RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4

RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.4.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Vedic Mathematics
Exercise	Ex 7.4
Number of Questions	1
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4

Question 1.
Convert the vinkulum number (RBSESolutions.com) into general number :
(i) 3[latex]\overline { 5 } [/latex]
(ii) 5[latex]\overline { 4 } [/latex]
(iii) 13[latex]\overline { 2 } [/latex]
(iv) 5[latex]\overline { 42 } [/latex]
(v) 6[latex]\overline { 23 } [/latex]
Solution.
(i) 3[latex]\overline { 5 } [/latex]
Hint :
(a) Write the parammitra digit 5 of
[latex]=3\bar { 5 } [/latex] the positive value of [latex]\bar { 5 } [/latex] Le., 5.
= [latex]\underset { \cdot  }{ 3 } 5[/latex] (b) Put one less sign on poorven of
= 25 [latex]\overline { 5 } [/latex] i.e„ 3.
(c) Write [latex]\underset { . }{ 3 } =1[/latex]
(d) Thus, we got general number of 3[latex]\overline { 5 } [/latex]

(ii) 5[latex]\overline { 4 } [/latex]
Hint :
= 5[latex]\overline { 4 } [/latex] (a) Write the (RBSESolutions.com) parammitra digit 6 of the
[latex]=\underset { . }{ 5 } 6[/latex] positive value of [latex]\overline { 4 } [/latex] i.e. 4.
= 46 (b) Put one less sign on poorven of [latex]\overline { 4 } [/latex] i.e., 5.
(c) Write [latex]\underset { . }{ 5 } =4[/latex]
(d) Thus, we got general number of 5[latex]\overline { 4 } [/latex]

(iii) 13[latex]\overline { 2 } [/latex]
Hint :
13[latex]\overline { 2 } [/latex] (a) Write the parammitra digit 8 of
[latex]=1\underset { . }{ 3 } 8[/latex] the positive (RBSESolutions.com) value of [latex]\overline { 2 } [/latex] i.e., 2.
= 128 (b) Put one less sign on poorven of [latex]\overline { 2 } [/latex] i.e., 3.
(c) Write [latex]\underset { . }{ 3 } =2[/latex]
(d) Thus, we got general number of 13[latex]\overline { 2 } [/latex].

(iv) 5[latex]\overline { 42 } [/latex]
Hint :
[latex]=5\overline { 42 } [/latex] (a) Write the (RBSESolutions.com) parammitra digit of
[latex]\underset { . }{ 5 } 6\overline { 2 } [/latex] positive value 4 of [latex]\overline { 4 } [/latex] (at the tens place) i.e., 6.
= 46[latex]\overline { 2 } [/latex] (b) Put one less sign on poorven of
[latex]=4\underset { . }{ 6 } 8[/latex] [latex]\overline { 4 } [/latex] i.e., 5.
= 458 (c) Write [latex]\underset { . }{ 5 } =4[/latex]
(d) Write the parammitra digit of positive value 2 of [latex]\overline { 2 } [/latex] (at the ones place) i.e., 8.
(e) Put one less sign on poorven of [latex]\overline { 2 } [/latex] i.e., 6.
(f) Write [latex]\underset { . }{ 6 } =5[/latex]
(g) Thus, we got general number of 5[latex]\overline { 42 } [/latex] .

(v) 6[latex]\overline { 23 } [/latex]
Hints :
= 6[latex]\overline { 23 } [/latex] (a) Write (RBSESolutions.com) the parammitra digit of
[latex]=\underset { . }{ 6 } 8\overline { 3 } [/latex] positive value 2 of [latex]\overline { 2 } [/latex] (at the tens place) i.e., 8.
= 58[latex]\overline { 3 } [/latex]
[latex]=5\underset { . }{ 8 } 7[/latex] (b) Pat one less sign on poorven of
= 577 [latex]\overline { 2 } [/latex] i.e., 6.
(c) Write [latex]\underset { . }{ 6 } =5[/latex]
(d) Write the parammitra digit of positive value of [latex]\overline { 3 } [/latex] of 3 (at the ones place), i.e., 7.
(e) Put one less sign on poorven of [latex]\overline { 3 } [/latex] i.e., 8.
(f) Write [latex]\underset { . }{ 8 } =7[/latex]
(g) Thus, we got (RBSESolutions.com) general number of 6[latex]\overline { 23 } [/latex].

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