RBSE Solutions for Class 7 Maths Chapter 5 Powers and Exponents Additional Questions is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Additional Questions.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 5 |

Chapter Name |
Powers and Exponents |

Exercise |
Additional Questions |

Number of Questions |
23 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Additional Questions

**Multiple Choice Questions**

Question 1

Value of 4^{2} will be :

(A) 16

(B) 15

(C) 18

(D) 4

Question 2

Number 625 is written in (RBSESolutions.com) exponential form as :

(A) 52

(B) 54

(C) 56

(D) none

Question 3

Value of (-1)^{3} will be :

(A) 1

(B) 0

(C) -1

(D) none

Question 4

Value (RBSESolutions.com) of 3^{5} : 3^{3} will be :

(A) 9

(B) 10

(C) 16

(D) 25

Question 5

Value of 3^{3} x 3^{5} x 3^{2} will be :

(A) 3^{8}

(B) 3^{10}

(C) 3^{18}

(D) 3^{0}

Question 6

Value of (3)^{5} ÷ (2)^{5} will be :

Question 7

Value (RBSESolutions.com) of (5 x 6)^{4}will be :

(A) 4^{8} x 6^{4}

(B) 5^{4} x 6^{4}

(C) 3^{4} x 2^{4}

(D) none

Answer:

1. (A), 2. (B), 3. (C), 4. (A), 5. (B), 6. (A), 7. (B)

**Fill in the blanks:**

(i) Exponential form (RBSESolutions.com) of \(\frac { 2 }{ 3 } \times\frac { 2 }{ 3 } \times\frac { 2 }{ 3 } \times\frac { 2 }{ 3 } \times\frac { 2 }{ 3 }\) will be ………

(ii) Value of (10)° will be ………

(iii) Expended form of 2^{2} x 3^{2} will be ………

Answer:

(i) (\(\frac { 2 }{ 3 }\))^{5}

(ii) 1,

(iii) 2 x 2 x 2 x 3 x 3

**True/False**

(i) Value of 2 x 3^{2} will be 18.

(ii) Value (RBSESolutions.com) of \(\frac { 2 }{ 3 } \div \frac { 2 }{ 3 }\) will be 2.

(iii) Standard form of 2500 is 2.5 x 10^{3}

(iv) The value of \(\frac { { 2 }^{ 3 }\times{ 3 }^{ 3 } }{ { 2 }^{ 3 }\times{ 3 }^{ 2 } }\) is \(\frac { 3 }{ 2 }\)

Answer:

(i) T

(ii) F

(iii) T

(iv) T

**Very Short Answer Type Questions**

Question 1

Simplify –

(i) 2 x 10^{3}

(ii) 7^{2} x 2^{2}

(iii) 2^{3} x 5

Solution:

(i) 2 x 10^{3} = 2 x 10 x 10 x 10 = 2000

(ii) 7^{2} x 2^{2} = 7 x 7 x 2 x 2 = 196

(iii) 2^{3} x 5 = 2 x 2 x 2 x 5 = 40

Question 2

Express the following (RBSESolutions.com) in exponent form

(i) 3^{2} x 3^{4} x 3^{8}

(ii) (5^{2})^{3} ÷ 5^{3}

Solution:

(i) 3^{2} x 3^{4} x 3^{8} = 3^{2 + 4 + 8} = 3^{14}

(ii) (5^{2})^{3}÷ 5^{3}= (5)^{6} ÷ 5^{3} = \(\frac { { 5 }^{ 6 } }{ { 5 }^{ 3 } }\)= 5^{6 – 3} = 5^{3}

Question 3

Expend in exponential (RBSESolutions.com) form by using the power of 10

(i) 172,

(ii) 5643

Solution:

(i) 172 = 1 x 100 +7 x 10 + 2 x 1

= 1 x 10^{2} +7 x 10^{1} + 2 x 10^{0}

(ii) 5643 = 5 x 1000 +6 x 100 +4 x 10 + 3 x 1

= 5 x 10^{3} + 6 x 10^{2} + 4 x 10^{1} + 3 x 10^{0}

**Short Answer Type Questions**

Question 1

Find the greater number (RBSESolutions.com) in the following

(i) 4^{3} or 3^{4}

(ii) 5^{3} or 3^{5}

Solution:

(i) 4^{3} = 4 x 4 x 4 = 64 and 3^{4} = 3 x 3 x 3 x 3= 81

Clearly 81 > 64

∴ 3^{4} is greater.

(ii) 5^{3} = 5 x 5 x 5 = 125

and 3^{5} = 3 x 3 x 3 x 3 x 3 = 243

Clearly 243 > 125

∴ 3^{5} is a greater.

Question 2

Express each of the following in the (RBSESolutions.com) form of powers of prime factors as product.

(i) 648

(ii) 405

Solution:

On factorizing by

∴ 648 = 2 x 2 x 2 x 3 x 3 x 3 x 3

= 2^{3 }x 3^{4}

(ii) On factorizing by division (RBSESolutions.com) method vision method

∴ 405 = 3 x 3 x 3 x 3 x 5

= 3^{4} x 5

Question 3

Write the following in (RBSESolutions.com) expended from

a^{3}b^{2}, a^{2}b^{3}, b^{2}a^{3} and b^{3}a^{2}

Solution:

a^{3}b^{2} = a^{3}x b^{2} = (a x a x a) x (b x b)

a^{2}b^{3} = a^{2} x a^{3} = (a x a ) x (b x b x b)

b^{2}a^{3} = b^{2} x a^{3} = (b x b) x (a x a x a)

b^{3}a^{2} = b^{3} x a^{2} = (b x b x b) x (a x a)

**Long Answer Type Questions**

Question 1

Simplify :

Solution:

Question 2

Express the following (RBSESolutions.com) numbers in standard form

(i) 5,00,00,000

(ii) 70,00,000

Solution:

(i) 5,00,00,000 = 5 x 10000000 = 5 x 10^{7}

(ii) 70,00,000 = 7 x 1000000 = 7 x 10^{6}

Question 3

A drop of water of 1.8 gm weight has 60,230,000,000,000,000,000,000 molecules. Express (RBSESolutions.com) it in standard form.

Solution:

Number of molecules in a dot of water of weight 1.8 gm

= 60. 230, 000, 000, 000, 000, 000, 000

= 6.023 x 1000000000000000000000

= 6.023 x 10^{22}

We hope the RBSE Solutions for Class 7 Maths Chapter 5 Powers and Exponents Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Additional Questions, drop a comment below and we will get back to you at the earliest.

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