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RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1

February 16, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 is part of RBSE Solutions for Class 5 Maths. Here we have given Rajasthan Board RBSE Class 5 Maths Solutions Chapter 7 तुल्य भिन्न Exercise 7.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 5
Subject Maths
Chapter Chapter 7
Chapter Name तुल्य भिन्न
Exercise Ex 7.1
Number of Questions 9
Category RBSE Solutions

Rajasthan Board RBSE Class 5 Maths Solutions Chapter 7 तुल्य भिन्न Ex 7.1

Question 1.
दी गई भिन्नों के अंश व हर को 2 से गुणा कर तुल्य भिन्न बनाइए –
(i) \(\frac { 1 }{ 2 }\)
(ii) \(\frac { 2 }{ 3 }\)
(iii) \(\frac { 1 }{ 5 }\)
(iv) \(\frac { 2 }{ 5 }\)
(v) \(\frac { 2 }{ 7 }\)
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 1

RBSE Solutions

Question 2.
दी गई भिन्नों में अंश व हर को 3 से गुणा कर तुल्य भिन्न बनाइए –
(i) \(\frac { 1 }{ 4 }\)
(ii) \(\frac { 3 }{ 5 }\)
(iii) \(\frac { 2 }{ 5 }\)
(iv) \(\frac { 2 }{ 7 }\)
(v) \(\frac { 1 }{ 6 }\)
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 2

RBSE Solutions

Question 3.
दी गई भिन्नों के अंश वे हर को क्रमशः 2, 3 और 4 से गुणा कर तुल्य भिन्न प्राप्त कीजिए –
उदाहरण – \(\frac { 1 }{ 5 }\) = \(\frac { 2 }{ 10 }\) = \(\frac { 3 }{ 15 }\) = \(\frac { 4 }{ 20 }\)
(i) \(\frac { 1 }{ 4 }\)
(ii) \(\frac { 2 }{ 3 }\)
(iii) \(\frac { 2 }{ 5 }\)
(iv) \(\frac { 3 }{ 4 }\)
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 3
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 4

RBSE Solutions
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 5

Question 4.
दी गई तुल्य भिन्नों को चित्रों में रंग भर कर दर्शाएँ –
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 6
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 7
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 8

RBSE Solutions

Question 5.
रिक्त स्थानों को भरिए –
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 9
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 10

RBSE Solutions

Question 6.
ऐसे और उदाहरण बताओ जिसमें(RBSESolutions.com)बराबर बाँटने पर \(\frac { 1 }{ 4 }\) भाग मिलती हो और नीचे लिखिए।
\(\frac { 1 }{ 4 }\) = \(\frac { 2 }{ 8 }\) = \(\frac { 3 }{ 12 }\) = ………
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 11

RBSE Solutions

Question 7.
\(\frac { 1 }{ 5 }\) के बराबर चार तुल्य भिन्न लिखिए।
हल:
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 12

RBSE Solutions

Question 8.
रानू ने बाजार से 6 मीटर लंबी रिबन खरीदी। इसे वह 4 सहेलियों में बराबर बाँटती है तो बताओ हर एक को कितने मीटर लंबी रिबन मिलेगी?
हल
6 मीटर लम्बी रिबन = 4 मीटर + 2 मीटर 4 सहेलियों(RBSESolutions.com)cमें बाँटने पर प्रत्येक सहेली को 4 मीटर में से 1-1 मीटर रिबन मिल जायेगी।
अब 2 मीटर में से 1 + 1 = \(\frac { 1 }{ 2 }\) + \(\frac { 1 }{ 2 }\) + \(\frac { 1 }{ 2 }\) + \(\frac { 1 }{ 2 }\)
अर्थात् चारों सहेलियों को या आधा मीटर या एक बटे दो मीटर और रिबन मिलेगी। इस प्रकार 6 मीटर रिबन में से प्रत्येक सहेली को 1 + \(\frac { 1 }{ 2 }\) = 1\(\frac { 1 }{ 2 }\) मीटर लम्बी रिबन मिलेगी।

Question 9.
सरस्वती को एक कमीज बनाने क(RBSESolutions.com) लिए 1\(\frac { 1 }{ 4 }\) (सवा) मीटर कपड़ा चाहिए तो ऐसे ही 2 कमीज के लिए कुल कितना मीटर कपड़ा चाहिए?
हुल
1 कमीज के लिए आवश्यक कपड़ा = 1\(\frac { 1 }{ 4 }\) (सवा) मीटर
∴ 2 कमीज के लिए आवश्यक कपड़ा
RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 image 13

RBSE Solutions

We hope the RBSE Solutions for Class 5 Maths Chapter 7 तुल्य भिन्न Ex 7.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 5 Maths Solutions Chapter 7 तुल्य भिन्न Exercise 7.1, drop a comment below and we will get back to you at the earliest.

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