RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.6

RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.6 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.6.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 2
Chapter Name	Fractions and Decimal Numbers
Exercise	Ex 2.6
Number of Questions	8
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.6

Question 1
Find:
(i) 0.8 ÷ 4
(ii) 0.42 ÷ 7
(ii) 3.96 ÷ 6
(iv) 842.4 ÷ 4
(v) 14.49 ÷ 7
(vi) 36 ÷ 0.2
(vi) 7 ÷ 3.5
(viii) 0.09 ÷ 3
Solution:

Question 2
Find:
(i) 4.2 ÷ 10
(ii) 98.6 ÷ 10
(iii) 0.2 ÷ 10
(iv) 143.2 ÷ 100
(v) 86 ÷ 100
(vi) 8.05 ÷ 100
(vii) 44.32 ÷ 100
(viii) 1.3 ÷ 1000
(ix) 0.06 ÷ 1000
Solution:
(i) 4.2 ÷ 10 = 0.42
(ii) 98.6 ÷ 10 = 9.86
(iii) 02 ÷ 10 = 0.02
(iv) 143.2 ÷ 100 = 1.432
(v) 86 ÷ 100 = 0.86
(vi) 8.05 ÷ 100 = 0.0805
(vii) 44.32 ÷ 100 = 0.4432
(viii) 1.3 ÷ 1000 = 0.0013
(ix) 0.06 ÷ 1000 = 0.00006

Question 3
(i) 1.2 ÷ 0.3
(ii) 3.64 ÷ 0.4
(iii) 9.6 ÷ 1.6
(iv) 1.25 ÷ 2.5
(v) 30.75 ÷ 1.5
(vi) 4.08 ÷ 1.2
(vii) 30.94 ÷ 0.7
(viii) 76.5 ÷ 0.15
(ix) 7.75 ÷ 0.25
Solution:

Question 4
A scooter covers a (RBSESolutions.com) distance of 212.5 km in 5 litres of petroL How much distance will It cover In one litre of petrol?
Solution:
∵ In 5 litre of petrol scooter covers = 212.5 km
∴ In 1 litre of petrol, it will cover = 212.5 ÷ 5

Question 5
Distance of the house of Gopal, Narayan and Krishna (RBSESolutions.com) from school are 1.5 km, 0.7 km and 1.4 km respectively. Find the average of all distancts.

Solution:
Distance of houses of Gopal, Narayan and
Krishna are 1.5 km, 0.7 km and 1.4 km

Question 6
A car travels 891 km distance within 2.2 hours. Find (RBSESolutions.com) the distance covered by car in 1 hour.
Solution:
∵ In 2.2 hours, car travelled distance = 89.1 km

Question 7
Find the area of the square (RBSESolutions.com) whose perimeter is 44.08 m.
Solution:
Perimeter of square = 44.08 m

= 11.02 m
∴ Area of square = side x side
= 11.02 x 11.02= 121.4404 sq m.

Question 8
If the area of a rectangle is 93.6 m and the (RBSESolutions.com) width is 3.6 m, then find the perimeter of the rectangle.
Solution:
Area of rectangle = 93.6 m²
breadth = 3.6 m
Area of rectangle = l x b
⇒ 93.6 = l x 3.6
∴ l = 93.6 ÷ 3.6 = \(\frac { 936 }{ 10 }\) ÷ \(\frac { 36 }{ 10 }\)
= \(\frac { 936 }{ 10 }\) x \(\frac { 10 }{ 36 }\) = \(\frac { 936 }{ 36 }\) = 26 m
Perimeter of (RBSESolutions.com) rectangle 2(l + b)
= 2 (26 + 3.6)
= 2 x 29.6
= 59.2 m

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