RBSE Solutions for Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise

RBSE Solutions for Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 13
Chapter Name	Algebraic Expression
Exercise	In Text Exercise
Number of Questions	6
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise

(Page 146)
Question
Fill the table (RBSESolutions.com) given below:

Expression	No. of terms	Terms	Factores of terms	variable	constant
3x2 + 6xy +7y2	3	3x2,6xy,7y2	3x2 = 3 × x × x	x,y	3,6,7
			6xy = 2 × 3 × x × y
			7y2 = 7 × y × y
a2 – b2	2
8p2 – 3p + 7

Solution:

Expression	No. of terms	Terms	Factores of terms	variable	constant
a2 – b2	2	a2, -b2	a2 = a × a, -b2 = -b × b	a,b	1,-1
8p2 – 3p + 7	3	8p2, -3p, 7	8p2 = 2 × 2 × 2 x p × p	p	8,-3,7
			-3p = -3 × p

(Page 147)
Question 1
Match the coefficients in the (RBSESolutions.com) following expression 4x²y² – 3xy + 15 .

Coefficient of x2y2	x2
Coefficient of xy	-3y
Coefficient of x2	-y
Coefficient of 4y2	-3
Coefficient of x	4y2
Coefficient of 3x	4

Solution:
Correct matching (RBSESolutions.com) as follows :

Coefficient x2y2	4
Coefficient xy	-3
Coefficient x2	4y²
Coefficient 4y2	x²
Coefficient x	-3y
Coefficient 3x	-y

(Page No. 147)
Question
Select the like terms (RBSESolutions.com) in the following :
3pq, -5p, 6q + 5, -8pq, p² + q, qp
Solution:
3pq, – 8pq and qp are like terms in these there is no effects on multiplication pq = qp therefore these are like terms where as – 5p, 6p+ 5 and p² + q, are unlike terms.

(Page 148)
Question 1:
Write in appropriate box by selecting (RBSESolutions.com) monomial, binomial and trinomial expression front the following:

Solution:

(Page 149)
Question 2
Match the (RBSESolutions.com) like terms.

Solution:
Correct matching (RBSESolutions.com) is as follows.

(Page 150)
Question
Addition and subraction (RBSESolutions.com) of algebraic expressions
(i) m – n and m + n
(2) mn – 5 + 2n and nm + 2m – 3
(3) \(\frac { xy }{ 5 }\) + \(\frac { x }{ 3 }\) and \(\frac { xy }{ 2 }\) – \(\frac { x }{ 3 }\)
Solution:
(1) (m – n) + (m + n) = m – n + m +n
= 2m + 0n
= 2m + 0 = 2m
and (m – n) – (m + n) = m – n – m – n
m – m – n – n = (1 – 1)m + (-1 – 1)n
= 0m + (-2)n
= 0 – 2n = -2n

(2) (mn – 5 + 2n) + (nm + 2m – 3)
= mn – 5+ 2n + nm + 2m – 3
= mn + mn + 2m + 2n – 5 – 3
= 2mn + 2(m + n) – 8
and (mn – 5 + 2n) – (nm + 2m – 3)
= mn – 5 + 2n – nm – 2m + 3
= mn – mn + 2n – 2m – 5+ 3
= 0(mn) + 2(n – m) – 2
= 0 + 2(n – m) – 2
= 2(n – m) – 2
= 2(n – m – 1)

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