RBSE Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 1 |

Chapter Name |
Rational Numbers |

Exercise |
Exercise 1.1 |

Number of Questions |
11 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 8 Maths Chapter 1 Rational Numbers Ex 1.1

Question 1.

Add the following rational numbers. (Solve any two on number line)

Solution:

Distance between two consecutive numbers on number line is [latex]\frac { 1 }{ 4 }[/latex]

So,addition of [latex]\frac { -3 }{ 4 }[/latex] with [latex]\frac { 5 }{ 2 }[/latex] means, addition of [latex]\frac { -3 }{ 4 }[/latex] with [latex]\frac { 10 }{ 4 }[/latex]

We have to move three gaps from [latex]\frac { 10 }{ 4 }[/latex] in left side (being negative(RBSESolutions.com) sign of [latex]\frac { -3 }{ 4 }[/latex])

So, we reach finally at [latex]\frac { 7 }{ 4 }[/latex]

Distance gap between two(RBSESolutions.com)consecutive points on number line is [latex]\frac { 1 }{ 3 }[/latex]. Therefore, addition of [latex]\frac { -2 }{ 3 }[/latex] with 0 means, we have to move 2 gaps in left side from zero, so we reach finally at [latex]\frac { -2 }{ 3 }[/latex]

Hence, 0 + [latex]\frac { -2 }{ 3 }[/latex] = [latex]\frac { -2 }{ 3 }[/latex]

Question 2.

Find the value (Solve any two on number line)-

Solution:

Distance between two points (gaps) on number line is [latex]\frac { 1 }{ 12 }[/latex]

So, addition of [latex]\frac { 8 }{ 12 }[/latex] and [latex]\frac { 15 }{ 12 }[/latex] means we have to move 15 gaps in right side (being positive sign of [latex]\frac { 8 }{ 12 }[/latex] So, we reach at [latex]\frac { 23 }{ 12 }[/latex] finally.

Solution on number line-

Distance(RBSESolutions.com)between two points (gaps) on

Number line is [latex]\frac { 1 }{ 63 }[/latex]

[latex]\frac { -7 }{ 63 } +\left( \frac { -5 }{ 21 } \right) =\left( \frac { -7 }{ 63 } \right) +\left( \frac { -15 }{ 63 } \right) [/latex]

S0, addition of [latex]\frac { -7 }{ 63 }[/latex] and [latex]\frac { -15 }{ 63 }[/latex] means we have to move 15 gaps in left side negative sign of [latex]\frac { -7 }{ 63 }[/latex] So, we reach at [latex]\frac { -22 }{ 63 }[/latex] finally.

Hence [latex]\frac { -7 }{ 63 } +\left( \frac { -5 }{ 21 } \right) =\frac { -22 }{ 63 } [/latex]

Question 3.

Multiply the following rational numbers-

Solution:

Question 4.

Find the values

Solution:

Question 5.

Find the values

Solution:

Question 6.

Find the value of the(RBSESolutions.com)following using the appropriate properties

Solution:

Question 7.

Find the additive inverse of the following rational numbers

Solution:

Question 8

Find multiplicative inverse of the following rational numbers

Solution:

(i) – 17

Question 9.

Multiply the rational number [latex]\frac { 5 }{ 7 }[/latex] to inverse of [latex]\frac { -7 }{ 15 }[/latex]

Solution:

Question 10.

Fill in the blanks—

(i) Product of two rational number is always ___(Rational/Integers)

(ii) Additive(RBSESolutions.com)inverse of any negative rational number is ___(positive/negative)

(iii) Inverse of zero is ___(zero/In determined)

(iv) Additive identity of rational number is ___(zero/one)

(v) Multiplicative identity of rational number is ____(zero/one)

(vi) Reciprocal of rational number is ___of that. (inverse/same)

(vii) Negative(RBSESolutions.com)rational number on number line is always lies on ____ of zero (right/left)

(viii) Positive rational number on number line is always lies on ___ of zero. (right/left)

(ix) When rational number is added with its additive inverse then result is always ___(zero/same)

(x) When rational number is divided by same rational number then result is always ____(zero/one)

Solution:

(i) Rational

(ii) positive

(iii) undefined

(iv) zero

(v) one

(vi) reciprocal

(vii) left

(viii) right

(ix) zero

(x) one.

Question 11.

By mean method-

(i) Write any five rational numbers between – 3 and 0.

(ii) Write an(RBSESolutions.com)four rational numbers larger than 0 and smaller than [latex]\frac { 5 }{ 6 }[/latex]

(iii) Find any three rational numbers between [latex]\frac { -3 }{ 4 }[/latex] and [latex]\frac { 5 }{ 6 }[/latex]

Solution:

(i) Rational number between – 3 and 0

(ii) Rational number between 0 and [latex]\frac { 5 }{ 6 }[/latex]

(iii) Rational number between [latex]\frac { -3 }{ 4 }[/latex] and [latex]\frac { 5 }{ 6 }[/latex]

We hope the given RBSE Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1, drop a comment below and we will get back to you at the earliest.

Deepak says

Nice