RBSE Solutions for Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
सरल समीकरण |

Exercise |
In Text Exercise |

Number of Questions |
2 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 14 सरल समीकरण In Text Exercise

**करो और सीखो**

**(पृष्ठ 155)**

प्रश्न 1

रिक्त स्थानों की पूर्ति कीजिए।

**तुला विधि**

7x + 6 = 34

7x + 6 – …… = 34 – …….

7x = …..

x = …….

**पक्षांतरण विधि**

7x + 6 = 34

7x = 34 -….

x = \(\frac { ……… }{ 7 }\)

x = 4

उत्तर की जाँच

LHS = 7x +6

= 7 x ….. + 6

= …… + 6 = RHS

हल:

**तुला विधि**

7x + 6 = 34

7x + 6 – 6 = 34 – 6

7x = 28

x = 4

**पक्षांतरण विधि**

7x + 6 = 34

7x = 34 – 6

x = \(\frac { 28 }{ 7 }\)

x = 4

उत्तर की जाँच

LHS = 7x + 6

= 7 x 4 + 6

= 28 + 6 = 34 = RHS

प्रश्न 2

सही/गलत बताइए।

(i) 4x +x – 13 = 7 में x = 4 सही/गलत

(ii) 3x – 8 = 25 में x = 12 सही/गलत

(iii) 7x – 5 = 3x +7 में x=3 सी/गलत

(iv) 5x – 7 = 4+1 में r = 5 सही/गलत

हल:

(i) 4x + x – 13 = 7 में x = 4 रखने पर

L.H.S. = 4x + x – 13 = 5x – 13

= 5 x 4 – 13

= 20 – 13 = 7 = RHS

अत: 4x + x -13 = 7 में x = 4 सही है।

(ii) 3x – 8 = 25 में x = 12

LHS = 3 – 8

= 3 x 12 – 8

= 36 – 8 = 28 ≠ RHS

अतः 3x – 8 = 25 में x = 12 गलत है।

(iii) 7x – 5 = 3x +7 में x = 3 रखने पर

7x – 5 = 3x +7

7 x 3 – 5 = 3 x 3 + 7

21 – 5 = 9 + 7

16 = 16

LHS = RHS

अत: 7x – 5 = 3x +7 में x = 3 सही है।

(iv) 5x – 7 = 4x +1 में x = 5

LHS व RHS में x= 5 रखने पर

5 x 5 – 7 = 4 x 5 + 1

25 – 7 = 20 + 1

18 ≠ 21

LHS ≠ RHS

अत: 5x – 7 = 4x + 1 में x = 5 गलत है।

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