RBSE Solutions for Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 13 |

Chapter Name |
Algebraic Expression |

Exercise |
In Text Exercise |

Number of Questions |
6 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 13 Algebraic Expression In Text Exercise

**(Page 146)**

Question

Fill the table (RBSESolutions.com) given below:

Expression |
No. of terms |
Terms |
Factores of terms |
variable |
constant |

3x^{2} + 6xy +7y^{2} |
3 | 3x^{2},6xy,7y^{2} |
3x^{2} = 3 × x × x |
x,y | 3,6,7 |

6xy = 2 × 3 × x × y | |||||

7y^{2} = 7 × y × y |
|||||

a^{2} – b^{2} |
2 | ||||

8p^{2} – 3p + 7 |

Solution:

Expression |
No. of terms |
Terms |
Factores of terms |
variable |
constant |

a^{2} – b^{2} |
2 | a^{2}, -b^{2} |
a^{2} = a × a, -b^{2} = -b × b |
a,b | 1,-1 |

8p^{2} – 3p + 7 |
3 | 8p^{2}, -3p, 7 |
8p^{2 }= 2 × 2 × 2 x p × p |
p | 8,-3,7 |

-3p = -3 × p |

**(Page 147)**

Question 1

Match the coefficients in the (RBSESolutions.com) following expression 4x^{2}y^{2} – 3xy + 15 .

Coefficient of x^{2}y^{2} |
x^{2} |

Coefficient of xy | -3y |

Coefficient of x^{2} |
-y |

Coefficient of 4y^{2} |
-3 |

Coefficient of x | 4y^{2} |

Coefficient of 3x | 4 |

Solution:

Correct matching (RBSESolutions.com) as follows :

Coefficient x^{2}y^{2} |
4 |

Coefficient xy | -3 |

Coefficient x^{2} |
4y² |

Coefficient 4y^{2} |
x² |

Coefficient x | -3y |

Coefficient 3x | -y |

**(Page No. 147)**

Question

Select the like terms (RBSESolutions.com) in the following :

3pq, -5p, 6q + 5, -8pq, p^{2} + q, qp

Solution:

3pq, – 8pq and qp are like terms in these there is no effects on multiplication pq = qp therefore these are like terms where as – 5p, 6p+ 5 and p^{2} + q, are unlike terms.

**(Page 148)**

Question 1:

Write in appropriate box by selecting (RBSESolutions.com) monomial, binomial and trinomial expression front the following:

Solution:

**(Page 149)**

Question 2

Match the (RBSESolutions.com) like terms.

Solution:

Correct matching (RBSESolutions.com) is as follows.

**(Page 150)**

Question

Addition and subraction (RBSESolutions.com) of algebraic expressions

(i) m – n and m + n

(2) mn – 5 + 2n and nm + 2m – 3

(3) \(\frac { xy }{ 5 }\) + \(\frac { x }{ 3 }\) and \(\frac { xy }{ 2 }\) – \(\frac { x }{ 3 }\)

Solution:

(1) (m – n) + (m + n) = m – n + m +n

= 2m + 0n

= 2m + 0 = 2m

and (m – n) – (m + n) = m – n – m – n

m – m – n – n = (1 – 1)m + (-1 – 1)n

= 0m + (-2)n

= 0 – 2n = -2n

(2) (mn – 5 + 2n) + (nm + 2m – 3)

= mn – 5+ 2n + nm + 2m – 3

= mn + mn + 2m + 2n – 5 – 3

= 2mn + 2(m + n) – 8

and (mn – 5 + 2n) – (nm + 2m – 3)

= mn – 5 + 2n – nm – 2m + 3

= mn – mn + 2n – 2m – 5+ 3

= 0(mn) + 2(n – m) – 2

= 0 + 2(n – m) – 2

= 2(n – m) – 2

= 2(n – m – 1)

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