RBSE Solutions for Class 5 Maths Chapter 14 Perimeter and Area Additional Questions is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area Additional Questions.
|Chapter Name||Perimeter and Area|
|Number of Questions||19|
Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area Additional Questions
Multiple Choice Questions
(a) Space occupied by object in air
(b) Space occupied by object in water
(c) Space occupied by object in plane
(d) Space occupied by object in any liquid
Space occupied by any shape on grid paper is find out by
(a) By drawing ray diagram of object
(b) By counting(RBSESolutions.com)number of squares covered by object
(c) By cutting graph paper of size of object
(d) None of the above.
External measurement of given figure
(a) 24 cm.
(b) 44 cm.
(c) 54 cm.
(d) 36 cm.
The length and width of the book is 6 cm. and 5 cm. How many (RBSESolutions.com)this book covered on graph paper.
The length of a envelop is 15 cm. and width is 20 cm. then external measurement of the envelop is
(a) 60 cm.
(b) 70 cm.
(c) 80 cm.
(d) 90 cm.
Unit of Area in meter is
(a) Square meter
(c) Meter cube
Formula to find perimeter of square
(a) Side × Side
(b) Length + Width
(c) Length ÷ Width
(d) 4 × Side
If the side of a square is 5 meter then(RBSESolutions.com)area of square in the following is
(a) 10 meter
(b) 25 meter
(c) 25 square meter
(d) 15 square meter
Fill in the blanks of the following
1. Area of rectangle = ………… × Width
2. Space covered by an object is called ………… of this object.
3 ………… of open shapes(RBSESolutions.com)can not be determined
4. Perimeter of regular shapes = ………… × measurement of side.
5. Perimeter of rectangle = 2 × ( ………… + width)
4. No. of sides
Very Short Answer Type Questions
Measurement of three sides of a triangle is 4 cm, 5 cm and 6 cm. Write external measurement of the triangle.
External measurement of triangle = Sum of three sides of triangle
= 4 cm. + 5 cm. + 6 cm. = 15 cm.
Length of a packet of biscuit is 8 cm. and width is 4 cm. then (RBSESolutions.com)many squares it cover on graph paper ?
Find out external measurement of the shape given below.
External measurement = 16 + 2 + 10 + 3 + 2 + 3 + 2 + 3 + 2 + 5 = 48 cm.
Which is called perimeter ?
Total of the external measurement of any shape is called perimeter of the shape.
If the length of sitting is 30 cm (RBSESolutions.com)width 25 cm. then how much space it occupied on floor ?
Length of sitting = 30 cm.
Width of sitting = 25 cm.
Therefore total space occupied = 30 × 25 = 750 square cm.
Short Answer and Essay type Questions
The length of a mobile is 9 cm. and width is 4 cm. then calculate the space occupied by mobile. [Use 1 cm. × 1 cm. square grid paper.]
Length of mobile = 9 cm.
Width of mobile = 4 cm.
Mobile covers 36 squares on grid paper.
Draw the given shapes on 1 cm × 1 cm square grid paper and find out. If the length of(RBSESolutions.com)paper is 8 cm and width is 3 cm. then space occupied by paper is equal to how many squares ?
Length of paper = 8 cm.
Width of paper = 3 cm.
On drawing a shape of paper on grid paper we see that Number of square covered = 24.
Some shapes are given below on grid paper. Answer the following questions given below.
(1) Area of rectangle ABCD is =
(2) Area of rectangle PQRS is =
(3) Are the area of both rectangles equal.
(4) Perimeter of rectangle ABCE is =
(5) Perimeter of rectangle PQRS =
(6) Perimeter of which rectangle is more ?
(1) Length of rectangle ABCD = 4 cm.
Breadth of rectangle ABCD = 3 cm
∴ Area of rectangle ABCD =Length × Breadth
= 4 × 3 = 12 square cm.
(2) Length of rectangle PQRS = 6 cm.
Breadth of rectangle PQRS = 2 cm.
∴ Area of rectangle PQRS = Length × Breadth
= 6 × 2 = 12 square cm.
(3) Yes, area of both rectangle are equal.
(4) Length of rectangle ABCD =4 cm.
Breadth of rectangle ABCD = 3 cm.
∴ Perimeter of rectangle ABCD
= 2 (Lenght + Breadth)
= 2 (4 + 3)
= 2 × 7 = 14 cm.
(5) Length of rectangle PQRS = 6 cm
Breadth of rectangle PQRS = 2 cm
∴ Perimeter of rectangle PQRS = 2 (Length = Breadth)
= 2 (Length + Breadth)
= 2 (6 + 2)
= 2 × 8 = 16 cm.
(6) Perimeter of rectangle PQRS is more.
Length and width of a cloth is 10 cm. and 12 cm. How much long lace required(RBSESolutions.com)to put on its edge ? We have to put flower on it. On how much area flowers can be put ? [Use 1 cm. × 1 cm. square grid]
Length of cloth = 12 cm.
Width of cloth = 10 cm.
Length of lace used around the edge of cloth = 12 + 10 + 12 + 10 = 44 cm.
The number of squares when cloth(RBSESolutions.com)is laid on graph paper are 120.
Therefore area of space of hanky on which flowers are putted = 120 square cm.
Length and width of a pocket diary is 12 cm and 6 cm. Find its external measurement on drawing figure.
12 cm. + 12 cm. + 6 cm. + 6 cm. = 36 cm.
We hope the RBSE Solutions for Class 5 Maths Chapter 14 Perimeter and Area Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area Additional Questions, drop a comment below and we will get back to you at the earliest.