RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions.
Board | RBSE |
Textbook | SIERT, Rajasthan |
Class | Class 7 |
Subject | Maths |
Chapter | Chapter 6 |
Chapter Name | Vedic Mathematics |
Exercise | Additional Questions |
Number of Questions | 8 |
Category | RBSE Solutions |
Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions
Multiple Choice Questions
Question 1
The sum of 27 + 58 + 392 + 68 + 32 + 23 will be :
(a) 600
(b) 500
(c) 400
(d) 300
Question 2
The number is find on (RBSESolutions.com) subtracting 569 from 854 is :
(a) 285
(b) 284
(c) 208
(d) 289
Answer:
1. (a).
2. (a).
Fill in the blanks :
(i) Product of fractions 5\(\frac { 1 }{ 2 }\) x 6 will be
(ii) Value of 6\(\frac { 1 }{ 4 }\) x 6\(\frac { 3 }{ 4 }\) is
(iii) Value of 3\(\frac { 3 }{ 4 }\) – 3\(\frac { 2 }{ 5 }\) is
Answer:
(i) 33
(ii) 42\(\frac { 3 }{ 16 }\)
(iii) \(\frac { 7 }{ 20 }\)
Short Answer Type Questions
Question 1
Find the (RBSESolutions.com) sum of
45 + 67 + 38 + 55 + 62 + 33
Solution:
(45 + 55) + (67 + 33) + (38 + 62) = 100 + 100 + 100 = 300
Question 2
Multiply 81 with 11.
Solution:
Question 3
Find the greater fractions (RBSESolutions.com) in \(\frac { 3 }{ 4 }\) व \(\frac { 4 }{ 5 }\)
Solution:
(i) Write numerator and denominator of fractions
(ii) 3 x 5 = 15 and 4 x 4 = 15
\(\frac { 3 }{ 4 }\) < \(\frac { 4 }{ 5 }\)
Question 4
Solve:
3\(\frac { 3 }{ 4 }\) – 3\(\frac { 2 }{ 5 }\)
Solution:
Question 5
Multiply :
7\(\frac { 1 }{ 2 }\) and 8\(\frac { 1 }{ 2 }\)
Solution:
We hope the RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics Additional Questions, drop a comment below and we will get back to you at the earliest.
Leave a Reply