RBSE Solutions for Class 5 Maths Chapter 10 Currency Ex 10.1

RBSE Solutions for Class 5 Maths Chapter 10 Currency Ex 10.1 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Exercise 10.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 5
Subject	Maths
Chapter	Chapter 10
Chapter Name	Currency
Exercise	Ex 10.1
Number of Questions	10
Category	RBSE Solutions

Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Ex 10.1

Question 1.
A farmer sells wheat for 2058 rupees and 25 paise and corn for 1154 rupees 50 paise, for how much money he has sold total grain?
Solution.

Therefore he has sold total grain for ₹ 3212 and 75 paise.

Question 2.
A shopkeeper went to market with 8575 rupees and 75 paise. Out of these he(RBSESolutions.com)paid 5052 rupees 25 paise for clothes and 2070 rupees 25 paise for grocery. Now how much money is left with the shopkeeper?
Solution.

Therefore, 1453 Rupees 25 paise left with him.

Question 3.
Solve-
(i) 525 Rs. 25 Paise x 13
(ii) 507 Rs. 75 Paise x 16
(iii) 899 Rs. 50 Paise x 17
(iv) 726 Rs. 72 Paise x 19
Solution.
(i) 525 Rs. 25 Paise x 13

Therefore, 6828 Rupees 25 Paise.

(ii) 507 Rs. 75 Paise x 16

Therefore, 8124 Rs.

(iii) 899 Rs. 50 Paise x 17

Therefore, 15291 Rupees 50 Paise.

(iv) 726 Rs. 72 Paise x 19

Therefore, 13807 Rupees 68 Paise.

Question 4.
13 women of Gorela village got 35755 rupees 20 paise for buying sewing(RBSESolutions.com)machine under Pradhanmantri Swarojgar Yojna. How much money each woman would have received ?
Solution.

Therefore each woman received 2750 Rupees 40 Paise.

Question 5.
Sujal bought ५ kg. of rice at the rate of ४५ rupees ५0 paise per kg and ३ kg of sugar at the(RBSESolutions.com)rate of २८ rupees ६0 paise per kg. Now he was left with २४५ rupees ६0 paise. Find out the total money he had in the begining ?
Solution.

Question 6.
Price of a shirt is ३२६ rupees ५0 paise and price of a(RBSESolutions.com)pant is ७८0 rupees ६0 paise, find out the total of ३ shirts and ५ pants.
Solution.


Therefore, total price of ३ shirts and ५ pants = ४८८२ rupees ५0 paise.

Question 7.
A fruit seller went to market with 35916 rupees, from this he has(RBSESolutions.com)paid 12763 rupees 30 paise for apple, 13243 rupees 30 paise for grapes and 947 rupees 25 paise for banana. Now how much money is left with him ?
Solution.

Therefore, money left with fruit seller is 8962 rupees 15 paise.

Question 8.
Mira has 20974 rupees 80 paise, of these she had(RBSESolutions.com)spend 10544 rupees 40 paise and remaining amount, she equally divides between her son and daughter. How many rupees each will get ?
Solution.

She wants to divides remaining amount equally between her son and daughter means, divide the money by 2.

Therefore each son and daughter will get 5215 Rs. 20 paise.

Question 9.
Price of a cycle is 1075 rupees 50 paise. What will be the price of such 52 cycles ?
Solution.
To find price of 52 cycles we have to(RBSESolutions.com)multiply price of one cycle by 52.

Therefore, price of 52 cycles will be Rs. 55926.

Question 10.
Add 25081 rupees 75 paise, 70860 rupees 60 paise and 9876 rupees 42 paise.
Solution.

We hope the RBSE Solutions for Class 5 Maths Chapter 10 Currency Ex 10.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 10 Currency Exercise 10.1, drop a comment below and we will get back to you at the earliest.