RBSE Solutions for Class 7 Maths Chapter 7 Lines and Angles Ex 7.1

RBSE Solutions for Class 7 Maths Chapter 7 Lines and Angles Ex 7.1 is part of RBSE Solutions for Class 7 Maths. Here we have given Rajasthan Board RBSE Class 7 Maths Chapter 7 Lines and Angles Exercise 7.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 7
Subject	Maths
Chapter	Chapter 7
Chapter Name	Lines and Angles
Exercise	Ex 7.1
Number of Questions	8
Category	RBSE Solutions

Rajasthan Board RBSE Class 7 Maths Chapter 7 Lines and Angles Ex 7.1

Question 1
Seprate out (Filter out) the (RBSESolutions.com) supplementary and complementary angles from the following pairs of angles :
(i) 140°, 40°
(ii) 170°, 10°
(iii) 75°, 15°
(iv) 33°, 57°
(v) 115°, 65°
(vi) 25°, 65°
Solution:
(i) 140°, 40°
Sum of angles = 140° + 40° = 180°
∴ These are (RBSESolutions.com) supplementary angles.

(ii) 170°, 10°
Sum of angles = 170° + 10° = 180°
∴ These are supplementary angles.

(iii) 75°, 15°
Sum of angles = 75° + 15° = 90°
∴ These are complementary (RBSESolutions.com) angles.

(iv) 33°, 57°
Sum of angles = 33° + 57° = 90°
∴ These are complementary angles.

(v) 115°, 65°
Sum of angles = 115° + 65° – 180°
∴ These are (RBSESolutions.com) supplemental angles.

(vi) 25°, 65°
Sum of angles = 25° + 65° = 90°
∴ It is complementary angles.

Question 2
Find those pairs of angles that are complementary to each other (RBSESolutions.com) and also of same measure.
Solution:
Let one angles is x°,
∴ its complementary’ angle = x°
∴ x° + x° = 90°
⇒ 2x° = 90° ⇒ x° = [latex]\frac { { 90 }^{ 0 } }{ 2 }[/latex] = 45°
Required pair of angles = 45°, 45°

Question 3
What will be the value (RBSESolutions.com) of supplementary of a right angle?
Solution:
Let x° be the supplementary angle of 90°
∴ Sum of supplementary angles = 180°.
∴ 90° + x°= 180°
⇒ x° = 180° – 90° = 90
Required supplement angle = 90°

Question 4
Write the pairs of adjacent angles (RBSESolutions.com) for the following figure :

Solution:
(i) ∠POQ व ∠QOR
(ii) ∠POQ व ∠QOS
(iii) ∠POR व ∠ROS
(iv) ∠QOR व ∠ROS

Question 5
Find the following pairs of angles (RBSESolutions.com) from the given figure :

(i) Similar supplementary angles.
(ii) Dissimilar supplementary angles
(iii) Vertically opposite angles
(iv) Adjacent angles which are not linear pair.
(v) Adjacent (RBSESolutions.com) complementary angles
Solution:
(i) Similar supplementary angles are ∠QOT and ∠TOP.
(ii) Dissimilar supplementary angles are ∠QOS and ∠SOP and ∠POR and ∠ROQ.
(iii) Vertically opposite angles ∠ROQ and ∠SOP.
(iv) Adjacent angles are ∠QOS and ∠SOT, ∠SOT and ∠TOP and ∠TOP and ∠POR.
(y) Adjacent complementary angles arc ∠QOS and ∠SOT.
(v) Adjacent complementary angles are ∠QOS and ∠SOT.

Question 6
In which of the following figures (RBSESolutions.com) the angles a and b are adjacent?

Solution:
(i) ∠a, ∠b are not adjacent angles (RBSESolutions.com) because they have no common vertex.
(ii) ∠a, ∠b are not adjacent angles because they have no common vertex. .
(iii) ∠a, ∠b are adjacent angles
(iv) ∠a, ∠b are adjacent angles.

Question 7
Find the value of (RBSESolutions.com) unknown angles in the following figures :

Solution:
(i) ∵∠x+ 125°= 180°
∠x = 180°- 125° = 55°
Two lines (RBSESolutions.com) intersect each other
∴ ∠y = 125° (vertically opposite angles)
(ii) ∠x + 20° = 180°
[ ∠x = 180° – 20°= 160°]
(iii) Two lines intersect each other
∠x = 55° (vertically opposite angles)
∵ ∠x + ∠z = 180° (x, z is a linear pair whose sum is 180°)
55° + ∠z = 180°
⇒ ∠z = 180°- 55°= 125°
Clearly ∠y + ∠x = 90°
∠y + 55° = 90°
∠y = 90° – 55° = 35°

Question 8
Identify (RBSESolutions.com) True or False :
(i) Sum of two angles forming a linear pair is 180°.
(ii) Sum of vertically opposite angles is 90°.
(iii) If two angles are supplementary than their sum is 180°.
(iv) If two adjecent angles are supplementary then they are called a linear pair.
Solution:
(i) True
(ii) False
(iii) True
(iv) True

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