RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.5

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.5 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.5.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 2
Chapter Name	Fractions and Decimal Numbers
Exercise	Ex 2.5
Number of Questions	8
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.5

Question 1
Find :
(i) 7 x 5.4
(ii) 80.1 x 2
(iii) 0.08 x 5
(iv) 3 x 0.86
(v) 312.05 x 4
(vi) 6.08 x 8
Solution:

Question 2
Find:
(i) 3.72 x 10
(ii) 0.37.x 10
(ii) 0.5 x 10
(iv) 1.08 x 100
(v) 73.8 x 10
(vi) 0.06 x 100
(vii) 47.03 x 1000
(viii) 0.03 x 1000
(ix) 42.7 x 1000
Solution:
(i) 3.72 x 10 = 37.2
(ii) 0.37 x 10 = 3.7
(iii) 0.5 x 10 = 5
(iv) 1.08 x 100 = 108
(v) 73.8 x 10 = 738
(vi) 0.06 x 100 = 6
(vii) 47.03 x 1000 = 47030
(viii) 0.03 x 1000 = 30
(ix) 42.7 x 1000 = 42700

Question 3
Find:
(i) 4.2 x 3.5
(ii) 6.25 x 0.5
(iii) 1.2 x 0.15
(iv) 0.08 x 0.5
(v) 101.01 x 0.01
(vi) 20.05 x 4.8
Solution:
(i) 4.2 x 3.5

(ii) 6.25 x 0.5

Hence 6.25 x 0.5 = 3.125

Place the decimal (RBSESolutions.com) point in product so decimal point is put from right side = 1 + 1 = 2
So 4.2 x 3.5 = 14.70
= 14.7

(iii) 1.2 x 0.15

so, 11.2 x 0.15 = 1.68

(iv) 0.08 x 0.5

Hence 0.08 x 0.5 = 0.040 = 0.04

(v) 101.01 x 0.01

so, 101.01 x 0.01 = 1.0101

(vi) 20.05 x 4.8

Hence, 20.05 x 4.8 = 96.240
= 96.24

Question 4
Find the area of a rectangle (RBSESolutions.com) whose length is 6.4 cm and breadth is 3.2 cm?
Solution:
Length of rectangle = 6.4 cm
breadth of rectangle = 3.2 cm
Area of rectangle 6.4 x 3.2 = 20.48 cm²

Question 5
A car moves 25.17 km in 1 litre petrol. Find (RBSESolutions.com) how many distance will it cover in 10.5 litre petrol?
Solution:
Distanc covered by car in 11 petrol
= 25.17km
∵ distance covered in 10.5 litre
= 25.17 x 10.5
= 264.285 km

Question 6
Prakash sells 2.500 kg of ghee to Raju (RBSESolutions.com) every month. How much ghee Prakash would have sold to Raju in 10 months?
Solution:
∵ Quantity of gbee sold by Raju in one month = 2.500 kg
∴ Quantity sold in 10 months
= 10 x 2.500 kg
= 25.00kg

Question 7
Aside of an equibteral (RBSESolutions.com) triangles is 4.5 cm. Find its perimeter.
Solution:
Length of one side of equilateral triangle = 4.5 cm
∴ Perimeter = 3 x length of one side
= 3 x 4.5 = 13.5 cm.

Question 8
Dipika buys a box of tomatoes at the wholesale rate of ₹ 16.50 per kg from the vegetable market. If the tomatoes weigh 22.5kg then how much money (RBSESolutions.com) will Dipika pay to the wholeseller.
Solution:
∵ Price of 1 kg tomato = ₹16.50
∴ Price of 22.5 kg tomato = 6.50 x 22.5
= ₹371.25

We hope the RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.5 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.5, drop a comment below and we will get back to you at the earliest.