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RBSE Solutions for Class 7 Maths Chapter 1 Integers In Text Exercise

March 21, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 7 Maths Chapter 1 Integers In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 1 Integers In Text Exercise .

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 1
Chapter Name Integers
Exercise In Text Exercise
Number of Questions 24
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 1 Integers In Text Exercise

(Page 2)
Question
Check if integers are also (RBSESolutions.com) closed for addition.

S.No Integers Integer Addition As the Sum integer yes/no
1. +2 +5 +7 yes
2. -3 +7
3. -4 +4
4. 3 -5

Take various integers and check if (RBSESolutions.com) this is true only for positive integers or it is true for negative integers also.
Solution:

S.No Integers Integer Addition As the Sum integer yes/no
1. +2 +5 +7 yes
2. -3 +7 +4 yes
3. -4 +4 0 yes
4. 3 -5 -2 yes

From above table it is clear that all integers whether they are negative or positive are closed for addition.

RBSE Solutions

(Page 3)
Question
Can you tell such integers (RBSESolutions.com) whose sum is not an integer?
Solution:
Such integers are impossible because sum of an two integers is always an integer.

Question
What happens when we subtract one integer from another? Does their difference is also an integer? Complete the following table by observation:
Solution:

S.No Statement Observation
1. 7 – 5 = 2 Result is an integer
2. 4 – 9 = -5 ………….
3. (-4) – (-5) = …. Result is an integer
4. (-18) – (-18) = .. ………..
5. 17 – 0 = …. ………….

Solution:

S.No Statement Observation
1. 7 – 5 = 2 Result is an integer
2. 4 – 9 = -5 Result is an integer
3. (-4) – (-5) = 1 Result is an integer
4. (-18) – (-18) = 0 Result is an integer
5. 17 – 0 = 17 Result is an integer

From table it ¡s clear that when we subtract one integer from another integer then remainder is also an integer. Therefore difference of two integers, is also an integer.

Question
Can we find such pair of integers (RBSESolutions.com) whose difference is not an Integer?
Solution:
Such pair is impossible because difference of two integers is also an integer.

Question
Check weather the following statements are same?
(-8) + (-4) and (-4) + (-8)
(-2) + 5 and 5 + (-2)
12 + 0 and 0 + 12
does integers also follow (RBSESolutions.com) commutative property of addition ? Find some other additions also.
Solution:

Mathematical
Statement
Result Mathematical
Statement
Result
(-8) + (-4) -12 (-4) + (-8) -12
(-2) + 5 +3 5 + (-2) +3
12 + 0 12 0 + 12 12
17 + (-2) 15 (-2) + 17 15
2 + (-3) -1 (-3) + 2 -1
(-3) + 6 3 6 + (-3) 3

From table it is clear that integers also follow the commutative property of addition.

RBSE Solutions

Question
Is there any such pair of integers (RBSESolutions.com) where result changes on. After changing the order of integers?
Solution:
No, such pair is impossible where result changes on interchanging their order.

(Page 4)
Question
Observe the following and fill in the blanks :
(i)(-4) + 0 = -4,
(ii) 7 + 0 = 7,
(iii) 0+ (-14) = ….,
(iv) -8 + …. = – 8
(v) …. + 0 = 15,
(vi) – 23 + …. =- 23
Solution:
(iii) 0 + (-14) = – 14,
(iv) (-8) + 0 = -8
(v) 15 +0 = 15,
(vi) (-23) + 1 = -23

Question
From some other examples, (RBSESolutions.com) confirm that 0 is an additive identity for integers.
Solution:
From above examples, it is clear that on adding 0 with any other integer, same integer is found. Therefore 0 is additive identity for integers. It can be understand by following examples
(i) 5 + 0 = 5,
(ii) (- 10) + 0 = – 10,
(iii) (- 9) + 0 = – 9,
(iv) 23 + 0 = 23
(v) 0 + 20 = 20,
(vi) 0 + (-2) = -2

(Page 6)
Question
What happens when we multiply (RBSESolutions.com) a negative integer with a positive integer?
Solution:
When a negative integer is multiplied with a positive integer then negative integer is found, it can be verified from following examples –
(i) – 1 x 4 = – 4 = 0 – 4
(ii) – 2 x 4 = – 8 = – 4 – 4
(iii) -3 x 4 = – 12 = – 4 – 4 – 4
(iv) – 5 x 2 = -10 = – 5 – 5
(v) – 6 x 3 = -18 = – 6 – 6 – 6

RBSE Solutions

(Page 7)
Question
Observe the (RBSESolutions.com) following :
-3 x 4 = -12
-3 x 3 = -9 = -12 – (-3)
-3 x 2 =-6 = -9 – (-3)
-3 x 1 = -3 = -6 – (-3)
-3 x 0 = 0 = -3 – (-3)
-3 x (-1) = 3 = 0 – (-3)
-3 x (-2) = 6 = 3-(-3)
Similarly, complete the following :
(i) -3 x (-3) = …….
(ii) – 3 x (-4) = …….
Solution:
(i) (-3) x (-3) = 9 = 6 – (-3)
(ii) (-3) x (-4) = 12 = 9 – (-3)

Question
Fill in the blanks in (RBSESolutions.com) similar manner:
-5 x 3 = -15
-5 x 2 = -10 = -15-(-5)
-5 x 1 =- = -10-(-5)
-5 x (-1) = ……. =
-5 x (-2) = ………. =
-5 x (-3) = ……… =
Solution:
-5 x 0 = 0 = – 5 -(-5)
-5 x (-1) = 5 = (0 -(-5)
(-5) x (-2) = 10 = 5-(-5)
(-5) x (-3) = 15 = 10 – (-5)

(Page 9)
Question
Observe the division statements in the (RBSESolutions.com) table and accordingly check the following statements and put the sign ( ✓ or ✘) :

Multiplication Statement Corresponding Division Statement
3 x (-5) = (-15) (-15) ÷ (3) = – 5, (15) ÷ (-5) = 3
(-3) x 4= (-12)

(-12) ÷ (-3) = 4,(-12) ÷ 4=-3

(-2) x (-7) = (14)…. 14 ÷ (-7)= -2,
……..
(-4) x 5 = (- 20) (-20) ÷ (-4) = 5,
……..
5 x (-9) = – 45…. ………………..
(- 6) x 5 = …. …………………
(+ 5) x (+ 2) = …. ………………..

(i) Negative integer ÷ Positive (RBSESolutions.com) integer = Negative integer ( )
(ii) Positive integer ÷ Negative integer = Negative integer ( )
(iii) Positive integer ÷ Positive integer = Positive integer ( )
(iv) Negative integer ÷ Negative integer = Positive integer ( )
Solution:

Multiplication Statement Corresponding Division Statement
(-2) x (-7) = (14) 14 ÷ (-7)=-2,
14 ÷ (-2) = -7
(-4) x 5 = (- 20) (-20) ÷ (-4) = 5,
(-20) ÷ 5 = -4
5 x (-9) = – 45 (-45) ÷ 5 = -9
(-45) ÷ (-9) = 5
(- 6) x 5 = (-30) (-30) ÷ (-6) = 5,
(-30) ÷ 5 = -6
(+ 5) x (+ 2) = 10 (+10) ÷ (+5) = +2,
(+10) ÷ (+2) = +5

(i) Negative integer ÷ Positive (RBSESolutions.com) integer = Negative integer (✓)
(ii) Positive integer ÷ Negative integer = Negative integer (✓)
(iii) Positive integer  ÷ Positive integer = Positive integer (✓)
(iv) Negative integer ÷ Negative integer = Positive integer (✓)

RBSE Solutions

(Page 10)
Question
Complete the following table:

Integer-1 Integer-2 Product Product is an integer Yes/No
2 -3 -6 Integer
-3 4 -12 Integer
-2 -3 …… …….
5 4 ….. …….
-5 3 ….. ……

Solution:

Integer-1 Integer-2 Product Product is an integer Yes/No
-2 -3 6 Integer
5 4 20 Integer
-5 3 -15 Integer

Conclusion: Product of two (RBSESolutions.com) integers is also an integer.

(Page 11)
Question
Observe and complete the following table RBSE Solutions for Class 7 Maths Chapter 1 Integers In Text Exercise
Solution:
RBSE Solutions for Class 7 Maths Chapter 1 Integers In Text Exercise
Outcome: Product of integers does not depend on their order.

Question
Check for the (RBSESolutions.com) integers
(-3) x 1 =-3 1 x 5=5
(-4) x 1 = 1 x 8 =
1 x (-5) = 3 x 1 =
1 x (-6) = 7 x 1 =
Solution:
(-4) x 1 =-4 1 x 8 = 8
1 x (5) =-5 3 x 1 = 3
1 x (-6) = – 6 7 x 1 = 7
Outcome : Multiplicative identity for integers is 1.

(Page 12)
Question
Observe and complete (RBSESolutions.com) the following table

Statement Conclusion
(- 8) ÷ (-2) = 4 is an integer
(-8 ) ÷ 4 ………….
(-2) ÷ (-8) = \(\frac { -2 }{ -8 }\) is not an integer
(3) ÷ (-8) = \(\frac { 3 }{ -8 }\) …………….

Solution:

Statement Conclusion
(-8 ) ÷ 4 = -2 is an integer
(3) ÷ (-8) = \(\frac { 3 }{ -8 }\) is not an integer

RBSE Solutions

Do and Learn

Question 1
In which direction one should (RBSESolutions.com) move on the number line to add – 5?
Solution:
On number line, left side will be used to add – 5.

Question 2
In which direction one will move on the number line to subtract – 5 from 3 and will reach on what number ? 3 – (- 5) = ……
Solution:
On number line, right side will be used and will reach at, 3 – (- 5) = 3 + 5 = 8.

Question 3
In which direction we will (RBSESolutions.com) move and on which number will we reach by adding 5 to 3?
Solution:
On number line, right side will be used and will reach at, 3 + 5 = 8.

Question 4
In which direction we will move and on which number will we teach by subtracting + 5 from – 3?
Solution:
On number line, left side will be (RBSESolutions.com) used and will reach at – 3 – (+ 5) = – 3 – 5 = -8.

(Page 6)
Question
Solve:
(i) 4 x (8) = …. = ….
(ii) 3 x (-3) = …. = ……
(iii) 5 x (-9) = …. = …..
Solution:
(i) 4 x (8) = (- 8) + (-8) + (-8) + (-8) = -32
(ii) 3 x (-3) = (-3) + (-3) + (-3) = -9
(iii) 5 x (-9) = (-9) + (-9) + (- 9) + (-9) + (-9) = -45

(Page 7)
Question
Find:
(i) 15 x (-5)
(ii) 27 x (- 10)
(iii) – 12 x 12
(iv) -7 x 4
Solution:
(i) 15 x (-5) = – 75
(ii) 27 x (- 10) = – 270
(iii) – 12 x 12 = – 144
(iv) – 7 x 4 = – 28

Question
Find the following (RBSESolutions.com) products:
(i) (-12) x (-15)
(ii) (-25) x (-4)
(iii) (-17) x (-11)
Solution:
(i) (-12) x (-15) = 180
(ii) (-25) x (-4) = 100
(iii) (-17) x (-11) = 187

RBSE Solutions

(Page 8)
Question
Find the following (RBSESolutions.com) product
(i) (-1) x (-1) x (-1) = ……..
(ii) (-1) x (-1) x (-1) x (-1) = ……..
Solution:
(i) (-1) x (-1) x (-1) = [(-1) x (-1)] x (-1) = (+1) x (-1) = -1
(ii) (-1) x (-1) x (-1) x (-1) = [(-1) x (-1)] x [(-1) x (-1)] = 1 x 1 = 1

We hope the RBSE Solutions for Class 7 Maths Chapter 1 Integers In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 1 Integers In Text Exercise, drop a comment below and we will get back to you at the earliest.

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