RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise

RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 13
Chapter Name	Ratio and Proportion
Exercise	In text Exercise
Number of Questions	9
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise

(Page No. 177)
Question 1.
Cost of a pen is Rs. 10 and cost of a pencil is Rs. 2. What will (RBSESolutions.com) be the ratio of a pen’s cost to a pencil’s cost?
Solution:
Cost of a pen = Rs. 10
Cost of a pencil = Rs. 2
The ratio of pen’s cost to pencil’s cost
= 10 : 2 = \(\frac { 10 }{ 2 } \) = \(\frac { 5 }{ 1 } \) = 5 : 1
∴ The ratio of pen’s and pencil’s cost = 5 : 1

Question 2.
Ravi walks 6 km in an hour while Suraj walks 4 km in an hour. What (RBSESolutions.com) is the ratio of the distance covered by Ravi to the distance covered by Suraj?
Solution:
Ravi walks every hour = 6 km
Suraj walks every hour = 4 km
According to question, required ratio
= \(\frac { 6 }{ 4 } \) = 3 : 2
∴ The ratio of the distance covered by Ravi and Suraj = 3 : 2

(Page No. 178)
Question 1.
The numbers of vehicles passing on the road (RBSESolutions.com) between 9 a.m to 10 a.m are recorded in the table below.

1. What is the ratio of number of two wheelers to the number of cars?
2. What is the ratio of number of total vehicles to the number of trucks?
3. Weight of a car is 3300 pounds and weight of a bicycle is 22 pounds. What is the ratio of the weight of bicycle to the weight of car ?
Solution:
Ratio of number of two wheelers to the number of cars :
= 24 : 60 = \(\frac { 24 }{ 60 } \) = \(\frac { 2 }{ 5 } \) = 2 : 5

2. Ratio of number of total (RBSESolutions.com) vehicles to the number of trucks
(24 + 60 + 40) : 4 = \(\frac { (24 + 60 + 40) }{ 40 } \)
= \(\frac { 124 }{ 40 } \) = \(\frac { 31 }{ 10 } \) = 31 : 10

3. Weight of car= 3300
pound weight of bicycle = 22 pound
According to question, required ratio
= 22 : 3300 = \(\frac { 22 }{ 3300 } \)
= \(\frac { 1 }{ 150 } \) = 1 : 150

(Page No. 179)
Question 1.
Find the ratio of number of doors and (RBSESolutions.com) the number of windows in year classroom.
Solution:
Number of doors = 2
Number of windows = 3
According to question, the ratio of number of doors and the number of windows = 2 : 3

Question 2.
Draw any rectangle and (RBSESolutions.com) find the ratio of its length of its breadth.
Solution:
Let, length of rectangle = x
and, breadth of rectangle = y

According to question:
required ratio
= \(\frac { x }{ y } \) = \(\frac { x = 15 }{ y = 10 } \) (Let)
= \(\frac { 15 }{ 10 } \) = \(\frac { 3 }{ 2 } \)= 3 : 2

(Page No. 181)
Question 1.
The length and diameter of a straw (RBSESolutions.com) are 12 cm and 6 mm respectively. What is the ratio of its diameter to its length?
Solution:
Length of a straw = 12 cm = 120 mm
its diameter = 6 mm
According to question, required ratio,
= 6 : 120 = \(\frac { 6 }{ 120 } \)
= \(\frac { 1 }{ 20 } \) = 1 : 20

Question 2.
Anand takes 25 minutes to reach school from his (RBSESolutions.com) house and Anshul takes one hour to reach school from his house. Find the ratio of the time taken by Anand to the time taken by Anshul.
Solution:
Time taken by Anand = 25 minute
Time taken by Anshul = 1 hour = 60 minute
According to question, required ratio
= \(\frac { 25 }{ 60 } \) = \(\frac { 5 }{ 12 } \) = 5 : 12

(Page No. 183)
Question 1.
Determine if the following (RBSESolutions.com) are in proportion
(i) 3 : 5 and 1 : 15
(ii) 4 : 12 and 9 : 27
(iii) Rs. 10, is to Rs. 15 and 4 is to 6
Solution:
(i) 3 : 5 = 1 : 15 = 3 × 15 = 5 × 1
45 ≠ 5
∴ 3 : 5 and 1 : 15 are not in proportion

(ii) 4 : 12 and 9 : 27
⇒ 4 : 12 = 9 : 27
⇒ 4 × 27 = 12 × 9
⇒ 108 = 108
∴ 4 : 12 and 9 : 27 are (RBSESolutions.com) in proportion

(iii) 10 : 15 = 4 : 6
⇒ 10 × 6 = 15 × 4
⇒ 60 = 60
∴ Given numbers are in proportion.

(Page No. 185)
Question 1.
Read the table and fill in the boxes.

Solution:
⇒ 50 : 70 = 25 : …
⇒ 50 × … = 70 × 25
⇒ … = 70 × \(\frac { 25 }{ 50 } \) = 7 × \(\frac { 25 }{ 5 } \) = 35
⇒ … = 35
for 5 books :
25 × 5 : 35 × 5 = 125 : 175
Thus,

(Page No. 177)
Question 1.
Read the table carefully (RBSESolutions.com) and fill in the blanks.

solution:

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