RBSE Solutions for Class 5 Maths Chapter 12 Weight In Text Exercise is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 12 Weight In Text Exercise.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Maths |

Chapter |
Chapter 12 |

Chapter Name |
Weight |

Exercise |
In Text Exercise |

Number of Questions |
7 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 5 Maths Chapter 12 Weight In Text Exercise

**Page No. 62
**Question 1.

Convert 4 kilogram into gram.

Solution.

4 Kilogram = ……… gram

4 Kilogram = I kilogram + 1 kilogram + 1 kilogram + 1 kilogram

∵ 4 Kilogram = 1000 gram + 1000 gram + 1000 gram + 1000 gram = 4000 gram

or 4 x 1000 gram = 4000 gram.

**Page No. 63 **

Question 1.

Convert 3000 gram into kilogram.

Solution.

3000 gram = ……… kilogram

∵ 3000 gram = 1000 gram + 1000 gram + 1000 gram

3000 gram = 1 kilogram + 1 kilogram + 1 kilogram

3000 gram = 3 kilogram = \(\frac { 3000 }{ 1000 }\) = 3 kg.

or 3000 – 1000 = 3 kilogram

Question 2.

**Fill in the blanks**

1. (i) 200 gram = …….. kilogram

(ii) 400 gram = …….. kilogram

(iii) 1250 gram = …….. kilogram

2. Convert \(1\frac { 1 }{ 4 }\) kilogram into grams

3. Convert \(1\frac { 3 }{ 4 }\) kilogram into grams

Solution.

1. (i) 200 gram = \(\frac { 200 }{ 1000 }\) kilogram = \(\frac { 2 }{ 10 }\) kg

= \(\frac { 1 }{ 5 }\) kilogram

(ii) 400 gram = \(\frac { 400 }{ 1000 }\) kg. = \(\frac { 4 }{ 10 }\) kg

= kilogram

(iii) 1250 gram = 1000 gram + 250 gram

= \(\frac { 1000 }{ 1000 }\) kg + \(\frac { 250 }{ 1000 }\) kg

= 1 kg + \(\frac { 1 }{ 4 }\) kg = \(1\frac { 1 }{ 4 }\) kg..

2. \(1\frac { 1 }{ 4 }\) kilogram = 1 kilogram + \(\frac { 1 }{ 4 }\) kilogram

= 1000 gram + \(\frac { 1 }{ 4 }\) × 1000 gram

= 1000 gram + 250 gram

= 1250 gram

3. \(1\frac { 3 }{ 4 }\) kg. = 1 kg + \(\frac { 3 }{ 4 }\) kg

= 1000 gram + \(\frac { 3 }{ 4 } \) 1000 gram

= 1000 gram + 3 × 250 gram

= 1000 gram + 750 gram

= 1750 gram

**Page No. 64
**Question 1.

Find weight of following(RBSESolutions.com)with the help of these weighting units ?

Solution.

Question 2.

Ramesh has one 5 kg and one 500 gm. of iron weight unit. He wants to weight out 4 kg and 500 gm of sugar. Look at the balance carfully and discuss, what would be the(RBSESolutions.com)amount of sugar in the bag, is it 4 kg and 500 gram ?

Solution.

Since, sugar bag with the weight unit 500 gm is equal to 5 kg of weight

so, the amount of sugar in the bag is 500 gm less than 5 kg.

Therefore, weight of sugar = 5 kg – 500 gm

= 4 kg 500 gm

**Page No. 65 **

**Try It
**Question 1.

Weigh out 300 gm with the help of 500 gm and 200 gm iron weight units.

Solution.

If you want to weight 300 grams then(RBSESolutions.com)weight by 500 gram iron weighing unit and put 200 gram iron weighing unit in this weight and weigh equal to 500 gram. This weight is equal to 300 gram.

Question 2.

Weigh out 700 gram with the help of 1 kg. 200 gram and 100 gram iron weight units.

Solution.

To weight 700 gram with the help(RBSESolutions.com)of 1 kg 200 grams and 100 gram iron weight units, put one side 1 kg and other side 200 gram and 100 gram iron weight units and weigh it. This weighing weight is 700 gram.

We hope the RBSE Solutions for Class 5 Maths Chapter 12 Weight In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 12 Weight In Text Exercise, drop a comment below and we will get back to you at the earliest.

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