RBSE Solutions for Class 5 Maths Chapter 14 Perimeter and Area Ex 14.1 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area Exercise 14.1.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Perimeter and Area |

Exercise |
Ex 14.1 |

Number of Questions |
10 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area Ex 14.1

Question 1.

Find out the perimeter of given shapes.

Solution.

(a) Perimeter of the shape = 10 + 7 + 10 + 8 + 7 + 7 + 9 + 7 = 65 cm.

(b) Perimeter of the shape = 10 + 5 + 4 + 5 + 5 + 4 + 5 = 38 cm.

(c) Perimeter of the shape = 4 × side = 4 × 7 = 28 cm.

Question 2.

Find out the perimeter of(RBSESolutions.com)rectangular shapes with given measurements :

(a) Length = 30 cm. , Width = 48 cm.

(b) Length=20 cm. , Width = 34 cm.

(c) Length = 60 cm. , Width = 20 cm.

(d) Length = 30 cm. , Width = 12 cm.

Solution.

(a) Perimeter = 2 × (Length + Width)

= 2 × (30 + 48)

= 2 × 78

= 156 cm.

(b) Perimeter = 2 × (Length + Width)

= 2 × (20 + 34)

= 2 × 54

= 108 cm.

(c) Perimeter = 2 × (Length + Width)

= 2 × (60+20)

= 2 × 80

= 160 cm.

(d) Perimeter = 2 × (Length + Width)

= 2 × (30 + 12)

= 2 × 42

= 84 cm.

Question 3.

Find out the perimeter of(RBSESolutions.com)following regular shapes with the help of formula.

Solution.

(a) Perimeter of triangle = 3 × side = 3 × 14 = 42 cm.

(b) Perimeter of square = 4 × side = 4 × 6 = 24 cm.

(c) Perimeter of Hexagon = 6 × side = 6 × 6 = 36 cm.

(d) Perimeter of Pentagon = 5 × side = 5 × 9 = 45 cm.

Question 4.

Vijay has made a rectangle. Find its perimeter and area?

Can you extend its length and width in such a way, so that it has equal perimeter and area. (There is no need to increase both length and width)

**OR**

A rectangle is shown in the picture. Find the (RBSESolutions.com)and the area of this rectangle. Can you increase or decrease its length and width in this way so that its perimeter and area become the same. If yes then write their measurements.

Solution.

Perimeter of a rectangle made by Vijay = 2 × (Length + Width)

= 2 × (5 + 3)

= 2 × 8

= 16 cm.

Area of rectangle = Length × Width = 5 × 3 = 15 square cm.

If length of this rectangle is decreased by 1 cm. and breadth increased by 1 cm.

then its measurements become.

Then perimeter and(RBSESolutions.com)area of this square become equal.

Perimeter of square = 4 × side = 4 × 4 = 16 cm.

Area of square = (side)^{2 }= (4)^{2} = 16 sq.cm.

Question 5.

Length and width of a rectangular field are 25 meter and 30 meter respectively. Find its area?

Solution.

Area of rectangular field = Length × Width

= 25 × 30

= 750 square meter.

Question 6.

Length and width of a rectangular towel are 125 cm and 60 cm respectively. What will be the perimeter of the towel?

Solution.

Perimeter of(RBSESolutions.com)rectangular towel = 2 × (Length + Width)

= 2 × (125 + 60)

= 2 × 185

= 370 cm.

Question 7.

A square field needs 260 meter long barbed wire for throughout fencing. Find its one side?

Solution.

Perimeter of square = 4 × side

Question 8.

The length and width of a room floor is 8 meter and 7 meter respectively. In this room one(RBSESolutions.com)mat covers the entire floor. Find out the area of this mat.

Solution.

Length of floor = 8 meter

Width of floor = 7 meter

Area of floor = Area of mat

= Length × Width

= 8 × 7

= 56 square meter

Therefore Area of mat = 56 square meter.

Question 9.

Find out the perimeter of a square stool, whose side is 60 centimeter.

Solution.

Perimeter of square stool = 4 × side

= 4 × 60

= 240 centimeter

Therefore perimeter of stool = 240 centimeter.

Question 10.

To take around of a square field, Dev had to walk 40 meters. Find the side of the square field.

Solution.

Distance walked in two round = 40 meter

∴ Distance walked (RBSESolutions.com)one round = \(\frac { 40 }{ 2 }\) = 20 meter

Distance walked in one round is called perimeter

Therefore perimeter of square field = 20 meter

∵ 4 × side = Perimeter

Therefore side of square field = 5 meter.

We hope the RBSE Solutions for Class 5 Maths Chapter 14 Perimeter and Area Ex 14.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area Exercise 14.1, drop a comment below and we will get back to you at the earliest.

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