RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.5

RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.5 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.5.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Vedic Mathematics
Exercise	Ex 7.5
Number of Questions	1
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.5

Question 1.
Find the sum of vinkulum (RBSESolutions.com) numbers.

Solution.

Hints :

(a) In the unit digit \(\overline { 3 }\) + \(\overline { 3 }\) = \(\overline { 6 }\)
(b) In the (RBSESolutions.com) tens digit 6 + \(\overline { 4 }\) = 2
(c) Convert 2\(\overline { 6 }\) into general number.
(d) Parammitra digit of \(\overline { 6 }\) i.e., 4.
(e) Put one less sign on the poorven digit of 6 i,e., 2.
(f) write \(\underset { . }{ 2 } =1\)
(g) Thus, \(\overline { 63 }\) + \(\overline { 43 }\) = 14

Hints :

(a) In the (RBSESolutions.com) unit digit 3 + \(\overline { 2 }\) = 1
(b) in the digit 7 + \(\overline { 4 }\) = 3
(c) Thus, 73 + \(\overline { 42 }\) = 31

Hints :

(a) In the unit digit \(\overline { 2 }\) + \(\overline { 5 }\) = \(\overline { 7 }\)
(b) In the tens (RBSESolutions.com) digit 8 + \(\overline { 5 }\) = 3
= 33 (c) Convert 3\(\overline { 7 }\) into general number.
= 23 (d) Parammitra digit of \(\overline { 7 }\) i.e., 3.
(e) Put one less sign on the poorven digit of \(\overline { 7 }\) i.e., 3.
(f) Write \(\underset { . }{ 3 } =2\)
(g) Thus, 8\(\overline { 2 }\) + \(\overline { 55 }\) = 23

Hints :

(a) In unit digit \(\overline { 9 }\) + 8 = \(\overline { 1 }\)
(b) In tens (RBSESolutions.com) digit 8 + \(\overline { 7 }\) = 1
(c) Convert 1\(\overline { 1 }\) into general numbrs.
= 19 (d) Parammitra digit of \(\overline { 1 }\) i.e., 9.
= 09 (e) Put one less sign on the poorven digit of \(\overline { 1 }\) i.e., 1.
(f) Write \(\underset { . }{ 1 } =0\)
(g) Thus, 8\(\overline { 9 }\) + \(\overline { 7 }\)8 = 09 or 9

Hints :

(a) In unit (RBSESolutions.com) digit \(\overline { 3 }\) + 1 = \(\overline { 2 }\)
(b) In tens digit 5 + \(\overline { 2 }\) = 3
(c) Convert 3\(\overline { 2 }\) into general number.
(d) Parammitra digit of \(\overline { 2 }\) i.e., 8.
(e) Put one less sign on the poorven digit of \(\overline { 2 }\) i.e., 3.
(f) Write \(\underset { . }{ 3 } =2\)
(g) Thus, 5\(\overline { 3 }\) + \(\overline { 2 }\)1 = 28

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