RBSE Solutions for Class 7 Maths Chapter 13 Algebraic Expression Ex 13.3 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression Exercise 13.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 13 |

Chapter Name |
Algebraic Expression |

Exercise |
Ex 13.3 |

Number of Questions |
4 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression Ex 13.3

Question 1

Find the value (RBSESolutions.com) of following if x = 2.

(i) – 3

(ii) 2x – 5

(iii) 9 – 6x

(iv) 3x^{2} – 4x – 7

(v) [latex]\frac { 5x }{ 2 }[/latex] – 4

Solution:

(i) In x – 3 put x = 2

x – 3 = 2 – 3 = -1

(ii) In 2x – 5 put x = 2

2x – 5 = 2 x 2 – 5

= 4 – 5 = -1

(iii) In 9 – 6x put x = 2

9 – 6x = 9 – 6 x 2

= 9 – 12 = -3

(iv) In 3x^{2} – 4x – 7 put x = 2

3x^{2} – 4x – 7 = 3 x 2 x 2 – 4 x 2 – 7

= 12 – 8 – 7

= 12 – 15 = -3

(v) In [latex]\frac { 5x }{ 2 }[/latex] – 4 put x = 2

[latex]\frac { 5x }{ 2 }[/latex] – 4 = [latex]\frac { 5\times 2}{ 2 }[/latex] – 4

= 5 – 4 = 1

Question 2

Find the value of (RBSESolutions.com) following, if p = – 1.

(i) 4p + 5

(ii) -3p^{2} + 4p + 8

(iii) 3(p – 2) + 6

Solution:

(i) In 4p + 5 put p =-1

4p + 5 = 4 x (-1) +5

= -4 + 5 = 1

(ii) In -3p^{2} + 4p +8 put p = -1

-3p^{2} + 4p + 8 = -3(-1)^{2}+ 4(-1) + 8

= -3 x 1 – 4 + 8

=-3 – 4 + 8 = 1

(iii) In 3(p – 2) + 6 put p = -1

3(p – 2) + 6 = 3 (-1 – 2) + 6

= 3(-3) + 6 = -9 +6 = -3

Question 3

Find the value of (RBSESolutions.com) following if a = 2 and b = – 2.

(i) a^{2} – b^{2}

(ii) a^{2} – ab + b^{2}

(iii) a^{2} + b^{2}

Solution:

(i) In (a^{2} – b^{2}) put a = 2 and b = -2

a^{2} – b^{2} = (2)^{2} – (-2)

= 4 – 4 = 0

(ii) In (a^{2} – ab + b^{2}) put a = 2 and b = -2

a^{2} – ab + b^{2} = (2)^{2} – 2x(-2) + (-2)^{2}

= 4 + 4 + 4 = 12

(iii) In a^{2} + b^{2} put a = 2 and b = -2

a^{2} + b^{2} = (2)^{2} + (-2)^{2}

= 4 + 4 = 8

Question 4

Find the value (RBSESolutions.com) of following if x = 1 and y = o.

(i) 2x + 2y

(ii) 2x^{2} + y^{2} +1

(iii) 2x^{2}y + 2x^{2}y^{2} +y^{2}

(iv) x^{2} + xy +5

Solution:

(i) In (2x + 2) put x = 1 and y= 0

2x + 2y = 2 x 1 + 2 x 0

= 2+ 0 = 2

(ii) In (2x^{2} + y^{2} + 1) put x = 1 and y = 0

2x^{2} + y^{2} + 1 = 2(1)^{2} + (0)^{2 }+ 1

= 2 x 1 +0 + 1

= 2 + 1 = 3

(iii) In (2x^{2}y+ 2x^{2}y^{2} +2) put x = 1 and y = 0

2x^{2}y + 2x^{2}y^{2 }+ y^{2} = 2(1)^{2} x 0 + 2(1)^{2}x (0)^{2}+ (0)^{2}

= 2 x 1 x 0 + 2 x 1 x 0 + 0

= 0 + 0 + 0 = 0

(iv) In (x^{2} + xy + 5) put x = 1 and y = 0

x^{2} + xy + 5 = (1)^{2} + 1 x 0 +5

= 1 + 0 + 5 = 6

We hope the RBSE Solutions for Class 7 Maths Chapter 13 Algebraic Expression Ex 13.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression Exercise 13.3, drop a comment below and we will get back to you at the earliest.

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