RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.6

RBSE Solutions for Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.6 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Exercise 7.6.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 7
Chapter Name	Vedic Mathematics
Exercise	Ex 7.6
Number of Questions	1
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 7 Vedic Mathematics Ex 7.6

Question 1.
Find out the difference (RBSESolutions.com) using vinkulum.

Solution.

Hints :

(a) Changing the sign of – 49 into +, write 4 and 9 with (RBSESolutions.com) their vinkulum lines.
(b) Write 6 + [latex]\overline { 9 } [/latex] = [latex]\overline { 3 } [/latex] in the units place.
[latex]=\underset { . }{ 5 } 7[/latex]
= 47 (c) Write 9 + [latex]\overline { 4 } [/latex] = 5 in the tens place.
(d) Convert 5[latex]\overline { 3 } [/latex] into general number.
(e) Parammitra of [latex]\overline { 3 } [/latex] i.e., 1.
(f) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 5.
(g) Write [latex]\underset { . }{ 5 } =4[/latex]
(h) Thus, 96 – 49 = 47

Hints :

(a) Changing the sign of – 245 into +, write 2, 4 and 5 with (RBSESolutions.com) their vinkulum lines.
[latex]-\underset { . }{ 7 } 9\overline { 3 } [/latex] (b) Write 2 + [latex]\overline { 5 } [/latex] = [latex]\overline { 3 } [/latex] in the units place.
= 69[latex]\overline { 3 } [/latex] (c) Write 3 + [latex]\overline { 4 } [/latex] = [latex]\overline { 1 } [/latex] in the tens place.
[latex]=6\underset { . }{ 9 } 7[/latex] (d) Write 9 + [latex]\overline { 2 } [/latex] = 7 in the hundreds place.
(e) Convert 7[latex]\overline { 13 } [/latex] into general number.
(f) Parammitra digit of 1 (tens digit) i.e., 9.
(g) Put one less sign on the poorven digit of [latex]\overline { 1 } [/latex] i.e., 7.
(h) Write [latex]\underset { . }{ 7 } =6[/latex]
(i) Parammitra digit of [latex]\overline { 3 } [/latex] (units digit) i.e., 7.
(j) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 9.
(k) Write [latex]\underset { . }{ 9 } =8[/latex]
(l) Thus, 932 – 245 = 687

Hints :

(a) Changing the (RBSESolutions.com) sign of – 788 into +, write 7, 8 and 8 with their vinkulum lines.
[latex]\underset { . }{ 2 } 7\overline { 6 } [/latex] (b) Write 2 + [latex]\overline { 8 } [/latex] = [latex]\overline { 6 } [/latex] in the units place.
[latex]=17\overline { 6 } [/latex] (c) Write 5 + [latex]\overline { 8 } [/latex] = [latex]\overline { 3 } [/latex] in the tens place.
[latex]=1\underset { . }{ 7 } 4[/latex] (d) Write 9 + [latex]\overline { 7 } [/latex] = 2 in the hundreds place.
(e) Convert 2[latex]\overline { 36 } [/latex] into general number.
(f) Parammitra digit of [latex]\overline { 3 } [/latex] (tens place) i.e., 7.
(g) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 2.
(h) Write 2 = 1.
(i) Parammitra digit of [latex]\overline { 6 } [/latex] (units place) i.e., 4.
(j) Put one less sign on (RBSESolutions.com) the poorven digit of [latex]\overline { 6 } [/latex] ie., 7.
(k) Write [latex]\underset { . }{ 7 } =6[/latex]
(l) Thus, 952 – 788 = 164

Hints :

(a) Changing the sign of -547 into + write 5, 4 and 7 with their vinkulum lines.
[latex]=\underset { . }{ 3 } 9\overline { 3 } [/latex] (b) Write 4 + [latex]\overline { 7 } [/latex] = [latex]\overline { 3 } [/latex] in the units place.
[latex]=29\overline { 3 } [/latex] (c) Write 3 + [latex]\overline { 4 } [/latex] = [latex]\overline { 1 } [/latex] in the tens place.
[latex]=2\underset { . }{ 9 } 7[/latex] (d) Write 8 + [latex]\overline { 5 } [/latex] = 3 in the hundreds place.
= 287 (e) Convert 3[latex]\overline { 13 } [/latex] into general number.
(f) Parammitra digit of [latex]\overline { 1 } [/latex] (tens digit) i.e., 9.
(g) Put one less sign on the poorven (RBSESolutions.com) digit of [latex]\overline { 1 } [/latex] i.e., 3.
(h) Write [latex]\underset { . }{ 3 } =2[/latex]
(i) Parammitra digit of [latex]\overline { 3 } [/latex] (units digit) i.e., 7.
(j) Put one less sign on the poorven digit of [latex]\overline { 3 } [/latex] i.e., 9.
(k) Write [latex]\underset { . }{ 9 } =8[/latex]
(l) Thus, 834 – 547 = 287

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