तिम शेषफल = 25 – 25 = 0

प्रश्न 3.
6889 (माध्य. शिक्षा बोर्ड, 2018)
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 3
\(\sqrt { 6889 } =83\) उत्तर

RBSE Solutions

प्रश्न 4.
59049
हल:
भाग विधि से-
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 4

प्रश्न 5.
125316
हल:
द्वन्द्व योग विधि द्वारा-
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 5
संकेत-

  1. संख्या के तीन जोड़े हैं अतः वर्गमूल के 3 अंक(RBSESolutions.com) होंगे। प्रथम वर्गमूल अंक = 3, शेषफल = 12 – 9 = 3
  2. नया भाज्य 35, संशोधित भाज्य भी 35 अतः 35 ÷ 6 = 5, शेषफल = 5
    नया भाज्य = 53, संशोधित भाज्य 53 – 52 = 28 ÷ 6 = 4, शेषफल 4, यहाँ अन्तिम शेषफल ज्ञात करना है। नया भाज्य 41 – 2 x 5 x 4 = 1
    नया भाज्य = 16, अन्तिम शेषफल 16 – 42 = 0 अतः

\(\sqrt { 125316 } =16\) उत्तर

प्रश्न 6.
16744
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 6
अंतः \([\sqrt { 169744 } =412\) उत्तर
संकेत-

  1. संख्या के तीन जोड़े हैं अतः वर्गमूल के 3 अंक(RBSESolutions.com) होंगे। प्रथम वर्गमूल अंक = 3, शेषफल = 12 – 9 = 3
  2. नया भाज्य 35, संशोधित भाज्य भी 35 अतः 35 ÷ 6 = 5, शेषफल = 5
  3. नया भाज्य = 53, संशोधित भाज्य 53 – 52 = 28 ÷ 6 = 4, शेषफल 4, यहाँ अन्तिम शेषफल ज्ञात करना है। नया भाज्य 41 – 2 x 5 x 4 = 1

RBSE Solutions

प्रश्न 7.
1265625
हल:
भाग विधि से—
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 7

प्रश्न 8.
1522756
हल:
भाग विधि से—
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 8
संकेत-

  1. वर्गमूल में 4 अंक, होंगे।
  2. प्रथम वर्गमूल अंक = 1 शेषफल = 0 जिसे 5 से पूर्ण लिखा जायेगा।
  3. 05 ÷ 2 = 2 तथा शेष 1 अतः संशोधित(RBSESolutions.com) भाज्य 12 ÷ 22 = 8
  4. 8 ÷ 2 = 4 तथा शेषफल शून्य अतः 8 = 2 = 3 लेकर शेषफल 2 प्राप्त करते हैं।
  5. संशोधित भाज्य 22 – 12 = 10 अतः \(\sqrt { 15\quad 22\quad 756 } =1234\) उत्तर

RBSE Solutions

वैदिक विधियों द्वारा पूर्ण घन संख्या का घनमूल ज्ञात कीजिये।

प्रश्न 9.
68921
हल:
भाग विधि से-
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 9
अतः 68921 का घनमूल = 41
संकेत-

  1. अन्तिम समूह 68 – 43 = 4
  2. घनमूल अंक 4 ऊपर(RBSESolutions.com) लिखा। नया भाज्य = 49
  3. नये भाज्य में 3 x 42 x 1 = 48 का भाग दिया।
  4. भागफल अंक 1 ऊपर लिखा। 3 x 42 x 1 घटाया। शेषफल = 1, नया भाज्य = 12
  5. 12 – 3 x 4 x 12 = 12, शेषफल = 0
  6. नया भाज्य = 01 – 13 = 0
    अतः घनमूल = 41 उत्तर

RBSE Solutions

प्रश्न 10.
636056
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 10

प्रश्न 11.
314432
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 11

प्रश्न 12.
493039
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 12

RBSE Solutions

प्रश्न 13.
8365427
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 13
अतः घनमूल = 203 उत्तर

प्रश्न 14.
1061208
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 14

प्रश्न 15.
8489664
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 15
अतः 8489664 का(RBSESolutions.com) घनमूल = 204 उत्तर

प्रश्न 16.
200201625
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 16

प्रश्न 17.
258474853
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 17
अतः 258474853 का(RBSESolutions.com) घनमूल = 637 उत्तर

RBSE Solutions

प्रश्न 18.
22665187
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 18

RBSE Solutions

प्रश्न 19.
8615125
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 19

प्रश्न 20.
660776311
हल:
RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 20
RBSE Solutions

We hope the RBSE Solutions for Class 10 Maths Chapter 1 वैदिक गणित Ex 1.3 help you. If you have any query regarding Rajasthan Board RBSE Class 10 Maths Chapter 1 वैदिक गणित Exercise 1.3, drop a comment below and we will get back to you at the earliest.

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