RBSE Solutions for Class 6 Maths Chapter 2 Relation Among Numbers Additional Questions

RBSE Solutions for Class 6 Maths Chapter 2 Relation Among Numbers Additional Questions is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 2 Relation Among Numbers Additional Questions.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 2
Chapter Name	Relation Among Numbers
Exercise	Additional Questions
Number of Questions	17
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 2 Relation Among Numbers Additional Questions

Multiple Choice Questions

Question 1.
Factors of number 24 are :
(i) 1, 2, 3
(ii) 4, 6
(iii) 12, 24
(iv) All above

Question 2.
Number of prime (RBSESolutions.com) numbers between 1 to 100 are :
(i) 24
(ii) 25
(iii) 26
(iv) 27

Question 3.
Number which is not divisible by 2 :
(i) 267
(ii) 468
(iii) 192
(iv) 374

Question 4.
First three multiples of 15 are :
(i) 15, 30, 60
(ii) 15, 45, 60
(iii) 15, 30, 45
(iv) 30, 45, 60

Question 5.
H.C.F. of 14 and 24 is :
(i) 7
(ii) 3
(iii) 2
(iv) 6.

Question 6.
L.C.M. of 40, 15, 20 is :
(i) 120
(ii) 100
(iii) 140
(iv) 160

The Postive Factors of 50 are therefore all the numbers we used to divide (divisors) above to get an even number.

Question 7.
Common (RBSESolutions.com) factor of 18, 27 is :
(i) 2
(ii) 4
(iii) 6
(iv) 9

Question 8.
Prime number in the following is :
(i) 6
(ii) 7
(iii) 9
(iv) 10

Ans.
1. (iv)
2. (ii)
3. (i)
4. (iii)
5. (iii)
6. (i)
7. (iv)
8. (ii)

Prime Factorization of 38 with a Factor Tree ·

Fill in the blanks

(i) Reverse process of factors is called ………………..
(ii) The numbers having more than two factors are called ………………..
(iii) ……………….. is even prime number.
(iv) The numbers completely divisible by 2 are called.
(v) Multiples of same multiple numbers are called ………………..
(vi) Smallest odd (RBSESolutions.com) prime number is ………………..

Answer.
(i) expansion
(ii) composite
(iii) 2
(iv) even
(v) common factor
(vi) 3

Very Short Answer Type Questions

Question 1.
Write all factors of 38.
Solution.
Factors of 38
38 = 1 × 38
38 = 2 × 19
38 = 19 × 2
∴ Thus, all factors of 38 are 1,2,19 and 38.

Question 2.
Write first seven (RBSESolutions.com) multiples of 4.
Solution.
First seven multiples of 4 are :
4 × 1 = 4
4 × 2 = 8
4 × 3 = 12
4 × 4 = 16
4 × 5 = 20
4 × 6 = 24
4 × 7 = 28
Thus, first seven multiples of 4 are 4,8,12,16, 20, 24 and 28.

Question 3.
Write all prime numbers between 1 and 50.
Solution.
Prime numbers (RBSESolutions.com) between 1 and 50 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47.

Question 4.
Find common factors of 15, 25, 35 and 45.
Solution.
Finding common factor of 15, 25,35 and 45,

∴ Common factors of 15, 25, 35 and 45 = 1, 5

Short/Long Answer Type Questions

Question 1.
Test divisibility (RBSESolutions.com) of 585 by 3, without division.
Solution.
Test divisibility by 3
Sum of digits in number =5 + 8 + 5 = 18 ⇒ 1 + 8 = 9
Which is divisible by 3.
Thus, 585 will be divisible by 3.

Question 2.
Test divisibility of 7640 by 8, without division.
Solution.
Test divisibility by 8
In number. 7640 number formed by digits of hundred tens and ones place = 640
Dividing 640 by 8
640 ÷ 8 = 80
Which is divisible by 8.
Thus, 7640 will be divisible by 8.

Question 3.
Three containers contains 26 l, 65 litre 117 l milk respectively. Find maximum (RBSESolutions.com) measurement of container milk of all three containers.
Solution.
Milk contains in 1st container= 26 l
Milk contains in 2nd container =65 l
Milk contains in 3rd container = 117 l
Factors of 26 = 2 × (13)
Factors of 65 = 5 × (13)
Factors of 117 = 3 × 3 × (13)
∴ H.C.M. of 26, 65 and 117 = 13
Thus, required maximum measurement of container will be 13 l.

Question 4.
Find the smallest number (RBSESolutions.com) which is completely divisible by 18, 36, 50.
Solution.
Finding L.C.M. 18, 36 and 50

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