RBSE Solutions for Class 8 Maths Chapter 10 Factorization Ex 10.3 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 10 Factorization Exercise 10.3.
Board | RBSE |
Textbook | SIERT, Rajasthan |
Class | Class 8 |
Subject | Maths |
Chapter | Chapter 10 |
Chapter Name | Factorization |
Exercise | Exercise 10.3 |
Number of Questions | 4 |
Category | RBSE Solutions |
Rajasthan Board RBSE Class 8 Maths Chapter 10 Factorization Ex 10.3
Question 1.
Carry out the following divisions.
(i) 28x4 by 56x
(ii) – 36y3 by 9y2
(iii) 34x3y3z3 by 51xy2z3
(iv) 12a8b8 by (- 6a6b4)
Solution
(i) 28x4 ÷ 56x
(ii) – 36y3 ÷ 9y2
(iii) 34x3y3z3 ÷ 51xy2z3
(iv) 12a8b8 ÷ (- 6a6b4)
Question 2.
Divide the given(RBSESolutions.com)polynomial by the given monomial.
(i) (5x2 – 6x) by 3x
(ii) (x3 + 2x2 + 3x) by 2x
(iii) (p3q6 – p6q3) by p3q3
(iv) (3x8 – 4x6 + 5x4) by x4
Solution
(i) (5x2 – 6x) ÷ 3x
(ii) (x3 + 2x2 + 3x) ÷ 2x
(iii) (p3q6 – p6q3) ÷ p3q3
(iv) (3x8 – 4x6 + 5x4) ÷ x4
Question 3.
Work out the following divisions.
(i) 10y(6y + 21) ÷ 5(2y + 7)
(ii) 9x²y²(3z – 24) ÷ 27xy(z – 8)
(iii) (10y + 14) ÷ 2
(iv) (6x – 15) ÷ (2x – 5)
Solution
(i) 10y(6y + 21) ÷ 5(2y + 7)
(ii) 9x²y²(3z – 24) ÷ 27xy(z – 8)
(iii) (10y + 14) ÷ 2
(iv) (6x – 15) ÷ (2x – 5)
Question 4.
Factorize the expressions and divide them as directed
(i) (y² + 7y + 10) ÷ (y + 5)
(ii) (5x² – 25x + 20) ÷ (x – 1)
(iii) 12xy(9x² – 16y²) ÷ 4xy(3x + 4y)
(iv) 4yz (z² + 6z – 16) ÷ 2y (z + 8)
Solution
(i) (y² + 7y + 10) ÷ (y + 5)
y² + 7y + 10
(ii) (5x² – 25x + 20) ÷ (x – 1)
(5x² – 25x + 20)
(iii) 12xy(9x² – 16y²) ÷ 4xy(3x + 4y)
12xy(9x² – 16y²) ÷ 4xy(3x + 4y)
(iv) 4yz (z² + 6z – 16) ÷ 2y (z + 8)
4yz (z² + 6z – 16) ÷ 2y (z + 8)
We hope the given RBSE Solutions for Class 8 Maths Chapter 10 Factorization Ex 10.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 10 Factorization Exercise 10.3, drop a comment below and we will get back to you at the earliest.
Leave a Reply