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RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions

March 13, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 5
Subject Maths
Chapter Chapter 7
Chapter Name Equivalent Fractions
Exercise Additional Questions
Number of Questions 25
Category RBSE Solutions

Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions

Multiple Choice Questions

Question 1.
Value of numerator in fraction \(\frac { 3 }{ 4 } \)
(a) 1
(b) 2
(c) 3
(d) 4

Question 2.
Value of denominator in fraction \(\frac { 7 }{ 8 } \)
(a) 7
(b) 8
(c) 15
(d) 56

Question 3.
Equivalent fraction of fraction \(\frac { 4 }{ 5 } \)
(a) \(\frac { 4 }{ 20 } \)
(b) \(\frac { 8 }{ 10 } \)
(c) \(\frac { 4 }{ 15 } \)
(d) \(\frac { 8 }{ 20 } \)

Question 4.
Simplest form of \(\frac { 24 }{ 30 } \) is-
(a) \(\frac { 4 }{ 5 } \)
(b) \(\frac { 3 }{ 5 } \)
(c) \(\frac { 5 }{ 4 } \)
(d) \(\frac { 5 }{ 3 } \)

RBSE Solutions

Question 5.
2 \(\frac { 1 }{ 2 } \) read as –
(a) Half
(b) One and half
(c) One and Quarter
(d) Two and half

Question 6.
Equivalent fraction(RBSESolutions.com)of \(\frac { 3 }{ 7 } \)
(a) \(\frac { 3 }{ 14 } \)
(b) \(\frac { 9 }{ 7 } \)
(c) \(\frac { 6 }{ 14 } \)
(d) \(\frac { 10 }{ 14 } \)

Question 7.
1 \(\frac { 1 }{ 4 } \) reads as –
(a) one quarter
(b) one and quarter
(c) one and half
(d) three by four

RBSE Solutions

Question 8.
Value of numerator and(RBSESolutions.com)denominator in fraction \(\frac { 11 }{ 13 } \) –
(a) Numerator 13 denominator 0
(b) Numerator 13 denominator 11
(c) Numerator 11 denominator 13
(d) Numerator 1 denominator 3

Answers
1. (c)
2. (b)
3. (b)
4. (a)
5. (d)
6. (c)
7. (b)
8. (c).

Fill in the blanks in the following Questions

1. Five by seven can be written as fractional form ………………
2. Fractions which are equal called ……………… fraction.
3. To obtain equivalent(RBSESolutions.com)fraction of a fraction, the numerator and denominator of the fraction are multiplied by ……………… number.
4. One of the equivalent fraction of \(\frac { 1 }{ 2 } \) is ………………
5. Number written in the form of ……………… and ……………… called fraction.

Answers
1. \(\frac { 5 }{ 7 } \)
2. Equivalent
3. Same
4. \(\frac { 2 }{ 4 } \)
5. Numerator, Denominator.

RBSE Solutions

Very Short Answer Type Questions

Question 1.
Which are called equivalent fractions ?
Solution.
Fractions which have the same value, are said to be equivalent fractions.

Question 2.
What can be done to obtain equivalent fraction of a fraction.
Solution.
Multiply the numerator(RBSESolutions.com)and denominator of the fraction by same number.

Question 3.
Write three equivalent fractions \(\frac { 3 }{ 5 } \)
Solution.
\(\frac { 6 }{ 10 } \) , \(\frac { 9 }{ 15 } \) , \(\frac { 12 }{ 20 } \)

RBSE Solutions

Question 4.
Write in simplest form.
Solution.
\(\frac { 4 }{ 5 } \)

Short Answer and Essay Type Questions

Question 1.
Write three equivalent fractions each of the following fraction
(1) \(\frac { 2 }{ 3 } \) = ………….. , ………….. , …………..
(2) \(\frac { 1 }{ 7 } \) = ………….. , ………….. , …………..
Solution.
RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions image 1

RBSE Solutions

Question 2.
Write four equivalent fractions of \(\frac { 9 }{ 10 } \).
Solution.
(i) \(\frac { 9 }{ 10 } \) × \(\frac { 2 }{ 2 } \) = \(\frac { 18 }{ 20 } \)
(ii) \(\frac { 9 }{ 10 } \) × \(\frac { 3 }{ 3 } \) = \(\frac { 27 }{ 30 } \)
(iii) \(\frac { 9 }{ 10 } \) × \(\frac { 4 }{ 4 } \) = \(\frac { 36 }{ 40 } \)
(iv) \(\frac { 9 }{ 10 } \) × \(\frac { 5 }{ 5 } \) = \(\frac { 45 }{ 50 } \)
Therefore, four equivalent fractions of
\(\frac { 9 }{ 10 } \) = \(\frac { 18 }{ 20 } \) , \(\frac { 27 }{ 30 } \) , \(\frac { 36 }{ 40 } \) and \(\frac { 45 }{ 50 } \)

Question 3.
Give some more examples where we(RBSESolutions.com)get \(\frac { 1 }{ 4 } \) chapati after dividing equally and write down below.
\(\frac { 1 }{ 4 } \) = \(\frac { 2 }{ 8 } \) = \(\frac { 3 }{ 12 } \) = ………….
Solution.
\(\frac { 4 }{ 16 } \) = \(\frac { 5 }{ 20 } \) = \(\frac { 6 }{ 24 } \) = \(\frac { 7 }{ 28 } \) = \(\frac { 8 }{ 32 } \) = …………. etc.

RBSE Solutions

Question 4.
Shade the region of each figure representing fraction given below :
RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions image 2
Solution.
RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions image 3

Question 5.
Seema bought 5 meter long ribbon from market, if she equally divides it between 4 friends, then what is the length of ribbon each friend will get ?
Solution.
Each friend will get = 5 ÷ 4
= \(\frac { 5 }{ 4 } \) = 1 \(\frac { 1 }{ 4 } \) meter
Therefore each friend(RBSESolutions.com)will get 1 \(\frac { 1 }{ 4 } \)
(One and one by four) meter ribbon.

RBSE Solutions

Question 6.
5 kg. Jaggary divided equally among two families then how much jaggary each family will get ?
Solution.
Each family will get = 5 ÷ 2 = \(\frac { 5 }{ 2 } \) = 2 \(\frac { 1 }{ 2 } \) kg.
Therefore, each family will get 2 \(\frac { 1 }{ 2 } \) (Two and half) kg. Jaggary

Question 7.
6 litre milk distributed between 12 children, then much litre milk each children will drink ?
Solution.
Each children will drink
= 6 ÷ 12 = \(\frac { 6 }{ 12 } \) = \(\frac { 1 }{ 2 } \) litre
Therefore, each children will drink \(\frac { 1 }{ 2 } \) (half) litre milk

Question 8.
Nazeeb needs 2 \(\frac { 1 }{ 2 } \) meter (two and half) cloth to make a payjama. How much(RBSESolutions.com)cloth he needs to make three such payjamas.
Solution.
∵ Cloth needed to make 1 payjama = 2 \(\frac { 1 }{ 2 } \) (Two and half) meter
∴ Cloth needed to make 3 payjamas
= 2 \(\frac { 1 }{ 2 } \) + 2 \(\frac { 1 }{ 2 } \) + 2 \(\frac { 1 }{ 2 } \)
= 2 + \(\frac { 1 }{ 2 } \) + 2 + \(\frac { 1 }{ 2 } \) + 2 + \(\frac { 1 }{ 2 } \)
= 6 + \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \)
= 7 \(\frac { 1 }{ 2 } \) meter
Therefore,7 \(\frac { 1 }{ 2 } \) (seven and half meter) cloth needed to make 3 payjamas.

RBSE Solutions

Question 9.
17kg. wheat divided equally among 4 families then how much kg wheat each family will get ?
Solution.
Each family will get = 17 ÷ 4 = \(\frac { 17 }{ 4 } \)
= 4 \(\frac { 1 }{ 4 } \) kg.
Therefore, each family will get 4 \(\frac { 1 }{ 4 } \) (four and one by four) kg wheat.

Question 10.
14 litre kerosene filled(RBSESolutions.com)equally in 4 stoves, then how much kerosene will be filled in each stove ?
Solution.
Kerosene filled in each stove = 14 ÷ 4 = \(\frac { 14 }{ 4 } \) litre
= \(\frac { 7 }{ 2 } \) = 3 \(\frac { 1 }{ 2 } \) litre
Therefore, 3 \(\frac { 1 }{ 2 } \) (Three and half) litre kerosene will be filled in each stove.

RBSE Solutions

Question 11.
Hemlata studied for 2 hours. She has read \(\frac { 3 }{ 4 } \) (Three by four) hour. Now, how much time is it to read ?
Solution.
Time is it to read Hemlata = \(\frac { 2 }{ 1 } \) – \(\frac { 3 }{ 4 } \)
\(\frac { 2\times 4 }{ 1\times 4 } -\frac { 3 }{ 4 } \)
\(\frac { 8 }{ 4 } \) – \(\frac { 3 }{ 4 } \) = \(\frac { 8-3 }{ 4 } \) = \(\frac { 5 }{ 4 } \) hours
= 1 \(\frac { 1 }{ 4 } \) hours
Therefore, 1 \(\frac { 1 }{ 4 } \) (one and one by four) hour is it to read Hemlata

RBSE Solutions

Question 12.
Meena took \(\frac { 1 }{ 2 } \) litre milk, her sister took 1 \(\frac { 1 }{ 2 } \) liters of milk and brought it ?
How much milk came in the house ? If milk is ₹ 20 per litre then how much rupees did Meena spend and how much her sister did spend ?
Solution.
RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions image 4

RBSE Solutions

We hope the RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Additional Questions, drop a comment below and we will get back to you at the earliest.

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