RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3

RBSE Solutions for Class 6 Maths Chapter 1 Know the Numbers Ex 1.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Exercise 1.3.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 1
Chapter Name	Know the Numbers
Exercise	Ex 1.3
Number of Questions	5
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 1 Know the Numbers Ex 1.3

Question 1.
Replace each number to the (RBSESolutions.com) nearest hundred of the following and calculate the answer again in the nearest hundred.
(i) 247 + 691
(ii) 4316 + 1567
(iii) 7122 – 3565
(iv) 4543 – 2036
Solution.
(i) 247 + 691
Tens place digit in 247 = 4 < 5 Rounding off 247 to nearest hundred = 200
Tens place digit in number 691 = 9 > 5
Digit of hundred =6 + 1 = 7
Roudning off 691 to nearest = 700
Thus, 200 + 700 = 900

(ii) 4316 + 1567
Tens place digit in 4316 = 1 < 5 Rounding off 4316 to (RBSESolutions.com) nearest hundred = 4300
Tens place digit in 1567 = 6 > 5
Digit of hundred =5 + 1=6
Rounding off 1567 to nearest hundred = 1600
Thus, 4300 + 1600 = 5900

(iii) 7122 – 3565
Tens digit in 7122 = 2 < 5 Rounding off 7122 to nearest hundred = 7100
Tens place digit in 3565 = 6 > 5
Digit of hundred =5 + 1 = 6 Rounding off 3565 to nearest hundred = 3600
Thus, 7100 – 3600 = 3500

(iv) 4543 – 2036
Tens place digit in 4543 = 4 < 5 Rounding off 4543 to nearest (RBSESolutions.com) hundred = 4500
Rounding off 2036 to nearest hundred = 3 < 5
Rounding off 2036 to nearest hundred = 2000
Thus, 4500 – 2000 = 2500

Question 2.
Multiply the nearest tens numbers of the following :
(i) 34 × 57
(ii) 294 × 72
(iii) 869 × 675
Solution.
(i) 34 × 57
Rounding off 34 to (RBSESolutions.com) nearest tens = 30
Rounding off 57 to nearest tens = 60
Thus, 30 × 60 = 1,800

(ii) 294 x 72
Rounding off 294 to nearest tens = 290
Rounding off 72 to nearest tens = 70
Thus, 290 × 70 = 20,300

(iii) 869 × 675
Rouding off 869 to nearest tens = 870
Rounding off 675 to nearest tens = 680
Thus, 870 × 680 = 5,91,600

Question 3.
In the school library, there are 2541 books of stories, 1017 subject books (RBSESolutions.com) and other books are 857. Find out the approximate number of books in the school. (Rounding the number to 100).
Solution.
Number of story books = 2541
Round off 2541 = 2500
Number of subject books = 1017
Round off 1017 = 1000
Other books = 857
Round off 857 to nearest hundred = 900
Thus, total books = 2500 + 1000 + 900 = 4400

Question 4.
8596 cows and 7015 buffaloes are there (RBSESolutions.com) in a village. Find out which cattle is more than the other and how much ? (Rounding the number to 100).
Solution.
Number of cows = 8596
Round off 8596 to nearest hundred = 8600
Number of buffaloes = 7015
Round off 7015 to nearest hundred = 7000
Difference = 8600 – 7000 = 1600
Thus, cows are more than others, approximately 1600.

Question 5.
A car runs 15 kilometer with 1 litre petrol. How (RBSESolutions.com) much petrol does it need to go 100 kms ? (Find out the value rounding the number to 10).
Solution.
Petrol need to ran 15 litre = 1 litre
Petrol need to run 1 km = [latex s=1]\frac { 1 }{ 15 } [/latex] litre
Petrol need to run 100 km
[latex]=\frac { 1\times 100 }{ 15 } =6.67=7[/latex] litre (approx)

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