RBSE Solutions for Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2.
Board | RBSE |
Textbook | SIERT, Rajasthan |
Class | Class 5 |
Subject | Maths |
Chapter | Chapter 17 |
Chapter Name | Mental Mathematics |
Exercise | Ex 17.2 |
Number of Questions | 11 |
Category | RBSE Solutions |
Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2
Question 1.
Choose the correct option in the following
Solution.
(i) (c)
(ii) (a)
(iii) (c)
(iv) (b)
(v) (c)
(vi) (b)
Question 2.
25 should be multiplied with which one digit(RBSESolutions.com)number to get a number having 0 at the tens and units place.
Solution.
If 25 is multiplied with 4 or 8 (one of them) then we get 0 at the tens and units place.
that is 25 x 4 = 100
and 25 x 8 = 200.
Question 3.
To obtain ten times of a given number with which number it should be multiplied.
Solution.
To obtain 10 times of a given(RBSESolutions.com)number it should be multiplied by 10.
Question 4.
Which number when multiplied by 5 gives products having 5 at the units place?
Solution.
Total 5 digits (1, 3, 5, 7, 9)
Question 5.
To find half of a number, by which number it should be divided.
Solution.
To find half of a number, the number should be divided by 2.
Question 6.
Find out a 2 – digits number whose(RBSESolutions.com)both digits are same and the number is divided by 7.
Solution.
Number is 77.
Question 7.
Find out a number, which divides all numbers.
Solution.
This number is 1 which divides all the numbers.
Question 8.
What operation we have to apply on 9 and 6, so that we have 54 as the number.
Solution.
To obtain 54, only multiplication performed between 9 and 6.
Question 9.
What operation we have to(RBSESolutions.com)apply on 6 and 3, so that we have 2 as answer.
Solution.
Only division operation is applied to obtain 2 from 6 and 3.
Question 10.
Which number when multiplied by any number gives the answer zero ?
Solution.
‘0’ is the only number which when multiplied by any number gives zero as answer.
Question 11.
Find out the smallest(RBSESolutions.com)number of 2 digits which is divisible by 2 and 3.
Solution.
Smallest 2 digit number is 12 which is divisible by 2 and 3 both.
We hope the RBSE Solutions for Class 5 Maths Chapter 17 Mental Mathematics Ex 17.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 17 Mental Mathematics Exercise 17.2, drop a comment below and we will get back to you at the earliest.
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