RBSE Solutions for Class 7 Maths Chapter 17 Data Handling In Text Exercise

RBSE Solutions for Class 7 Maths Chapter 17 Data Handling In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 17 Data Handling In Text Exercise.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 17
Chapter Name	Data Handling
Exercise	In Text Exercise
Number of Questions	9
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 17 Data Handling In Text Exercise

Do and Learn

(Page 198)
Question 1
The marks of the subjects Mathematics and Science of five students (RBSESolutions.com) of class 7 are given in the table. Exhibit these by the vertical double bar graph.

Student name	Maths	Science
Aarti	65	75
Varsha	70	75
Simran	55	70
Radha	75	80
Jyothi	50	60

Solution:
Double bar graph  Maths, Science scale : 1 unit = 10 marks

Question 2
The details of different expenditures occurring in (RBSESolutions.com) one month of two families are shown in the table. Make a double bar graph on the basis of this table and answer the following questions.

Expenditure heads	Family – 1	Family – 2
House rent	2000	2500
Electricity,water,telephone	800	600
Food Items	8000	7000
Children Education	2000	3000
Saving	2200	1900

(i) Under which head the expenditure is maximum?
(ii) Under which head the expenditure is mini mum?
(iii) If monthly income of both the families is ₹15000 then what (RBSESolutions.com) percentage of expenditure is used on children education in both the families?
Solution:
Double bar graph  = Family – 1
= Family – 2, Scale 1 unit = ₹1000

(i) On food items family-1 spend ₹8000 and family – 2 spend ₹7000,
So expenditure is maximum (RBSESolutions.com) on food items
(ii) On electricity, water and telephone family-1 spend ₹800 and family-2 spend ₹600, which is minimum.
(iii) Monthly income of both families = ₹15000
Family-1 expenditure on education in percentage.
= \(\frac { 2000\times 100 }{ 15000 }\)
= 13.33%
Family-2 expenditure on education in percentage
= \(\frac { 3000\times 100 }{ 15000 }\)
= 20%

(Page 201)
Question 1
Determine the weight of students of your class by (RBSESolutions.com) weighing machine. Tabulate these by arranging data. Write these data in ascending or descending order. Then answer the following questions :
(1) The weight of which student is maximum in the class?
(2) How many students have weight more than 25 kg in the class?
(3) How many students have weight in between 20 to 30 kg?
Solution:
Solution of this questions will have to be done by the student rather than an other example is giving here for the convenience to the students.
Weight of students are as follows :
23, 18, 22, 25, 24. 28, 30, 27, 32, 25
Table

Student	Weight in kg	Student	Weight in kg
Vijay	23	Devi	28
Sarika	18	Sunita	30
Saritha	22	Anil	27
Ramesh	25	Subhash	32
Suresh	24	Ajay	25

Arranging the observations (RBSESolutions.com) in ascending order
18, 22, 23, 24, 25, 25, 27, 28, 30, 32
(1) Subhash has more weight.
(2) Four students weight is more than 25 kg.
(3) Eight students weight is in between 20 to 30 kg.

(Page 203)
Question 1
Find the mean heights of your family members.
Solution:
Solution of this questions will have to be done by the (RBSESolutions.com) student rather than an other example is giving here for the convenience ot the students.
My family members height are as follows in cm 70, 85, 110, 150, 170
Airthmetic mean
= \(\frac { 70+85+110+150+170 }{ 5 } =\quad \frac { 858 }{ 5 } =\quad 117\) cm.

Question 2
Find the mean age of your family members.
Solution:
Solution ofthis questions will have to be done by the (RBSESolutions.com) student rather than an other example is giving here for the convenience ot the students.
My family members ages are as follows 7, 9.5, 10, 25.5, 28
Mean = \(\frac {7 + 9.5 + 10 + 25.5 + 28 }{ 5 } =\quad \frac { 80 }{ 5 } =\quad 16\) years

(Page 205)
Question 1
40 students of class 7 wrote their number of family members together. This number is shown below :
4, 3, 5, 4, 7, 3, 5, 6, 4, 4, 4, 7, 6, 4, 5, 4, 3, 4, 5,
6, 7, 4, 4, 5, 3, 4, 6, 4, 5, 5, 4, 3, 4, 7, 6, 4, 3, 5, 4,
Find out the mode of these observations.
Solution:
Arranging these (RBSESolutions.com) observations in ascending orders.
3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4,
4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 7, 7, 7, 7
In the given observations 4 occuss more times, therefore mode is 4.

Question 2
Find mode of following data :
21, 22, 25, 24, 22, 23, 23, 24, 25, 24, 22, 24, 23, 24, 23, 24, 22,21,25, 23
Solution:
Arranging these (RBSESolutions.com) observations in ascending orders
21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 23, 24. 24, 24, 24, 24, 24, 25, 25, 25
by observing the number 24 is repeated more so mode of this is 24.

(Page 207)
Question 1
The data arranged in ascending order are as follows :
8, 11, 12, 16, 16 + x, 20, 25, 30 If median is 18 then Find x.
Solution:
8, 11, 12, 16, 16 + x, 20, 25, 30 median is 18.
The given (RBSESolutions.com) observations is even (n = 8)

Question 2
Jyoti scored the following marks (out of 10) in (RBSESolutions.com) different subjects 5, 7, 0, 3, 5, 8.
Jyoti calculated mean, median and mode from the remaining numbers ignoring 0. Did she do it correctly?
Solution:
Jyoti has not done correct because we have to take all observations.

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