RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 4 Rational Numbers Exercise 4.1.
Board | RBSE |
Textbook | SIERT, Rajasthan |
Class | Class 7 |
Subject | Maths |
Chapter | Chapter 4 |
Chapter Name | Rational Numbers |
Exercise | Ex 4.1 |
Number of Questions | 10 |
Category | RBSE Solutions |
Rajasthan Board RBSE Class 7 Maths Chapter 4 Rational Numbers Ex 4.1
Welcome to our step-by-step math rational expressions calculator.
Question 1
Write five rational numbers equivalent to (RBSESolutions.com) the following ratinal numbers
Solution:
(i) Five equivalent rational numbers of –\(\frac { 2 }{ 3 }\) are
(ii) Five equivalent rational (RBSESolutions.com) numbers of \(\frac { 1 }{ 5 }\) are
(iii) Five equivalent rational (RBSESolutions.com) numbers of \(\frac { -5 }{ 3 }\) are
(iv) Five equivalent rational (RBSESolutions.com) numbers of \(\frac { 4 }{ -9 }\) are
.
Question 2
Write three such (RBSESolutions.com) rational numbers equivalent to \(\frac { -5 }{ 12 }\) in which the denominator is 60, – 96 and 108.
Solution:
Question 3
Write three such rational (RBSESolutions.com) numbers equivalent to \(\frac { -3 }{ 7 }\) in which the numerator is 24, – 60 and 75.
Solution:
Question 4
Write the following rational numbers in the (RBSESolutions.com) simplest from (standard forms) :
Solution:
Question 5
Represent the following rational numbers (RBSESolutions.com) on number line :
Solution:
(i) We know that \(\frac { 3 }{ 5 }\) is greater than 0, so \(\frac { 3 }{ 5 }\) will be in between 0 and 1.
Now to represent \(\frac { 3 }{ 5 }\) on number line, the distance between 0 and S is divided in 5 equal parts and take three parts from it to mark point P. This way point P represents point \(\frac { 3 }{ 5 }\) .
(ii) We know (RBSESolutions.com) that \(\frac { 7 }{ 8 }\) is greater than 0 and less than 1.
∴ \(\frac { 7 }{ 8 }\) will be in between 0 and 1.
Now to represent \(\frac { 7 }{ 8 }\) on number line, distance between 0 and 1 is divided in 8 equal parts and take 7 parts from it to mark point P. Thus point P represent point \(\frac { 7 }{ 8 }\).
(iii) We know that \(\frac { -8 }{ 3 }\) or -2\(\frac { 2 }{ 3 }\), is greater than -3 and less than – 2 so \(\frac { -8 }{ 3 }\), will be in between -2 and – 3.
Now on number line, the (RBSESolutions.com) distance between – 2 and – 3 divided in 3 equal parts and take 2 parts from it to mark point P. This way point P represents point \(\frac { -8 }{ 3 }\).
(iv) We know that -2\(\frac { 1 }{ 2 }\) or \(\frac { -5 }{ 2 }\), is greater from – 3 and less than – 2 so \(\frac { -5 }{ 2 }\) will be in between – 2 and -3.
Now to represent \(\frac { -5 }{ 2 }\) on number line, the distance between -2 and -3 is divided in 2 equal parts and take one part from it to mark point P.
This way point P represent (RBSESolutions.com) the point –\(\frac { 5 }{ 2 }\) ( -2\(\frac { 1 }{ 2 }\)) or number line.
(v) We know that \(\frac { 5 }{ 7 }\) is greater than 0 and less than 1.
\(\frac { 5 }{ 7 }\), will be in between 1 and 1.
Now to represent \(\frac { 5 }{ 7 }\) on number line, the distance between 0 and 1 is divided in 7 equal parts and take 5 parts to make point P. This way point P
represents \(\frac { 5 }{ 7 }\) on number line.
Question 6
Choose the correct (RBSESolutions.com) sign from <, >, = and fill in the blanks :
Solution:
(i) We know that positive rational numbers are greater than negative rational numbers
(ii) L.C.M. of (RBSESolutions.com) denominator 4 and 3 is 12
(iii) L.C.M. of (RBSESolutions.com) denominator – 5 and 3 is 15
(iv) L.C.M. of 7 and 2 is 14
(vi) We know that negative rational (RBSESolutions.com) numbers are smaller than positive rational number.
Question 7
Write five rational numbers between fol-lowing rational numbers :
Solution:
We know that integers (RBSESolutions.com) between -9 and -3 are
⇒ -8 < -7 < -6 < -5 < -4
∴ Five rational numbers between – 9 and – 3 will be:
We know that integers (RBSESolutions.com) between 0 and -6 are
∴ Five rational numbers between 0 and -1
∴ Five rational numbers (RBSESolutions.com) between -56 and – 50 are
We know that integers between 12 and 6 are :
∴ Five rational (RBSESolutions.com) numbers between \(\frac { 1 }{ 2 }\) and \(\frac { 1 }{ 4 }\) are
(v) We know that integers between 2 and -4 are:
-4 < -3 < -2 < -1 < 0 < 1 < 2
∴ Five rational numbers between \(\frac { 2 }{ 5 }\) and \(\frac { -4 }{ 5 }\) will be
Question 8
Write three more rational (RBSESolutions.com) numbers in each of the following :
Solution:
Question 9
Write the (RBSESolutions.com) following rational number in increasing order :
Solution:
(i) ∵ Denominators of given rational numbers are positive.
∴ L.C.M of 2, 2, 4 and 4 = 4 on making denominator of each = 4
∵ Denominators of (RBSESolutions.com) rational numbers are positive
∴ L.C.M. of 2, 4 and 7 = 28 on making the denominator of each = 28
∴ Increasing order is
∵ Denominator of rational (RBSESolutions.com) numbers are positive.
∴ L.C.M of 11, 15, 1, 1 and 15 = 165
on making denominator of each = 165
∵ Denominator of rational number are positive
∴ L.C.M of 5, 7, 6, 9 = 630 on making (RBSESolutions.com) denominator of each = 165
Question 10
Write the following rational (RBSESolutions.com) numbers is decreasing order :
Solution:
on making (RBSESolutions.com) the denominator 48 of each
∵ Denominator of rational number (RBSESolutions.com) are positive
∴ L.C.M of 6, 6, 9, 12 = 36
on making denominator 36 of each
on making (RBSESolutions.com) denominator 6 of each
on making (RBSESolutions.com) denominator 30 of each
We hope the RBSE Solutions for Class 7 Maths Chapter 4 Rational Numbers Ex 4.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 4 Rational Numbers Exercise 4.1, drop a comment below and we will get back to you at the earliest.
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