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RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise

February 23, 2019 by Fazal Leave a Comment

RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 10
Chapter Name गुणनखण्ड
Exercise In Text Exercise
Number of Questions 4
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise

पृष्ठ 119
करो और सीखो

प्रश्न
दो पूर्णांक a तथा b ऐसे ज्ञात कीजिए कि

a + b ab a b
8 15 5 3
13 12
– 1 – 20 – 5 4
– 5 4
10 21
– 1 – 12
– 11 10
– 7 10

हल:
(a + b)2 = a2 + 2ab + b2
(a – b)2 = a2 – 2ab + b2
तब (a + b)2 – (a – b)2 = 4ab
RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise Q1
RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise Q1a
RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise Q1b
RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise Q1c
उपरोक्त मान तालिका में(RBSESolutions.com)भरने पर

a + b ab a b
8 15 5 3
13 12 12 1
– 1 – 20 – 5 4
– 5 4 – 4 – 1
10 21 7 3
– 1 – 12 – 4 3
– 11 10 – 10 – 1
– 7 10 – 5 – 2

पृष्ठ 123
करो और सीखो
त्रुटियों को पहचानो

प्रश्न 1
3x + x + 4 = 56
7x = 56
x = \(\frac { 56 }{ 7 }\)
= 8
किसी पद के गुणांक 1 को प्रायः दर्शाया(RBSESolutions.com) नहीं जाता है परन्तु समान पदों को जोड़ते समय इसे योग में सम्मिलित करते हैं।
त्रुटि कहाँ है? सही उत्तर ज्ञात कीजिए।

RBSE Solutions

प्रश्न 2
5x का मान =- 2 पर ज्ञात कीजिए।
= 5 – 2 = 3
त्रुटि कहाँ है? सही मान ज्ञात कीजिए।

प्रश्न 3
व्यंजकों के हल कॉलम A तथा कॉलम B में दिए गए(RBSESolutions.com)हैं। जाँच करके बताएँ कौनसा हल सही है?

व्यंजक A B
3(x – 4) 3x – 4 3x – 12
(2x)2 2x2 4x2
(x + 4)2 X2 + 16  X2 + 8x + 16
(x – 3)2 X2 – 9 X2 – 6x -+ 9
\(\frac { y+5 }{ 5 }\) Y + 1   \(\frac { y }{ 5 }\) + 1

हल:
(1) 3x + x + 4 = 56
= 3x + 1 + 4x = 56
= (3 + 1 + 4) x = 56
⇒ 8x = 56
⇒ x =  \(\frac { 56 }{ 8 }\) = 7 (सही मान)

(2) x = – 2 पर 5x का मान
= 5 x (-2) 5x = 5 x x
= – 10 (सही मान)

(3) (i) 3(x – 4)
= 3 x x – 3 x 4
= 3x – 12
अतः B(RBSESolutions.com) सही है।

(ii) (2x)2
= (2x) x (2x)
= (2 x x) x (2 x x)
= 2 x 2 x x x x
=4 x x2
= 4x2
अत: B सही है।

(iii) (x + 4)2 = x2 + 2(x) (4) + (4)2
= x2 + 8x + 16
अत: B सही है।

(iv)(x – 3)2 = x2 – 2 (x) (3) + (3)2
= x2 – 6x + 9
अतः B(RBSESolutions.com)सही है।

(v) \(\frac { y+5 }{ 5 }\) = \(\frac { y }{ 5 }\) + \(\frac { y }{ 5 }\)
= \(\frac { y }{ 5 }\) + 1
अतः B सही है।

RBSE Solutions

We hope the RBSE Solutions for Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 10 गुणनखण्ड In Text Exercise, drop a comment below and we will get back to you at the earliest.

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