RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.5 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.5.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Vedic Mathematics |

Exercise |
Ex 7.5 |

Number of Questions |
1 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.5

Question 1.

Find the sum of vinkulum (RBSESolutions.com) numbers.

Solution.

**Hints :
**

(a) In the unit digit [latex]\overline { 3 }[/latex] + [latex]\overline { 3 }[/latex] = [latex]\overline { 6 }[/latex]

(b) In the (RBSESolutions.com) tens digit 6 + [latex]\overline { 4 }[/latex] = 2

(c) Convert 2[latex]\overline { 6 }[/latex] into general number.

(d) Parammitra digit of [latex]\overline { 6 }[/latex] i.e., 4.

(e) Put one less sign on the poorven digit of 6 i,e., 2.

(f) write [latex]\underset { . }{ 2 } =1[/latex]

(g) Thus, [latex]\overline { 63 }[/latex] + [latex]\overline { 43 }[/latex] = 14

**Hints :
**

(a) In the (RBSESolutions.com) unit digit 3 + [latex]\overline { 2 }[/latex] = 1

(b) in the digit 7 + [latex]\overline { 4 }[/latex] = 3

(c) Thus, 73 + [latex]\overline { 42 }[/latex] = 31

**Hints :
**

(a) In the unit digit [latex]\overline { 2 }[/latex] + [latex]\overline { 5 }[/latex] = [latex]\overline { 7 }[/latex]

(b) In the tens (RBSESolutions.com) digit 8 + [latex]\overline { 5 }[/latex] = 3

= 33 (c) Convert 3[latex]\overline { 7 }[/latex] into general number.

= 23 (d) Parammitra digit of [latex]\overline { 7 }[/latex] i.e., 3.

(e) Put one less sign on the poorven digit of [latex]\overline { 7 }[/latex] i.e., 3.

(f) Write [latex]\underset { . }{ 3 } =2[/latex]

(g) Thus, 8[latex]\overline { 2 }[/latex] + [latex]\overline { 55 }[/latex] = 23

**Hints :
**(a) In unit digit [latex]\overline { 9 }[/latex] + 8 = [latex]\overline { 1 }[/latex]

(b) In tens (RBSESolutions.com) digit 8 + [latex]\overline { 7 }[/latex] = 1

(c) Convert 1[latex]\overline { 1 }[/latex] into general numbrs.

= 19 (d) Parammitra digit of [latex]\overline { 1 }[/latex] i.e., 9.

= 09 (e) Put one less sign on the poorven digit of [latex]\overline { 1 }[/latex] i.e., 1.

(f) Write [latex]\underset { . }{ 1 } =0[/latex]

(g) Thus, 8[latex]\overline { 9 }[/latex] + [latex]\overline { 7 }[/latex]8 = 09 or 9

**Hints :
**(a) In unit (RBSESolutions.com) digit [latex]\overline { 3 }[/latex] + 1 = [latex]\overline { 2 }[/latex]

(b) In tens digit 5 + [latex]\overline { 2 }[/latex] = 3

(c) Convert 3[latex]\overline { 2 }[/latex] into general number.

(d) Parammitra digit of [latex]\overline { 2 }[/latex] i.e., 8.

(e) Put one less sign on the poorven digit of [latex]\overline { 2 }[/latex] i.e., 3.

(f) Write [latex]\underset { . }{ 3 } =2[/latex]

(g) Thus, 5[latex]\overline { 3 }[/latex] + [latex]\overline { 2 }[/latex]1 = 28

We hope the RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.5 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.5, drop a comment below and we will get back to you at the earliest.

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