RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Ex 7.1

RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Ex 7.1 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Exercise 7.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 5
Subject	Maths
Chapter	Chapter 7
Chapter Name	Understanding the Fractions
Exercise	Ex 7.1
Number of Questions	9
Category	RBSE Solutions

Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Ex 7.1

Question 1.
Convert the given fraction in to equivalent fraction by multiplying numerator and denominator by 2.
(i) [latex s=1]\frac { 1 }{ 2 } [/latex]
(ii) [latex s=1]\frac { 2 }{ 3 } [/latex]
(iii) [latex s=1]\frac { 1 }{ 5 } [/latex]
(iv) [latex s=1]\frac { 2 }{ 5 } [/latex]
(v) [latex s=1]\frac { 2 }{ 7 } [/latex]
Solution.
(i) [latex s=1]\frac { 1 }{ 2 } =\frac { 1\times 2 }{ 2\times 2 } =\frac { 2 }{ 4 } [/latex]
(ii) [latex s=1]\frac { 2 }{ 3 } =\frac { 2\times 2 }{ 3\times 2 } =\frac { 4 }{ 6 } [/latex]
(iii) [latex s=1]\frac { 1 }{ 5 } =\frac { 1\times 2 }{ 5\times 2 } =\frac { 2 }{ 10 } [/latex]
(iv) [latex s=1]\frac { 2 }{ 5 } =\frac { 2\times 2 }{ 5\times 2 } =\frac { 4 }{ 10 } [/latex]
(v) [latex s=1]\frac { 2 }{ 7 } =\frac { 2\times 2 }{ 7\times 2 } =\frac { 4 }{ 14 } [/latex]

Question 2.
Convert the given fraction into equivalent fraction(RBSESolutions.com)by multiplying numerator and denominator by 3.
(i) [latex s=1]\frac { 1 }{ 4 } [/latex]
(ii) [latex s=1]\frac { 3 }{ 5 } [/latex]
(iii) [latex s=1]\frac { 2 }{ 5 } [/latex]
(iv) [latex s=1]\frac { 2 }{ 7 } [/latex]
(v) [latex s=1]\frac { 1 }{ 6 } [/latex]
Solution.
(i) [latex s=1]\frac { 1 }{ 4 } =\frac { 1\times 3 }{ 4\times 3 } =\frac { 3 }{ 12 } [/latex]
(ii) [latex s=1]\frac { 3 }{ 5 } =\frac { 3\times 3 }{ 5\times 3 } =\frac { 9 }{ 15 } [/latex]
(iii) [latex s=1]\frac { 2 }{ 5 } =\frac { 2\times 3 }{ 5\times 3 } =\frac { 6 }{ 15 } [/latex]
(iv) [latex s=1]\frac { 2 }{ 7 } =\frac { 2\times 3 }{ 7\times 3 } =\frac { 6 }{ 21 } [/latex]
(v) [latex s=1]\frac { 1 }{ 6 } =\frac { 1\times 3 }{ 6\times 3 } =\frac { 3 }{ 18 } [/latex]

Question 3.
Convert the given fraction into equivalent fraction(RBSESolutions.com)by multiplying numerator and denominator respectively 2, 3 and 4.
Example – [latex s=1]\frac { 1 }{ 5 } [/latex] = [latex s=1]\frac { 2 }{ 10 } [/latex] = [latex s=1]\frac { 3 }{ 15 } [/latex] = [latex s=1]\frac { 4 }{ 20 } [/latex]
(i) [latex s=1]\frac { 1 }{ 4 } [/latex]
(ii) [latex s=1]\frac { 2 }{ 3 } [/latex]
(iii) [latex s=1]\frac { 2 }{ 5 } [/latex]
(iv) [latex s=1]\frac { 3 }{ 4 } [/latex]
Solution.

Question 4.
Represent the given equivalent(RBSESolutions.com)fraction by filling colour in following diagrams.

Solution:

Question 5.
Fill in the blanks

Solution:

Question 6.
Give some more examples where(RBSESolutions.com)we get [latex s=1]\frac { 1 }{ 4 } [/latex] after dividing equally and write down below.
[latex s=1]\frac { 1 }{ 4 } [/latex] = [latex s=1]\frac { 2 }{ 8 } [/latex] = [latex s=1]\frac { 3 }{ 12 } [/latex] = ……………
Solution.
[latex s=1]\frac { 1 }{ 4 } =\frac { 1\times 4 }{ 4\times 4 } =\frac { 4 }{ 16 } [/latex]
[latex s=1]=\frac { 1\times 5 }{ 4\times 5 } =\frac { 5 }{ 20 } [/latex]
[latex s=1]=\frac { 1\times 6 }{ 4\times 6 } =\frac { 6 }{ 24 } [/latex]
∴ [latex s=1]\frac { 1 }{ 4 } [/latex] = [latex s=1]\frac { 2 }{ 8 } [/latex] = [latex s=1]\frac { 3 }{ 12 } [/latex] = [latex s=1]\frac { 4 }{ 16 } [/latex] = [latex s=1]\frac { 5 }{ 20 } [/latex] = [latex s=1]\frac { 6 }{ 24 } [/latex]

Question 7.
Write four equivalent fractions of [latex s=1]\frac { 1 }{ 5 } [/latex]
Solution.
[latex s=1]\frac { 1 }{ 5 } =\frac { 1\times 2 }{ 5\times 2 } =\frac { 2 }{ 10 } [/latex]
[latex s=1]=\frac { 1\times 3 }{ 5\times 3 } =\frac { 3 }{ 15 } [/latex]
[latex s=1]=\frac { 1\times 4 }{ 5\times 4 } =\frac { 4 }{ 20 } [/latex]
[latex s=1]=\frac { 1\times 5 }{ 5\times 5 } =\frac { 5 }{ 25 } [/latex]
∴[latex s=1]\frac { 1 }{ 5 } [/latex] = [latex s=1]\frac { 2 }{ 10 } [/latex] = [latex s=1]\frac { 3 }{ 15 } [/latex] = [latex s=1]\frac { 4 }{ 20 } [/latex] = [latex s=1]\frac { 5 }{ 25 } [/latex]

Question 8.
Ranu bought 6 meter long ribbon from market, if she equally divides it between 4 friends, then what is the length of ribbon each friend will get ?
Solution.
6 meter long ribbon = 4 meter + 2 meter On dividing among 4 friends each will get 1 meter ribbon out of 4 meter Now, out of 2 meter = 1 + 1
= [latex s=1]\frac { 1 }{ 2 } [/latex] + [latex s=1]\frac { 1 }{ 2 } [/latex] + [latex s=1]\frac { 1 }{ 2 } [/latex] + [latex s=1]\frac { 1 }{ 2 } [/latex]
That is four friends will get [latex s=1]\frac { 1 }{ 2 } [/latex] or half meter or one by 2 meter ribbon each.
Therefore, in 6 meter ribbon each will get 1 + [latex s=1]\frac { 1 }{ 2 } [/latex] = 1 [latex s=1]\frac { 1 }{ 2 } [/latex] meter long ribbon.

Question 9.
Saraswati needs 1 [latex s=1]\frac { 1 }{ 4 } [/latex] meter of cloth to make a shirt. How much cloth she needs to make two such shirts ?
Solution.
Cloth required for 1 shirt = 1 [latex s=1]\frac { 1 }{ 4 } [/latex] meter (one and quarter)
∴ Cloth required for 2 shirts = 1 [latex s=1]\frac { 1 }{ 4 } [/latex] + 1 [latex s=1]\frac { 1 }{ 4 } [/latex] meter
= 1 + [latex s=1]\frac { 1 }{ 4 } [/latex] + 1 + [latex s=1]\frac { 1 }{ 4 } [/latex] meter
= 1 + 1 + [latex s=1]\frac { 1 }{ 4 } [/latex] + [latex s=1]\frac { 1 }{ 4 } [/latex] meter
= 2 + [latex s=1]\frac { 1 }{ 2 } [/latex] meter
= 2 [latex s=1]\frac { 1 }{ 2 } [/latex] meter

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