RBSE Solutions for Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3

RBSE Solutions for Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3 is part of RBSE Solutions for Class 10 Maths. Here we have given Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Exercise 17.3.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 10
Subject	Maths
Chapter	Chapter 17
Chapter Name	Measures of Central Tendency
Exercise	Exercise 17.3
Number of Questions Solved	6
Category	RBSE Solutions

Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3

Find the mean (arithmetic) of following (RBSESolutions.com) frequency distribution (Q. 1 – 4)
Question 1.

Solution :
Calculation of arithmetic mean

Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 1580 }{ 60 } \) = 26.33(approx)

Question 2.

Solution :
Calculation of arithmetic (RBSESolutions.com) mean

Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 618 }{ 40 } \) = 15.45

Question 3.

Solution:
Calculation of arithmetic mean :

Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 10200 }{ 70 } \) = 145.71
Thus, required (RBSESolutions.com) arithmetic mean = 145.71

Question 4.

Solution:
Calculation of arithmetic mean :

Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 1980 }{ 40 } \) = 49.5
Thus, required arithmetic mean = 49.5

Question 5.
Find mean of the following (RBSESolutions.com) frequency distribution :

Solution:

Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 6820 }{ 100 } \) = 68.2
Thus, frequency distribution mean = 68.2

Question 6.
The salary of employees in a factory are (RBSESolutions.com) according to following table :

Find the arithmetic mean of salary.
Solution :
Calculation of arithmetic mean :

Arithmetic mean = \(\frac { { \Sigma f }_{ i }{ x }_{ i } }{ { \Sigma f }_{ i } } =\frac { 102000 }{ 70 } \) = 1457.14
Thus, arithmetic (RBSESolutions.com) mean of salary = ₹ 1457.14

We hope the given RBSE Solutions for Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Exercise 17.3, drop a comment below and we will get back to you at the earliest.