RBSE Solutions for Class 6 Maths Chapter 8 Basic Geometrical Concepts and Shapes Ex 8.2

RBSE Solutions for Class 6 Maths Chapter 8 Basic Geometrical Concepts and Shapes Ex 8.2 is part of RBSE Solutions for Class 6 Maths. Here we have given Rajasthan Board RBSE Class 6 Maths Chapter 8 Basic Geometrical Concepts and Shapes Exercise 8.2.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 6
Subject	Maths
Chapter	Chapter 8
Chapter Name	Basic Geometrical Concepts and Shapes
Exercise	Ex 8.2
Number of Questions	6
Category	RBSE Solutions

Rajasthan Board RBSE Class 6 Maths Chapter 8 Basic Geometrical Concepts and Shapes Ex 8.2

Question 1.
Write the names of parallel and intersecting (RBSESolutions.com) lines in the figures below.

Solution:
Parallel lines – (i) AB and CD, (iv) MN and ST
Intersecting lines – (ii) XY and WZ (i) PQ and RS

Question 2.
If five lines of different lengths pass through a point, then what are the lines called?
Solution:
Concurrent lines.

Question 3.
Bisect the line segments of the following (RBSESolutions.com) lengths and write the length of each part.
(i) 8 cm
(ii) 7.6 cm
(iii) 5.8 cm
(iv) 6.4 cm
Solution:
(i) (A) Given : Line segment AB = 8 cm.
(B) To Draw : Bisector of line segment AB.
(C) To Find : Measurement of each part.

Drawing :
(1) Draw a line segment AB = 8 cm.
(2) Now, open the compass more than (RBSESolutions.com) half and cut an arc on both sides letting A and B as center, which intersects each other at points C and D.
(3) Draw a line CD, joining the points C and D, which cut AB at point O.
∴ OA and OB are two required segments of equal lengths.
Measurement : OA = OB = 4 cm.

(ii) (A) Given : Line segment AB = 7.6 cm.
(B) To Draw : Bisector of line segment AB.
(C) To Find : Measurement of each part.

Drawing :
(1) Draw a line segment AB = 7.6 cm.
(2) Now, open the compass more than (RBSESolutions.com) half and cut on arc on both sides, letting A and B as center, which intersects each other at point C and D.
(3) Draw a line CD, joining the points C and D, which cut AB at point O.
∴ OA and OB are two required segments of equal lengths.
Measurement : OA = OB = 3.8 cm.

(iii)  (A) Given : Line segment AB = 5.8 cm
(B) To Draw : Bisector of line segment AB.
(C) To Find : Measurement of each part.

Drawing :
(1) Draw line segment AB = 5.8 cm
(2) Now, open the con pass (RBSESolutions.com) more than hall and cut an arc on both sides letting A and B as center, which intersects each other at point C and D.
(3) Draw a line CD, joining the points C and D, which cut AB at point O.
∴ OA and OB are two required segments of equal lengths.
Measurement : OA = OB = 2.9 cm

(iv) (A) Given : Line segment AB = 6.4 cm.
(B) To Draw : Bisector of line segment AB.
(C) To Find : Measurement of each part.

Drawing :
(1) Draw a line segment AB = 6.4 cm.
(2) Now, open the (RBSESolutions.com) compass more than 6.4 cm halt and cut an arc A on both sides, letting A and B as center, which intersects each other at point C and D.
(3) Draw a line CD, joining the points C and D, which cut AB at point O.
∴ OA and OB are two required segments of equal lengths.
Measurement : OA = OB = 3.2 cm.

Question 4.
Identify and name the perpendicular lines from the figures below

Solution:
On measuring angles we find that
(i) PQ ⊥ QR
(ii) XY ⊥ PQ
(v) AB ⊥ BC.

Question 5.
Draw a line segment MN and mark a point L on it. With (RBSESolutions.com) a ruler and compass, draw a perpendicular to MN through the point L.
Solution:
Drawing a perpendicular on given point on a line.
Step 1 : Point L is given on line MN.

Step 2 : Assume L as a center and take a convenient radius draw an arc which will intersect line MN at points C and D.

Step 3 : Keeping the pointed tip of the (RBSESolutions.com) compasses on point C. Draw an arc above the line. Keeping the radius same, draw another arc while the tip of the compass is at D. The point of intersection of two arcs is labelled as Q. Join Q and L.

Step 4 : In this way, QL is perpendicular to MN.

Question 6.
Draw a line segment AB. Taking a point R not on the line AB, draw a perpendicular to AB from R.
Solution:
Drawing a perpendicular on a line from a given point.
Step 1 : Point R is situated externally to line AB.

Step 2 : Taking a suitable radius draw on arc (RBSESolutions.com) from point R using compass. This arc intersects the line AB at points C and D.

Step 3 : Keeping the tip of compass on C, draw an arc at the bottom, with same radius and the tip of compass on D. Draw an arc intersecting the previous arc. Thus, point Q obtained and is joined with R. Line PR is perpendicular to AB from point R.

We hope the RBSE Solutions for Class 6 Maths Chapter 8 Basic Geometrical Concepts and Shapes Ex 8.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 6 Maths Chapter 8 Basic Geometrical Concepts and Shapes Exercise 8.2, drop a comment below and we will get back to you at the earliest.