Rajasthan Board RBSE Class 12 Maths Chapter 10 Definite Integral Ex 10.2
Find the value of the following integrals :
Question 1.
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Question 2.
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Question 3.
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Question 4.
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Question 6.
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Question 7.
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Question 8.
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Question 10.
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Question 11.
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Question 15.
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Question 20.
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Question 24.
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Question 25.
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Question 26.
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\([\log (x+1)]_{1}^{2}-[\log (x+2)]_{1}^{2}\)
= [log (2 + 1) – log (1 + 1)]
– [log (2+ 2)-log (1 +2)]
= log 3 – log 2 – log 4 + log 3
= 2 log 3 – (log 2 + log 4)
= 2 log 3 – log 8
= log \(\frac { { 3 }^{ 2 } }{ 8 } \) = log \(\frac { 9 }{ 8 } \)
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