RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.6 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.6.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 2 |

Chapter Name |
Fractions and Decimal Numbers |

Exercise |
Ex 2.6 |

Number of Questions |
8 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.6

Question 1

Find:

(i) 0.8 ÷ 4

(ii) 0.42 ÷ 7

(ii) 3.96 ÷ 6

(iv) 842.4 ÷ 4

(v) 14.49 ÷ 7

(vi) 36 ÷ 0.2

(vi) 7 ÷ 3.5

(viii) 0.09 ÷ 3

Solution:

Question 2

Find:

(i) 4.2 ÷ 10

(ii) 98.6 ÷ 10

(iii) 0.2 ÷ 10

(iv) 143.2 ÷ 100

(v) 86 ÷ 100

(vi) 8.05 ÷ 100

(vii) 44.32 ÷ 100

(viii) 1.3 ÷ 1000

(ix) 0.06 ÷ 1000

Solution:

(i) 4.2 ÷ 10 = 0.42

(ii) 98.6 ÷ 10 = 9.86

(iii) 02 ÷ 10 = 0.02

(iv) 143.2 ÷ 100 = 1.432

(v) 86 ÷ 100 = 0.86

(vi) 8.05 ÷ 100 = 0.0805

(vii) 44.32 ÷ 100 = 0.4432

(viii) 1.3 ÷ 1000 = 0.0013

(ix) 0.06 ÷ 1000 = 0.00006

Question 3

(i) 1.2 ÷ 0.3

(ii) 3.64 ÷ 0.4

(iii) 9.6 ÷ 1.6

(iv) 1.25 ÷ 2.5

(v) 30.75 ÷ 1.5

(vi) 4.08 ÷ 1.2

(vii) 30.94 ÷ 0.7

(viii) 76.5 ÷ 0.15

(ix) 7.75 ÷ 0.25

Solution:

Question 4

A scooter covers a (RBSESolutions.com) distance of 212.5 km in 5 litres of petroL How much distance will It cover In one litre of petrol?

Solution:

∵ In 5 litre of petrol scooter covers = 212.5 km

∴ In 1 litre of petrol, it will cover = 212.5 ÷ 5

Question 5

Distance of the house of Gopal, Narayan and Krishna (RBSESolutions.com) from school are 1.5 km, 0.7 km and 1.4 km respectively. Find the average of all distancts.

Solution:

Distance of houses of Gopal, Narayan and

Krishna are 1.5 km, 0.7 km and 1.4 km

Question 6

A car travels 891 km distance within 2.2 hours. Find (RBSESolutions.com) the distance covered by car in 1 hour.

Solution:

∵ In 2.2 hours, car travelled distance = 89.1 km

Question 7

Find the area of the square (RBSESolutions.com) whose perimeter is 44.08 m.

Solution:

Perimeter of square = 44.08 m

= 11.02 m

∴ Area of square = side x side

= 11.02 x 11.02= 121.4404 sq m.

Question 8

If the area of a rectangle is 93.6 m and the (RBSESolutions.com) width is 3.6 m, then find the perimeter of the rectangle.

Solution:

Area of rectangle = 93.6 m^{2}

breadth = 3.6 m

Area of rectangle = l x b

⇒ 93.6 = l x 3.6

∴ l = 93.6 ÷ 3.6 = [latex]\frac { 936 }{ 10 }[/latex] ÷ [latex]\frac { 36 }{ 10 }[/latex]

= [latex]\frac { 936 }{ 10 }[/latex] x [latex]\frac { 10 }{ 36 }[/latex] = [latex]\frac { 936 }{ 36 }[/latex] = 26 m

Perimeter of (RBSESolutions.com) rectangle 2(l + b)

= 2 (26 + 3.6)

= 2 x 29.6

= 59.2 m

We hope the RBSE Solutions for Class 7 Maths Chapter 2 Fractions and Decimal Numbers Ex 2.6 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 2 Fractions and Decimal Numbers Exercise 2.6, drop a comment below and we will get back to you at the earliest.

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