RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.4.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Vedic Mathematics |

Exercise |
Ex 7.4 |

Number of Questions |
1 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.4

Question 1.

Convert the vinkulum number (RBSESolutions.com) into general number :

(i) 3[latex]\overline { 5 } [/latex]

(ii) 5[latex]\overline { 4 } [/latex]

(iii) 13[latex]\overline { 2 } [/latex]

(iv) 5[latex]\overline { 42 } [/latex]

(v) 6[latex]\overline { 23 } [/latex]

Solution.

(i) 3[latex]\overline { 5 } [/latex]

**Hint :**

(a) Write the parammitra digit 5 of

[latex]=3\bar { 5 } [/latex] the positive value of [latex]\bar { 5 } [/latex] Le., 5.

= [latex]\underset { \cdot }{ 3 } 5[/latex] (b) Put one less sign on poorven of

= 25 [latex]\overline { 5 } [/latex] i.e„ 3.

(c) Write [latex]\underset { . }{ 3 } =1[/latex]

(d) Thus, we got general number of 3[latex]\overline { 5 } [/latex]

(ii) 5[latex]\overline { 4 } [/latex]

**Hint :**

= 5[latex]\overline { 4 } [/latex] (a) Write the (RBSESolutions.com) parammitra digit 6 of the

[latex]=\underset { . }{ 5 } 6[/latex] positive value of [latex]\overline { 4 } [/latex] i.e. 4.

= 46 (b) Put one less sign on poorven of [latex]\overline { 4 } [/latex] i.e., 5.

(c) Write [latex]\underset { . }{ 5 } =4[/latex]

(d) Thus, we got general number of 5[latex]\overline { 4 } [/latex]

(iii) 13[latex]\overline { 2 } [/latex]

**Hint :**

13[latex]\overline { 2 } [/latex] (a) Write the parammitra digit 8 of

[latex]=1\underset { . }{ 3 } 8[/latex] the positive (RBSESolutions.com) value of [latex]\overline { 2 } [/latex] i.e., 2.

= 128 (b) Put one less sign on poorven of [latex]\overline { 2 } [/latex] i.e., 3.

(c) Write [latex]\underset { . }{ 3 } =2[/latex]

(d) Thus, we got general number of 13[latex]\overline { 2 } [/latex].

(iv) 5[latex]\overline { 42 } [/latex]

**Hint :**

[latex]=5\overline { 42 } [/latex] (a) Write the (RBSESolutions.com) parammitra digit of

[latex]\underset { . }{ 5 } 6\overline { 2 } [/latex] positive value 4 of [latex]\overline { 4 } [/latex] (at the tens place) i.e., 6.

= 46[latex]\overline { 2 } [/latex] (b) Put one less sign on poorven of

[latex]=4\underset { . }{ 6 } 8[/latex] [latex]\overline { 4 } [/latex] i.e., 5.

= 458 (c) Write [latex]\underset { . }{ 5 } =4[/latex]

(d) Write the parammitra digit of positive value 2 of [latex]\overline { 2 } [/latex] (at the ones place) i.e., 8.

(e) Put one less sign on poorven of [latex]\overline { 2 } [/latex] i.e., 6.

(f) Write [latex]\underset { . }{ 6 } =5[/latex]

(g) Thus, we got general number of 5[latex]\overline { 42 } [/latex] .

(v) 6[latex]\overline { 23 } [/latex]

**Hints :**

= 6[latex]\overline { 23 } [/latex] (a) Write (RBSESolutions.com) the parammitra digit of

[latex]=\underset { . }{ 6 } 8\overline { 3 } [/latex] positive value 2 of [latex]\overline { 2 } [/latex] (at the tens place) i.e., 8.

= 58[latex]\overline { 3 } [/latex]

[latex]=5\underset { . }{ 8 } 7[/latex] (b) Pat one less sign on poorven of

= 577 [latex]\overline { 2 } [/latex] i.e., 6.

(c) Write [latex]\underset { . }{ 6 } =5[/latex]

(d) Write the parammitra digit of positive value of [latex]\overline { 3 } [/latex] of 3 (at the ones place), i.e., 7.

(e) Put one less sign on poorven of [latex]\overline { 3 } [/latex] i.e., 8.

(f) Write [latex]\underset { . }{ 8 } =7[/latex]

(g) Thus, we got (RBSESolutions.com) general number of 6[latex]\overline { 23 } [/latex].

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