RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Ex 7.1 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Exercise 7.1.
Board | RBSE |
Textbook | SIERT, Rajasthan |
Class | Class 5 |
Subject | Maths |
Chapter | Chapter 7 |
Chapter Name | Understanding the Fractions |
Exercise | Ex 7.1 |
Number of Questions | 9 |
Category | RBSE Solutions |
Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Ex 7.1
Question 1.
Convert the given fraction in to equivalent fraction by multiplying numerator and denominator by 2.
(i) \(\frac { 1 }{ 2 } \)
(ii) \(\frac { 2 }{ 3 } \)
(iii) \(\frac { 1 }{ 5 } \)
(iv) \(\frac { 2 }{ 5 } \)
(v) \(\frac { 2 }{ 7 } \)
Solution.
(i) \(\frac { 1 }{ 2 } =\frac { 1\times 2 }{ 2\times 2 } =\frac { 2 }{ 4 } \)
(ii) \(\frac { 2 }{ 3 } =\frac { 2\times 2 }{ 3\times 2 } =\frac { 4 }{ 6 } \)
(iii) \(\frac { 1 }{ 5 } =\frac { 1\times 2 }{ 5\times 2 } =\frac { 2 }{ 10 } \)
(iv) \(\frac { 2 }{ 5 } =\frac { 2\times 2 }{ 5\times 2 } =\frac { 4 }{ 10 } \)
(v) \(\frac { 2 }{ 7 } =\frac { 2\times 2 }{ 7\times 2 } =\frac { 4 }{ 14 } \)
Question 2.
Convert the given fraction into equivalent fraction(RBSESolutions.com)by multiplying numerator and denominator by 3.
(i) \(\frac { 1 }{ 4 } \)
(ii) \(\frac { 3 }{ 5 } \)
(iii) \(\frac { 2 }{ 5 } \)
(iv) \(\frac { 2 }{ 7 } \)
(v) \(\frac { 1 }{ 6 } \)
Solution.
(i) \(\frac { 1 }{ 4 } =\frac { 1\times 3 }{ 4\times 3 } =\frac { 3 }{ 12 } \)
(ii) \(\frac { 3 }{ 5 } =\frac { 3\times 3 }{ 5\times 3 } =\frac { 9 }{ 15 } \)
(iii) \(\frac { 2 }{ 5 } =\frac { 2\times 3 }{ 5\times 3 } =\frac { 6 }{ 15 } \)
(iv) \(\frac { 2 }{ 7 } =\frac { 2\times 3 }{ 7\times 3 } =\frac { 6 }{ 21 } \)
(v) \(\frac { 1 }{ 6 } =\frac { 1\times 3 }{ 6\times 3 } =\frac { 3 }{ 18 } \)
Question 3.
Convert the given fraction into equivalent fraction(RBSESolutions.com)by multiplying numerator and denominator respectively 2, 3 and 4.
Example – \(\frac { 1 }{ 5 } \) = \(\frac { 2 }{ 10 } \) = \(\frac { 3 }{ 15 } \) = \(\frac { 4 }{ 20 } \)
(i) \(\frac { 1 }{ 4 } \)
(ii) \(\frac { 2 }{ 3 } \)
(iii) \(\frac { 2 }{ 5 } \)
(iv) \(\frac { 3 }{ 4 } \)
Solution.
Question 4.
Represent the given equivalent(RBSESolutions.com)fraction by filling colour in following diagrams.
Solution:
Question 5.
Fill in the blanks
Solution:
Question 6.
Give some more examples where(RBSESolutions.com)we get \(\frac { 1 }{ 4 } \) after dividing equally and write down below.
\(\frac { 1 }{ 4 } \) = \(\frac { 2 }{ 8 } \) = \(\frac { 3 }{ 12 } \) = ……………
Solution.
\(\frac { 1 }{ 4 } =\frac { 1\times 4 }{ 4\times 4 } =\frac { 4 }{ 16 } \)
\(=\frac { 1\times 5 }{ 4\times 5 } =\frac { 5 }{ 20 } \)
\(=\frac { 1\times 6 }{ 4\times 6 } =\frac { 6 }{ 24 } \)
∴ \(\frac { 1 }{ 4 } \) = \(\frac { 2 }{ 8 } \) = \(\frac { 3 }{ 12 } \) = \(\frac { 4 }{ 16 } \) = \(\frac { 5 }{ 20 } \) = \(\frac { 6 }{ 24 } \)
Question 7.
Write four equivalent fractions of \(\frac { 1 }{ 5 } \)
Solution.
\(\frac { 1 }{ 5 } =\frac { 1\times 2 }{ 5\times 2 } =\frac { 2 }{ 10 } \)
\(=\frac { 1\times 3 }{ 5\times 3 } =\frac { 3 }{ 15 } \)
\(=\frac { 1\times 4 }{ 5\times 4 } =\frac { 4 }{ 20 } \)
\(=\frac { 1\times 5 }{ 5\times 5 } =\frac { 5 }{ 25 } \)
∴\(\frac { 1 }{ 5 } \) = \(\frac { 2 }{ 10 } \) = \(\frac { 3 }{ 15 } \) = \(\frac { 4 }{ 20 } \) = \(\frac { 5 }{ 25 } \)
Question 8.
Ranu bought 6 meter long ribbon from market, if she equally divides it between 4 friends, then what is the length of ribbon each friend will get ?
Solution.
6 meter long ribbon = 4 meter + 2 meter On dividing among 4 friends each will get 1 meter ribbon out of 4 meter Now, out of 2 meter = 1 + 1
= \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \) + \(\frac { 1 }{ 2 } \)
That is four friends will get \(\frac { 1 }{ 2 } \) or half meter or one by 2 meter ribbon each.
Therefore, in 6 meter ribbon each will get 1 + \(\frac { 1 }{ 2 } \) = 1 \(\frac { 1 }{ 2 } \) meter long ribbon.
Question 9.
Saraswati needs 1 \(\frac { 1 }{ 4 } \) meter of cloth to make a shirt. How much cloth she needs to make two such shirts ?
Solution.
Cloth required for 1 shirt = 1 \(\frac { 1 }{ 4 } \) meter (one and quarter)
∴ Cloth required for 2 shirts = 1 \(\frac { 1 }{ 4 } \) + 1 \(\frac { 1 }{ 4 } \) meter
= 1 + \(\frac { 1 }{ 4 } \) + 1 + \(\frac { 1 }{ 4 } \) meter
= 1 + 1 + \(\frac { 1 }{ 4 } \) + \(\frac { 1 }{ 4 } \) meter
= 2 + \(\frac { 1 }{ 2 } \) meter
= 2 \(\frac { 1 }{ 2 } \) meter
We hope the RBSE Solutions for Class 5 Maths Chapter 7 Equivalent Fractions Ex 7.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Chapter 7 Equivalent Fractions Exercise 7.1, drop a comment below and we will get back to you at the earliest.
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