RBSE Solutions for Class 5 Maths Chapter 4 Vedic Mathematics Ex 4.2 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 4 Vedic Mathematics Exercise 4.2.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 5 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Vedic Mathematics |

Exercise |
Ex 4.2 |

Number of Questions |
1 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 5 Maths Chapter 4 Vedic Mathematics Ex 4.2

**Subtract the following –**

(Sutra – Ekadhikena purvena + param mitra digit)

Solution:

**Directions –**

(i) 2 can not be subtracted from 0 so add param mitra digit of 2 which is 8 in 0 and write the sum = 8 below in answer and put Ekadhik mark on 3, which is purvena digit of 2 in below(RBSESolutions.com)number i.e. \(\overset { . }{ 3 }\).

(ii) \(\overset { \bullet }{ 3 } \) = 4,4 can not be subtracted from 0. So add param mitra digit of 4 which is 6 in 0 and write the sum = 6 below in answer.

(iii) Put Ekadhik mark on 1, which is purvena digit of 3 i.e. \(\overset { . }{ 1 } =2\)

(iv) \(\overset { \bullet }{ 1 } =2\), subtract 2 from 2 and write (2 – 2) = 0 below in answer.

**Directions –**

(i) 9 can not be subtracted from 0 so add param mitra digit of 9 which is 1 in 0 and write the sum = 1 below in answer and put Ekadhik mark on 0. Which is purvena digit of 9 in below number.

(ii) \(\overset { \bullet }{ 0 } =1\), 1 can not be(RBSESolutions.com)subtracted from 0 so add param mitra digit of 1 which is 9 in 0 and write the sum = 9 below in answer.

(iii) Put Ekadhik mark on 3, which is purvena digit of O.

(iv) \(\overset { \bullet }{ 3 } =4\), subtract 4 from 5 and write (5 – 4) = 1 below in anwer.

**Directions –**

(i) 8 can not be subtracted from 5 so add param mitra digit of 8 which is 2 in 5 and write the sum = 7 below in answer and put Ekadhik mark on 0 which is purvena digit of 8.

(ii) \(\overset { \bullet }{ 0 } =1\),1 can(RBSESolutions.com)not be subtracted from 0 so add param mitra digit of 1 which is 9 in 0 and Write the sum = 9 below in answer.

(iii) Put Ekadhik mark on 6 which is purvena digit of 0.

(iii) \(\overset { \bullet }{ 6 } =7\), subtract 7 from 8 and write (8 – 7) – 1 below in answer.

**Directions –**

(i) 3 can not be subtracted from 0 so add param mitra digit of 3 which is 7 in 0 and write the sum = 7 below in answer and put Ekadhik mark on 7 which is purvena digit of 3 in below number.

(ii) \(\overset { \bullet }{ 7 } =8\), 8 can not be subtracted from 0, so add param mitra digit of 8 which is 2 in 0 and write the sum = 2 below in answer.

(iii) Put Ekadhik mark on 9 which is purvena digit of 7.

(iv) \(\overset { \bullet }{ 9 } =10\), 10 can(RBSESolutions.com)not be subtracted from 7. So add param mitra digit of 10 which is 0 in 7 and write the sum = 7 below in answer.

(v) Put Ekadhik mark on 0 which is purvena digit of 9.

(iv) \(\overset { \bullet }{ 0 } =1\), Subtract 1 from 1 and write (1 – 1) = 0 below in answer.

**Directions –**

(i) Subtract 1 from 5 and write below in answer. 8 can not be subtracted from 0 so add param mitra digit of 8 which is 2 in 0 and write the sum = 2 below in answer and put(RBSESolutions.com)Ekadhik mark on 2 which is purvena digit of 8 in below number.

(ii) \(\overset { \bullet }{ 2 } =3\), subtract 3 from 3 and write (3 – 3) = 0 below in answer.

(iii) Subtract 5 from 8 and write (8 – 5) = 3 below in answers

**Directions –**

(i) 6 can not be subtract from 0 so add param mitra digit of 6 which is 4 in 0 and write the sum = 4 below in answer and put Ekadhik mark on 3 which is purvena digit of 6 in below number.

(ii) \(\overset { \bullet }{ 3 } =4\), 4 can not be subtracted from 0 so add param mitra digit of 4 which is 6 in 0 and write the sum = 6 below in answer.

(iii) Put Ekadhik mark on 7 which is purvena digit of 3.

(iv) \(\overset { \bullet }{ 7 } =8\), 8 can not(RBSESolutions.com)be subtracted from 0 so add param mitra digit of 8 which is 2 in 0 and write the sum = 2 below in answer.

(v) Put Ekadhik mark on 2 which is purvena digit of 7.

(vi) \(\overset { \bullet }{ 2 } =3\), Subtract 3 from 4 and write (4 – 3) = 1 below in answer.

**Directions –**

(i) 4 can not be subtracted from 0. So add param mitra digit of 4 which is 6 in 0 and write the sum = 6 below in answer and put Ekadhik mark on 0 which is purvena digit of 4 in below number.

(ii) \(\overset { \bullet }{ 0 } =1\),1 can not be subtracted from 0 so add param mitra digit of 1 which is 9 in 0 and write the sum = 9 below in answer.

(iii) Put Ekadhik mark on 9 which is purvena digit of 0.

(iv) \(\overset { \bullet }{ 9 } =10\), 10 can not(RBSESolutions.com)be subtracted from 7 so add param mitra digit of 10 which is 0 in 7 and write the sum = 7 below in answer.

(v) Put Ekadhik mark on 4 which is purvena digit of 9.

(vi) \(\overset { \bullet }{ 4 } =5\), subtract 5 from 9 and write (9 – 5) = 4 below in answer.

**Directions –**

(i) 4 can not be subtracted from 0 so add param mitra digit of 4 which is 6 in 0 and write the sum = 6 below in answer and put Ekadhik mark on 5 which is purvena digit of 4.

(ii) \(\overset { \bullet }{ 5 } =6\), 7 can not be subtracted from 0 so add param mitra digit of 6 which is 4 in 0 and write the sum = 4 below in answer.

(iii) Put Ekadhik mark on 8 which is purvena digit of 5.

(iv) \(\overset { \bullet }{ 8 } =9\), 9 can not be(RBSESolutions.com)subtracted from 0 so add param mitra digit of 9 which is 1 in 0 and write the sum = 1 below in answer.

(v) Put Ekadhik mark on 0 which is purvena digit of 8.

(vi) \(\overset { \bullet }{ 0 } =1\), Subtract 1 from 1 and write (1 – 1) = 0 below in answer.

**Directions –**

(i) 6 can not be subtracted from 0 so add param mitra digit of 6 which is 4 in 0 and write the sum = 4 below in answer and put Ekadhik mark on 9 which is purvena digit of 6.

(ii) \(\overset { \bullet }{ 9 } =10\), 10 can not be subtracted from 0 so add param mitra digit of 10 which is ‘O’ zero in 0 and write the sum = 0 below in answer.

(iii) Put Ekadhik mark on 8 which is purvena digit of 9;

(iv) \(\overset { \bullet }{ 8 } =9\), 9 can not be(RBSESolutions.com)subtracted from 0 so add param mitra digit of 9 which is 1 in 0 and write the sum = 1 below in answer.

(v) Put Ekadhik mark on 3 which is purvena digit of 8.

(vi) \(\overset { \bullet }{ 3 } =4\), subtract 4 from 9 and write (9 – 4) = 5 below in answer.

We hope the RBSE Solutions for Class 5 Maths Chapter 4 Vedic Mathematics Ex 4.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 4 Vedic Mathematics Exercise 4.2, drop a comment below and we will get back to you at the earliest.

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