RBSE Solutions for Class 6 Maths Chapter 12 Algebra Ex 12.3 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 12 Algebra Exercise 12.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 12 |

Chapter Name |
Algebra |

Exercise |
Ex 12.3 |

Number of Questions |
4 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 12 Algebra Ex 12.3

Question 1.

State which of the following are equations (with a variable). Identify (RBSESolutions.com) the variable from the equations with a variable.

(i) 5x = 0

(ii) t – 7 > 5

(iii) 4 ÷ 2 = 2

(iv) 2x – 1 < 5

(v) 7 = 14 × 2 + q

(vi) 15000 = 2t + 3500

Solution:

Question 2.

For the equation, 10y = 50, pick out the solution (RBSESolutions.com) which satisfies the equation from the values y = 10, y = 8 and y = 5.

Solution:

Given equation 10y = 50

Putting y = 10,

= 10 × 10 = 50

⇒ 100 = 50

Equation does not satisfy.

Putting y = 8,

= 10 × 8 = 50

⇒ 80 = 50

Equation satisfies.

Putting y = 5,

= 10 × 5 = 50

⇒ 50 = 50

Equation satisfies.

∴ Given equation satisfies for y = 5

Question 3.

A possible solution is given with each of the equations given below. Put (RBSESolutions.com) the value of the variable in the equations and show that the value satisfy/do not satisfy the equation.

(i) 3x – 7 = 5, x = 5

(ii) 3p + 2 = 8, p = 2

Solution:

(i) 3x – 7 = 5

Putting x = 5, 3 × 5 – 7 = 5

⇒ 15 – 7 = 5

⇒ 8 = 5

Thus, given equations (RBSESolutions.com) does not satisfy for x = 5.

(ii) 3p + 2 = 8

Putting p = 2, 3 × 2 + 2 = 8

⇒ 6 + 2 = 8

⇒ 8 = 8

Thus, given equation satisfy for p = 2.

Question 4.

Complete the table and by inspection of the (RBSESolutions.com) table find the solution to the equation :

(i) 3x = 15

(ii) [latex s]\frac { p }{ 3 }=4[/latex]

(iii) x – 3 = 5

Solution:

(i) Table

3x = 15 ⇒ x = [latex s=1]\frac { 15 }{ 3 } [/latex] = 5

Thus: x = 5

(ii)Table

[latex s=1]\frac { p }{ 3 }=4[/latex]

⇒ p = 4 × 3 = 12

Thus: p = 12

(iii) Table

x – 3 = 5 ⇒ x = 3 + 5 = 8

Thus: x = 8

We hope the RBSE Solutions for Class 6 Maths Chapter 12 Algebra Ex 12.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 12 Algebra Exercise 12.3, drop a comment below and we will get back to you at the earliest.

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