RBSE Solutions for Class 7 Maths Chapter 5 Powers and Exponents Ex 5.3

RBSE Solutions for Class 7 Maths Chapter 5 Powers and Exponents Ex 5.3 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Exercise 5.3.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 5
Chapter Name	Powers and Exponents
Exercise	Ex 5.3
Number of Questions	5
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 5 Powers and Exponents Ex 5.3

Question 1
Write the following numbers (RBSESolutions.com) into standard form :
(i) 50,0000
(ii) 48,30,000
(iii) 3,94,00,00,00,000
(iv) 30000000
(v) 180000
Solution:
(i) 50,0000 = 5.0 x 100000 = 5.0 x 10⁵
(ii) 48,30,000 = 4.83 x 1000000 = 4.83 x 10⁶
(iii) 3,94,00,00,00,000
= 3.94 x 100000000000
= 3.94 x 10¹¹
(iv) 30000000 = 3.0 x 10000000 = 3.0 x 10⁷
(v) 180000 = 1.8 x 100000 = 1.8 x 10⁵

Question 2
Distance of the sun from the (RBSESolutions.com) earth is approximately 15,00,00,00 km. Express this distance in scientific notations.
Solution:
Distance of earth from sun = 15,00,00,000 km
∴ Scientific expression = 1.5 x 100000000 km
= 1.5 x 10⁸ km

Question 3
A person gets 3000 calorie energy from his daily meal. Represent (RBSESolutions.com) in scientific notations, how much energy he will get in one year.
Solution:
Calories received daily = 3000 calories
∴ Calories received during 365 days = 3000 x 365 calories
=1095000 calories
∴ Scientific expression = 1.095 x 10⁶ calories.

Question 4
According to an estimation, Indian railways (RBSESolutions.com) transports approximately 1 crore 30 lakhs people from one place to another daily. How many people travel by train in 30 days ? Write your answer in standard form.
Solution:
∵ Number of passengers travel in 1 day = 1 crore 30 lac = 1,30,00,000
∴ Number of passengers travels in 30 days = 30 x 1,30,00,000
= 390000000 = 3.9 x 10⁸

Question 5
Write the following in (RBSESolutions.com) simple form :
(i) 2.5 x (10)⁴
(i) 1.75 x (10)⁶
(iii) 1.21 x (10)^-8
(iv) 4.50 x (10)^-5
Solution:
(i) 2.5 x (10)⁴ = 2.5 x 10 x 10³
= 25 x 1000 = 25000

(ii) 1.75 x (10)⁶ = 1.75 x 10 x 10 x 10⁴
= 175 x 10⁴ = 175 x 10000
= 1750000

(iii) 1.21 x (10)^-8 = 1.21 x 10^-1 x 10^-7
= 0.121 x 10^-7
= 0.0000000121

(iv) 4.50 x (10)^-5 = 4.50 x 10^-1 x 10^-4
= 0.45 x 10^-4 = 0.000045

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