RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.6 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.6.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Vedic Mathematics |

Exercise |
Ex 7.6 |

Number of Questions |
1 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.6

Question 1.

Find out the difference (RBSESolutions.com) using vinkulum.

Solution.

**Hints :
**

(a) Changing the sign of – 49 into +, write 4 and 9 with (RBSESolutions.com) their vinkulum lines.

(b) Write 6 + [latex]\overline { 9 } [/latex] = [latex]\overline { 3 } [/latex] in the units place.

[latex]=\underset { . }{ 5 } 7[/latex]

= 47 (c) Write 9 + [latex]\overline { 4 } [/latex] = 5 in the tens place.

(d) Convert 5[latex]\overline { 3 } [/latex] into general number.

(e) Parammitra of [latex]\overline { 3 } [/latex] i.e., 1.

(f) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 5.

(g) Write [latex]\underset { . }{ 5 } =4[/latex]

(h) Thus, 96 – 49 = 47

**Hints :
**

(a) Changing the sign of – 245 into +, write 2, 4 and 5 with (RBSESolutions.com) their vinkulum lines.

[latex]-\underset { . }{ 7 } 9\overline { 3 } [/latex] (b) Write 2 + [latex]\overline { 5 } [/latex] = [latex]\overline { 3 } [/latex] in the units place.

= 69[latex]\overline { 3 } [/latex] (c) Write 3 + [latex]\overline { 4 } [/latex] = [latex]\overline { 1 } [/latex] in the tens place.

[latex]=6\underset { . }{ 9 } 7[/latex] (d) Write 9 + [latex]\overline { 2 } [/latex] = 7 in the hundreds place.

(e) Convert 7[latex]\overline { 13 } [/latex] into general number.

(f) Parammitra digit of 1 (tens digit) i.e., 9.

(g) Put one less sign on the poorven digit of [latex]\overline { 1 } [/latex] i.e., 7.

(h) Write [latex]\underset { . }{ 7 } =6[/latex]

(i) Parammitra digit of [latex]\overline { 3 } [/latex] (units digit) i.e., 7.

(j) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 9.

(k) Write [latex]\underset { . }{ 9 } =8[/latex]

(l) Thus, 932 – 245 = 687

**Hints :
**

(a) Changing the (RBSESolutions.com) sign of – 788 into +, write 7, 8 and 8 with their vinkulum lines.

[latex]\underset { . }{ 2 } 7\overline { 6 } [/latex] (b) Write 2 + [latex]\overline { 8 } [/latex] = [latex]\overline { 6 } [/latex] in the units place.

[latex]=17\overline { 6 } [/latex] (c) Write 5 + [latex]\overline { 8 } [/latex] = [latex]\overline { 3 } [/latex] in the tens place.

[latex]=1\underset { . }{ 7 } 4[/latex] (d) Write 9 + [latex]\overline { 7 } [/latex] = 2 in the hundreds place.

(e) Convert 2[latex]\overline { 36 } [/latex] into general number.

(f) Parammitra digit of [latex]\overline { 3 } [/latex] (tens place) i.e., 7.

(g) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 2.

(h) Write 2 = 1.

(i) Parammitra digit of [latex]\overline { 6 } [/latex] (units place) i.e., 4.

(j) Put one less sign on (RBSESolutions.com) the poorven digit of [latex]\overline { 6 } [/latex] ie., 7.

(k) Write [latex]\underset { . }{ 7 } =6[/latex]

(l) Thus, 952 – 788 = 164

**Hints :
**

(a) Changing the sign of -547 into + write 5, 4 and 7 with their vinkulum lines.

[latex]=\underset { . }{ 3 } 9\overline { 3 } [/latex] (b) Write 4 + [latex]\overline { 7 } [/latex] = [latex]\overline { 3 } [/latex] in the units place.

[latex]=29\overline { 3 } [/latex] (c) Write 3 + [latex]\overline { 4 } [/latex] = [latex]\overline { 1 } [/latex] in the tens place.

[latex]=2\underset { . }{ 9 } 7[/latex] (d) Write 8 + [latex]\overline { 5 } [/latex] = 3 in the hundreds place.

= 287 (e) Convert 3[latex]\overline { 13 } [/latex] into general number.

(f) Parammitra digit of [latex]\overline { 1 } [/latex] (tens digit) i.e., 9.

(g) Put one less sign on the poorven (RBSESolutions.com) digit of [latex]\overline { 1 } [/latex] i.e., 3.

(h) Write [latex]\underset { . }{ 3 } =2[/latex]

(i) Parammitra digit of [latex]\overline { 3 } [/latex] (units digit) i.e., 7.

(j) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 9.

(k) Write [latex]\underset { . }{ 9 } =8[/latex]

(l) Thus, 834 – 547 = 287

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