RBSE Solutions for Class 6 Maths Chapter 5 Fractions Ex 5.1

RBSE Solutions for Class 6 Maths Chapter 5 Fractions Ex 5.1 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 5 Fractions Exercise 5.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 5
Chapter Name	Fractions
Exercise	Ex 5.1
Number of Questions	8
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 5 Fractions Ex 5.1

Question 1.
Write the fractions to (RBSESolutions.com) represent shaded parts of the following.

Solution.
Following is the fractions of shaded parts –
(i) \(\frac { 2 }{ 4 } \) = \(\frac { 1 }{ 2 } \)
(ii) \(\frac { 4 }{ 6 } \) = \(\frac { 2 }{ 3 } \)
(iii) \(\frac { 6 }{ 10 } \) = \(\frac { 3 }{ 5 } \)

Question 2.
Show the following (RBSESolutions.com) fractions by diagram.
(i) \(\frac { 3 }{ 5 } \)
(ii) \(\frac { 5 }{ 4 } \)
(iii) \(\frac { 3 }{ 6 } \)
(iv) 2 \(\frac { 2 }{ 5 } \)
Solution.
Showing given fractions by diagrams

Question 3.
What is the fraction for 35 minutes to 1 hour?
Solution.

Question 4.
Write the fraction for (RBSESolutions.com) even numbers 1 to 15.
Solution.
Even numbers 1 to 15 = 2, 4, 6, 8, 10, 12, 14.
Total even numbers = 7
Hence, fraction = \(\frac { 7 }{ 15 } \)

Question 5.
Look at the following figures and write the fraction for its uncolored parts.

Solution.
Following fractions represents the uncolored parts of given figrues-
(i) \(\frac { 3 }{ 4 } \)
(ii) \(\frac { 6 }{ 10 } \) = \(\frac { 3 }{ 5 } \)
(iii) \(\frac { 2 }{ 3 } \)

Question 6.
Show the following (RBSESolutions.com) fractions on number line.
(i) \(\frac { 3 }{ 5 } \)
(ii) \(\frac { 3 }{ 7 } \)
(iii) \(\frac { 8 }{ 3 } \)

Solution.

Question 7.
Express the following (RBSESolutions.com) in mixed fractions.
(i) \(\frac { 20 }{ 3 } \)
(ii) \(\frac { 11 }{ 5 } \)
(iii) \(\frac { 19 }{ 6 } \)
Solution.

Question 8.
Express the following in (RBSESolutions.com) improper fractions.
(i) 7 \(\frac { 2 }{ 3 } \)
(ii) 5 \(\frac { 3 }{ 4 } \)
(iii) 4 \(\frac { 1 }{ 2 } \)
Solution.
On expressing fractions as improper fraction –
Dividend = Divisor × Quotient + Remainder
(i) 3 × 7 + 2 = 21 + 2 = 23
Thus, improper fraction = \(\frac { 23 }{ 2 } \)
(ii) 4 × 5 + 3= 20+ 3 = 23
Thus, improper fraction = \(\frac { 23 }{ 4 } \)
(iii) 2 × 4 + 1 = 8 + 1 = 9
Thus, improper fraction = \(\frac { 9 }{ 2 } \)

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