RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.3.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 2
Chapter Name	Fractions and Decimal Numbers
Exercise	Ex 2.3
Number of Questions	6
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.3

Question 1
Find:

Solution:

Question 2
Find the reciprocal (RBSESolutions.com) of the following:

Solution:

Question 3
Find :

Solution:

Question 4
Find :

Solution:

Question 5
What will be number of \(\frac { 1 }{ 4 }\) parts of bread if each of 6 breads is (RBSESolutions.com) divided into equal parts of \(\frac { 1 }{ 4 }\)?
Solution:
Total breads = 6, each bread is to be divided in \(\frac { 1 }{ 4 }\)th part
∴ Nurnber of \(\frac { 1 }{ 4 }\) parts = 6 ÷ \(\frac { 1 }{ 4 }\) = 24 parts.

Question 6
How many \(\frac { 1 }{ 2 }\)cm log (RBSESolutions.com) pieces can be cut of 11 \(\frac { 1 }{ 2 }\) long ribon?
Solution:
Length of ribon = 11\(\frac { 1 }{ 2 }\) cm = \(\frac { 23 }{ 2 }\) cm
∴ Number of pieces to be cut = \(\frac { 23 }{ 2 }\) ÷ \(\frac { 1 }{ 2 }\)
=\(\frac { 23 }{ 2 }\) x \(\frac { 2 }{ 1 }\) = \(\frac { 23\times 1 }{ 1\times 1 }\) pieces

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