RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 13 |

Chapter Name |
Ratio and Proportion |

Exercise |
In text Exercise |

Number of Questions |
9 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise

**(Page No. 177)
**Question 1.

Cost of a pen is Rs. 10 and cost of a pencil is Rs. 2. What will (RBSESolutions.com) be the ratio of a pen’s cost to a pencil’s cost?

Solution:

Cost of a pen = Rs. 10

Cost of a pencil = Rs. 2

The ratio of pen’s cost to pencil’s cost

= 10 : 2 = \(\frac { 10 }{ 2 } \) = \(\frac { 5 }{ 1 } \) = 5 : 1

∴ The ratio of pen’s and pencil’s cost = 5 : 1

Question 2.

Ravi walks 6 km in an hour while Suraj walks 4 km in an hour. What (RBSESolutions.com) is the ratio of the distance covered by Ravi to the distance covered by Suraj?

Solution:

Ravi walks every hour = 6 km

Suraj walks every hour = 4 km

According to question, required ratio

= \(\frac { 6 }{ 4 } \) = 3 : 2

∴ The ratio of the distance covered by Ravi and Suraj = 3 : 2

**(Page No. 178)**

Question 1.

The numbers of vehicles passing on the road (RBSESolutions.com) between 9 a.m to 10 a.m are recorded in the table below.

1. What is the ratio of number of two wheelers to the number of cars?

2. What is the ratio of number of total vehicles to the number of trucks?

3. Weight of a car is 3300 pounds and weight of a bicycle is 22 pounds. What is the ratio of the weight of bicycle to the weight of car ?

Solution:

Ratio of number of two wheelers to the number of cars :

= 24 : 60 = \(\frac { 24 }{ 60 } \) = \(\frac { 2 }{ 5 } \) = 2 : 5

2. Ratio of number of total (RBSESolutions.com) vehicles to the number of trucks

(24 + 60 + 40) : 4 = \(\frac { (24 + 60 + 40) }{ 40 } \)

= \(\frac { 124 }{ 40 } \) = \(\frac { 31 }{ 10 } \) = 31 : 10

3. Weight of car= 3300

pound weight of bicycle = 22 pound

According to question, required ratio

= 22 : 3300 = \(\frac { 22 }{ 3300 } \)

= \(\frac { 1 }{ 150 } \) = 1 : 150

**(Page No. 179)**

Question 1.

Find the ratio of number of doors and (RBSESolutions.com) the number of windows in year classroom.

Solution:

Number of doors = 2

Number of windows = 3

According to question, the ratio of number of doors and the number of windows = 2 : 3

Question 2.

Draw any rectangle and (RBSESolutions.com) find the ratio of its length of its breadth.

Solution:

Let, length of rectangle = x

and, breadth of rectangle = y

According to question:

required ratio

= \(\frac { x }{ y } \) = \(\frac { x = 15 }{ y = 10 } \) (Let)

= \(\frac { 15 }{ 10 } \) = \(\frac { 3 }{ 2 } \)= 3 : 2

**(Page No. 181)**

Question 1.

The length and diameter of a straw (RBSESolutions.com) are 12 cm and 6 mm respectively. What is the ratio of its diameter to its length?

Solution:

Length of a straw = 12 cm = 120 mm

its diameter = 6 mm

According to question, required ratio,

= 6 : 120 = \(\frac { 6 }{ 120 } \)

= \(\frac { 1 }{ 20 } \) = 1 : 20

Question 2.

Anand takes 25 minutes to reach school from his (RBSESolutions.com) house and Anshul takes one hour to reach school from his house. Find the ratio of the time taken by Anand to the time taken by Anshul.

Solution:

Time taken by Anand = 25 minute

Time taken by Anshul = 1 hour = 60 minute

According to question, required ratio

= \(\frac { 25 }{ 60 } \) = \(\frac { 5 }{ 12 } \) = 5 : 12

**(Page No. 183)**

Question 1.

Determine if the following (RBSESolutions.com) are in proportion

(i) 3 : 5 and 1 : 15

(ii) 4 : 12 and 9 : 27

(iii) Rs. 10, is to Rs. 15 and 4 is to 6

Solution:

(i) 3 : 5 = 1 : 15 = 3 × 15 = 5 × 1

45 ≠ 5

∴ 3 : 5 and 1 : 15 are not in proportion

(ii) 4 : 12 and 9 : 27

⇒ 4 : 12 = 9 : 27

⇒ 4 × 27 = 12 × 9

⇒ 108 = 108

∴ 4 : 12 and 9 : 27 are (RBSESolutions.com) in proportion

(iii) 10 : 15 = 4 : 6

⇒ 10 × 6 = 15 × 4

⇒ 60 = 60

∴ Given numbers are in proportion.

**(Page No. 185)**

Question 1.

Read the table and fill in the boxes.

Solution:

⇒ 50 : 70 = 25 : …

⇒ 50 × … = 70 × 25

⇒ … = 70 × \(\frac { 25 }{ 50 } \) = 7 × \(\frac { 25 }{ 5 } \) = 35

⇒ … = 35

for 5 books :

25 × 5 : 35 × 5 = 125 : 175

Thus,

**(Page No. 177)**

Question 1.

Read the table carefully (RBSESolutions.com) and fill in the blanks.

solution:

We hope the RBSE Solutions for Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 13 Ratio and Proportion In text Exercise, drop a comment below and we will get back to you at the earliest.

## Leave a Reply