RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions

RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 8
Subject	Maths
Chapter	Chapter 13
Chapter Name	Comparison of Quantities
Exercise	Additional Questions
Number of Questions	32
Category	RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions

I. Objective Type Questions

Question 1.
The basic salary of a person is Rs 1,40,000. If his salary is increased by 10%, than his new salary will be
(a) Rs 1,50,000
(b) Rs 1,40,010
(c) Rs 1,54,000
(d) Rs 1,40,100

Question 2.
Yasha mark up the(RBSESolutions.com)computers I am selling by 20% and sell then at a discount of 15%. What is my net gain percent?
(a) 1%
(b) 2%
(c) 3%
(d) 4%

Question 3.
The printed price of a jeans is Rs 220. The discount 20% is given on this. Selling price is

Question 4.
There are 15 apples and 5 oranges in a bucket. Then what is the ratio of number of oranges to number is apples
(a) 1:3
(b) 15 : 5
(c) 3 : 1
(d) 5 : 20

Question 5.
The compound(RBSESolutions.com)interest of ? 20,000 at the rate of 8% per year for 2 years is
(a) Rs 3,200
(b) Rs 1,728
(c) Rs 1,600
(d) Rs 3,328

Question 6.
If the cost of one kg sugar is Rs 18, then cost of 3 kg sugar is Rs 54. Thus relation is called
(a) Direct Proportion
(b) Inverse Proportion
(c) Ratio
(d) None of the above

Question 7.
If number of purchased items is increased, then their cost will be
(a) decreased
(b) increased
(c) decreased or increased
(d) neither(RBSESolutions.com)increased nor decreased

Question 8.
If two variables are related to each other in such a way, that if we increase the value of first variable then the value of second variable decreases, and converse is also occurred. Thus related is called
(a) ratio
(b) inverse proportional
(c) direct proportional
(d) None of these

Percent Decrease Calculator Go here if you need to calculate another percent decrease.

Question 9.
If interest is calculated quarterly then time period is
(a) double
(b) four times
(c) triple
(d) No change

Question 10.
80% students are good at maths out of 25 students. How many(RBSESolutions.com)students are not good at maths?
(a) 10
(b) 5
(c) 15
(d) 20

Answers
1. (c)
2. (b)
3. (c)
4. (a)
5. (d)
6. (a)
7. (b)
8. (b)
9. (b)
10. (b)

II. Fill in the blanks

Question 1.
The concession on printed rate is called___

Question 2.
Sale tax is added to cost price of item is called___

Question 3.
The interest(RBSESolutions.com)compounded on total amount of previous year (A = P + I) is called___

Question 4.
The direct ratios is x and y then \(\frac { { x }_{ 1 } }{ { y }_{ 1 } } =\)____

Question 5.
If the speed of a vehicle is increased then the time taken for travelling same distance is___

Answers
1. discount
2. VAT
3. Compound Interest
4. \(\frac { { x }_{ 2 } }{ { y }_{ 2 } }\)
5. decreased.

III. True/False Type Questions

Question 1.
When interest is(RBSESolutions.com)added yearly, the compound interest \(P\left[ { \left( 1+\frac { R }{ 100 } \right) }^{ n }-1 \right] \)
Where P = Principal; R = Rate; n = Time

Question 2.
When interest is added on half yearly, then rate of interest reduces to half.

Question 3.
The percentage form of 1 : 4 is 25%.

Question 4.
The interest is(RBSESolutions.com)based on the amount deposited in bank.

Question 5.
There is a direct relation between height of a tree and number of leaves on its branches.

Answers
1. True
2. True
3. True
4. True
5. False.

IV. Matching Type Questions

Part 1	Part 2
1. Formula of calculating simple interest	(a) Cost price + Profit
2. Selling price (if profit exist)	(b) Constant
3. If x and y are in inverse relationship, then xy =	(c) 1 : 10
4. Ratio between 50 paise to Rs 5	(d) \(\frac { PRT }{ 100 }\)

Answers
1. ↔ (d),
2. ↔ (a),
3. ↔ (b),
4. ↔ (c)

V. Very Short Answer Type Questions

Question 1.
The meaning of twice of a number is to increase 100%. What is the percentage decrease if number reduces to its half?
Solution
Percentage loss

= 50%

Question 2.
If any amount is borrowed for one year at the 16% rate of interest p.a. If interest is compounded for quarterly, then how many times will the interest be paid?
Solution
1 year = 4 quarters
∴ Interest will be(RBSESolutions.com)paid 4 times in a year.

Question 3.
After selling a plot for Rs 61,200, the gain is 2%. What is the cost price of plot?
Solution
Let plot cost price Rs x

Hence, the required(RBSESolutions.com)cost price of plot is Rs 60,000.

Question 4.
The cost price of a scooter is Rs 42,000. If it depreciates at a rate of 8%, what will be the price of scooter after 1 year?
Solution
Price of scooter after 1 year

= Rs 38,640.

Question 5.
In a government school 25% Neem plants were shown during(RBSESolutions.com)environment pakwara (fortnight). If there are 180 plants in total then how many Neem plants are there?
Solution
Total plants = 180
Percentage of Neem plants = 25%
Hence the required number of Neem plants = 25% of 180
= \(\frac { 25 }{ 100 }\) × 180
= 45

Question 6.
Convert 2 : 5 ratios into percentage.
Solution
= 2 : 5

= 40%

VI. Short Answer Type Questions

Question 1.
Simple interest for 5 years on some money is \(\frac { 2 }{ 5 }\) of total amount (A). Find the rate of simple interest
Solution
Amount = Principal + Simple Interest
Principal x Time x Rate 100


⇒ 5 PR = 40 P + 2 PR
⇒ 5R = 40 + 2R
⇒ 5R – 2R = 40
⇒ 3R = 40
⇒ R= \(\frac { 40 }{ 3 }\) = \(13\frac { 1 }{ 3 }\)
Hence, the required rate(RBSESolutions.com)of simple interest is \(13\frac { 1 }{ 3 }\) %

Question 2.
The population of a town before 3 years was 25,000. If grows at 10%, 15% and 8% in consecutive three years. Find the present population.
Solution
Present Population

= 34,155

Question 3.
Find the rate of which a sum of money will \(\frac { 81 }{ 16 }\) times itself in one year, if the interest is compounded quarterly.
Solution
Let R% yearly be the rate of interest.
Then quarterly(RBSESolutions.com)rate of interest = \(\frac { R }{ 4 }\) %
1 year = 4 quarters
According to question,

Hence, the required rate of interest is 200% p.a.

Question 4.
A farmer took loan of Rs 20,000 from Nationalized Bank for his agricultural work. If bank charges interest on the rate of 14% yearly and the interest is compounded yearly. What is the total amount to be paid after 2 years and 6 months?
Solution
Loan amount = Rs 20,000
Rate of(RBSESolutions.com)interest = 14% yearly
Time = 2 years 6 months
= 2 years + \(\frac { 6 }{ 12 }\) year
= \(\frac { 5 }{ 2 }\) years

Total Amount = Principal Amount + Interest
= 20,000 + 7,000
= Rs 27,000
Hence the total amount to be paid is Rs 27,000.

Question 5.
A farmer has enough food for 20 animals for 6 days. If he increases 10 more animals then for how many days this food will be enough?
Solution:

Let required days be x.
Here inverse relation occurred.
30 : 20 :: 6 : x
Product of outer(RBSESolutions.com)terms = Product of middle terms
⇒ 30 × x = 20 × 6
⇒ \(x=\frac { 20\times 6 }{ 30 } =4\)
Hence, the required days are 4.

Question 6.
Suppose in 2 Kg. sugar, there are 9 x 10⁶ crystals. How many crystals will be there in 1.2 kg. sugar?
Solution

Let x crystals be in 1.2 kg sugar.
Then, 2 : 1.2 :: 9 × 10⁶ : x
Product of outer terms = Product of middle terms
⇒ 2 × x = 1.2 × 9 × 10⁶

Hence, the required crystals are 5.4 x 10⁶.

Question 7.
In class VIII 60% students in Maths obtained grade A out of 45 students. How many students got A grade in Maths?
Solution
Total number of students = 45 %
of students getting grade A in Maths = 60%
Number of(RBSESolutions.com)students getting grade A in Maths
= 60% of 45 = \(\frac { 60 }{ 100 }\) × 45 = 27
∴ Number of students getting grade A in Maths = 27

Question 8.
A businessman sold two television sets at the rate of Rs 36,000 for each television set If he gets 20% profit on one television set and 20% loss on the other television set then find the percentage of profit or loss in total transaction?
Solution
Selling price of one television = Rs 36,000
Let cost(RBSESolutions.com)price be Rs x
Percentage profit = 20%

Question 9.
Naval borrowed Rs 84,000 from a nationalized bank for \(1\frac { 1 }{ 2 }\) years at the rate of 10% per annum. Compute the total compound interest(RBSESolutions.com)payable by Naval after \(1\frac { 1 }{ 2 }\) year, if the interest is compound half yearly.
Solution
\(1\frac { 1 }{ 2 }\) years = 3 half years
Principal Amount = Rs 84,000
Rate = 10%
= 5% half yearly
Total amount = principal amount

∴ Compound Interest = Total Amount – Principal Amount
= 97,240.50 – 84,000
= Rs 13,240.50

Question 10.
Rahul sold a scooter for Rs 18,750 at a loss of 25%. Find the cost price of the scooter.
Solution
Let the required(RBSESolutions.com)cost price of scooter be Rs x.
Loss = 25% of x
Selling Price = Rs 18,750
Therefore,
Cost Price – Loss = Selling Price

= 25,000
Hence the required cost price of scooter is Rs 25,000..

Question 11.
Find compound interest of Rs 24,000 for \(1\frac { 1 }{ 2 }\) years at the rate of 8% per year, when interest is calculated yearly.
Solution
Time = \(1\frac { 1 }{ 2 }\) year
Principal(RBSESolutions.com)Amount = Rs 24,000
Annual interest rate = 8%

∴Amount = Rs 26,956.80
Compound Interest = Amount – Principal
= 26,956.80 – 24,000
= Rs 2,956.80

Question 12.
The population of a town increases at annual rate of 8%. If present population of town is 17,496 then find population of town before 2 years. Solution
Present Population = 17,496
Time = 2 years
Rate of increase = 8%
Let the(RBSESolutions.com)population of town before 2 years be x.
Hence, Present Population

⇒ x = 15,000
Hence the required population of town before 2 years = 15,000

Question 13.
Payal took loan of Rs 20,000 for parlor from a nationalized(RBSESolutions.com)Bank. How much amount will she repay after 3 years, if annual rate of interest is 14% and interest is compounded annually?
Solution
Amount borrowed from Bank (P) = Rs 20,000
Time (n) = 3 years
Rate of interest = 14%
Condition = Interest is compounded annually

∴ Payal has to return Rs 29,631 to the bank.

Question 14.
A businessman purchased goods for Rs 14,000. He paid Rs 50 for freight(RBSESolutions.com)and Rs 150 for wages. To earn 5% profit, at what price he should sell goods?
Solution
Cost price of goods = Rs 14,000
Auto rent = Rs 50
Wages = Rs 150
Total cost(RBSESolutions.com)price of goods
= Rs (14,000 + 50 + 150)
= Rs 14,200
Wants to earn profit = 5%
∴Profit = 5% of 14,200
= \(\frac { 14,200X5 }{ 100 }\)
= Rs 710
∴ Selling price of goods = Rs(14,200 + 710)
= Rs 14,910.

We hope the given RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Additional Questions, drop a comment below and we will get back to you at the earliest.