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RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise

March 23, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 7
Subject Maths
Chapter Chapter 6
Chapter Name Vedic Mathematics
Exercise In Text Exercise
Number of Questions 6
Category RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise

(Page 74)
Question
Multiply 99 by 11.
RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise
(in the number 18, 8 will remain at tens (RBSESolutions.com) place and I will be added to the number at hundreds place)
Could we apply this rule in case of three digit numbers ? Discuss and practice such problems.
Solution:
Yes. this rule is applicable for three or more than three digit numbers.
RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise
Students can (RBSESolutions.com) practice such more questions

RBSE Solutions

Do and Learn

(Page 74)
Question 1
If a number is multiplied with 100 and 1000 then what change do you observe in the product ? Discuss with your friends.
Solution:
If on multiplying a number with 100,0 takes unit or tens place and original number shifted from unit or tens place ahead on multiplying with 1000,0 takes unit, tens or hundredth place and original number shifted to ahead from unit, tens or hundredth place.

Question 2
Divide the class into (RBSESolutions.com) two groups. One group should ask the question of multiplying the numbers by 10, 100 and 1000 and another group should answer and vice-versa. Play it like “ANTYAKSHARI”.
Solution:
Student should take help of their teacher to act.

(Page 72)
Question 1
Can we use the method of (RBSESolutions.com) multiplication by 5 in the case of 50 and 500?
Solution:
Yes,
(i) 50 x 5 = 50 x \(\frac { 10 }{ 2 }\) = \(\frac { 50 }{ 2 }\) x 10
= 25 x 10 = 250
(ii) 500 x 5 = 500 x \(\frac { 10 }{ 2 }\) = \(\frac { 500 }{ 2 }\) x 10
= 250 x 10 = 2500

Question 2
Can we multiply (RBSESolutions.com) a number by 25 in the 100 form of \(\frac { 100 }{ 4 }\)discuss in your class.
Solution:
yes, 25 = \(\frac { 100 }{ 4 }\) can be expressed.

(Page 74)
Question
Multiply any number by 999 and 9999 yourself and ask your teacher in case of any problem.
Solution:
Let the (RBSESolutions.com) number is 18
RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise

RBSE Solutions

We hope the RBSE Solutions for Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 7 Maths Chapter 6 Vedic Mathematics In Text Exercise, drop a comment below and we will get back to you at the earliest.

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