RBSE Solutions for Class 5 Maths Chapter 14 Perimeter and Area In Text Exercise is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area In Text Exercise.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Perimeter and Area |

Exercise |
In Text Exercise |

Number of Questions |
4 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area In Text Exercise

**Page No. 72**

Question 1.

Nirmal’s mathematics book has questions to find the perimeter of some shapes :

Can you find out the perimeter of above three shapes?

Solution.

We know that, only closed shapes have perimeters. Here(RBSESolutions.com)shape (b) and (c) are not closed, so we cannot find their perimeter. These type of shapes are known as open shapes.

**Page No. 72**

Question 1.

Some shapes are given below :

Find out the perimeter of these shapes.

Solution.

(a) We know that Perimeter(RBSESolutions.com)of regular shapes = number of sides × length of a side

∴ Perimeter = 3 × 10 = 30 cm.

(b) Perimeter = 4 × 12 = 48 cm.

(c) Perimeter = 5 × 7 = 35 cm.

**Page No. 73 **

**Try these**

Question 1.

Think, is rectangle a regular shape? If you want to find a formula for the perimeter of a rectangle. What will you do?

Solution.

No, rectangular is not a regular shape.

Because it’s all sides are not equal measurement.

We know that opposite sides of a rectangle are equal.

i.e. perimeter = 2 × length + 2 × breadth

Therefore formula(RBSESolutions.com)for the perimeter of rectangle

perimeter = 2 × (length + breadth)

This is the perimeter of rectangle.

Now perimeter of given rectangular shape = 2 × (15 + 5)

= 2 × 20 = 40 m.

**Page No. 75**

Question 1.

Some shapes are given below on grid paper. Find the area of these.

Solution.

(i) Shape is a picture of rectangle.

If each side of square is of 1 cm on grid paper then

length of rectangle is = 5 cm

and width = 2 cm.

Number of squares covered by rectangle ABCD = 10

Therefore, area of(RBSESolutions.com)rectangle ABCD = 10 square cm.

Here, there is a rule been between length, width and area of rectangle

Length × Width = Area

= 5 cm. × 2 cm. = 10 square cm.

(ii) Length of square = 4 cm.

Width of square = 4 cm.

Area of square = (side)^{2} = (4)^{2} = 16 square cm.

Number of squares covered by square = 16.

Therefore area of square = 16 square cm.

(iii) Length of rectangle = 7 cm.

Width of rectangle = 3 cm.

Area of rectangle = Length × Width = 7 × 3 = 21 square cm.

Number of(RBSESolutions.com)squares covered by rectangle ABCD = 21.

Therefore area = 21 square cm.

We hope the RBSE Solutions for Class 5 Maths Chapter 14 Perimeter and Area In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 14 Perimeter and Area In Text Exercise, drop a comment below and we will get back to you at the earliest.

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