## Rajasthan Board RBSE Class 12 Maths Chapter 10 Definite Integral Ex 10.2

**Find the value of the following integrals :**

Question 1.

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Question 2.

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Question 9.

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Similar Question

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Question 10.

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Question 11.

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Question 12.

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Question 15.

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Question 16.

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Question 17.

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Question 18.

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Question 20.

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Question 26.

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\([\log (x+1)]_{1}^{2}-[\log (x+2)]_{1}^{2}\)

= [log (2 + 1) – log (1 + 1)]

– [log (2+ 2)-log (1 +2)]

= log 3 – log 2 – log 4 + log 3

= 2 log 3 – (log 2 + log 4)

= 2 log 3 – log 8

= log \(\frac { { 3 }^{ 2 } }{ 8 } \) = log \(\frac { 9 }{ 8 } \)

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