RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4

RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.4.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Vedic Mathematics
Exercise	Ex 7.4
Number of Questions	1
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4

Question 1.
Convert the vinkulum number (RBSESolutions.com) into general number :
(i) 3\(\overline { 5 } \)
(ii) 5\(\overline { 4 } \)
(iii) 13\(\overline { 2 } \)
(iv) 5\(\overline { 42 } \)
(v) 6\(\overline { 23 } \)
Solution.
(i) 3\(\overline { 5 } \)
Hint :
(a) Write the parammitra digit 5 of
\(=3\bar { 5 } \) the positive value of \(\bar { 5 } \) Le., 5.
= \(\underset { \cdot  }{ 3 } 5\) (b) Put one less sign on poorven of
= 25 \(\overline { 5 } \) i.e„ 3.
(c) Write \(\underset { . }{ 3 } =1\)
(d) Thus, we got general number of 3\(\overline { 5 } \)

(ii) 5\(\overline { 4 } \)
Hint :
= 5\(\overline { 4 } \) (a) Write the (RBSESolutions.com) parammitra digit 6 of the
\(=\underset { . }{ 5 } 6\) positive value of \(\overline { 4 } \) i.e. 4.
= 46 (b) Put one less sign on poorven of \(\overline { 4 } \) i.e., 5.
(c) Write \(\underset { . }{ 5 } =4\)
(d) Thus, we got general number of 5\(\overline { 4 } \)

(iii) 13\(\overline { 2 } \)
Hint :
13\(\overline { 2 } \) (a) Write the parammitra digit 8 of
\(=1\underset { . }{ 3 } 8\) the positive (RBSESolutions.com) value of \(\overline { 2 } \) i.e., 2.
= 128 (b) Put one less sign on poorven of \(\overline { 2 } \) i.e., 3.
(c) Write \(\underset { . }{ 3 } =2\)
(d) Thus, we got general number of 13\(\overline { 2 } \).

(iv) 5\(\overline { 42 } \)
Hint :
\(=5\overline { 42 } \) (a) Write the (RBSESolutions.com) parammitra digit of
\(\underset { . }{ 5 } 6\overline { 2 } \) positive value 4 of \(\overline { 4 } \) (at the tens place) i.e., 6.
= 46\(\overline { 2 } \) (b) Put one less sign on poorven of
\(=4\underset { . }{ 6 } 8\) \(\overline { 4 } \) i.e., 5.
= 458 (c) Write \(\underset { . }{ 5 } =4\)
(d) Write the parammitra digit of positive value 2 of \(\overline { 2 } \) (at the ones place) i.e., 8.
(e) Put one less sign on poorven of \(\overline { 2 } \) i.e., 6.
(f) Write \(\underset { . }{ 6 } =5\)
(g) Thus, we got general number of 5\(\overline { 42 } \) .

(v) 6\(\overline { 23 } \)
Hints :
= 6\(\overline { 23 } \) (a) Write (RBSESolutions.com) the parammitra digit of
\(=\underset { . }{ 6 } 8\overline { 3 } \) positive value 2 of \(\overline { 2 } \) (at the tens place) i.e., 8.
= 58\(\overline { 3 } \)
\(=5\underset { . }{ 8 } 7\) (b) Pat one less sign on poorven of
= 577 \(\overline { 2 } \) i.e., 6.
(c) Write \(\underset { . }{ 6 } =5\)
(d) Write the parammitra digit of positive value of \(\overline { 3 } \) of 3 (at the ones place), i.e., 7.
(e) Put one less sign on poorven of \(\overline { 3 } \) i.e., 8.
(f) Write \(\underset { . }{ 8 } =7\)
(g) Thus, we got (RBSESolutions.com) general number of 6\(\overline { 23 } \).

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