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RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2

March 23, 2019 by Fazal 1 Comment

RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Exercise 13.2.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 13
Chapter Name Comparison of Quantities
Exercise Exercise 13.2
Number of Questions 9
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2

Question 1.
Mohan purchases some mattresses for Rs. 7250. After some time he sold them for Rs. 6090. Find out loss percentage.
Solution:
Cost price = Rs 7,250
Selling price = Rs 6,090
∴ Loss = Cost price – Selling price
= 7,250 – 6,090
= Rs 1,160
∵ Loss(RBSESolutions.com)on Rs 7,250 = 1,160
∴ Loss on Rs 1 = Rs \(\frac { 1160 }{ 7250 }\)
∴ Loss on Rs 100 = Rs \(\frac { 1160 }{ 7250 }\) x 100
= Rs 16
Hence, % loss of Mohan = 16%

RBSE Solutions

Question 2.
Due to increase in salary of Ajit Singh by 12% new salary becomes Rs. 25760. Find his previous salary.
Solution:
Let Rs x be the previous salary.
Percentage increase = 12%
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-1
⇒ x = 23,000
Hence, the previous salary was Rs 23,000.

RBSE Solutions

Question 3.
Manjeet mark up price on a pump by increasing 40%. If he wishes to sell it after providing subsidy of 40% then find out profit or loss percentage.
Solution:
Let Rs x be the cost price of pump set.
∴ Marked price = x + 40% of x
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-2
= 16%
Hence, loss percentage is 16%.

RBSE Solutions

Question 4.
Cost of a moped is t 54,000. Now price increased by 14%, then tell the price to be paid for moped.
Solution:
Price of Moped = Rs 54,000
Percentage(RBSESolutions.com)increase in cost = 14%
Increase = 14% of 54,000
= 54000 x \(\frac { 14 }{ 100 }\)
= Rs 7650
∴ New cost of Moped = 54,000 + 7,560
= Rs 61,560
Hence, the required price of Moped is Rs 61,560.

RBSE Solutions

Question 5.
A businessman purchased goods for Rs. 14000. He paid Rs. 350 as auto rent and Rs. 150 as wages. For earning 5% profit, at what price he should sell goods.
Solution:
Cost price of(RBSESolutions.com)products = Rs 14,000
Transportation = Rs 350
Labor = Rs 150
∴ Total cost price of products
= 14,000 + 350 + 150
= Rs 14,500
Profit % = 5%
∴ Profit = 5% of 14,500
= 14,500 x \(\frac { 5 }{ 100 }\)
= Rs 725
∴ Selling Price = Total Cost Price + Profit
= 14,500 + 725
= Rs 15,225
Hence, he will sell his products for Rs 15,225.

RBSE Solutions

Question 6.
A furniture seller sold two dressing tables at the rate of Rs. 7200. Out of them 20% profit obtained on one table and 20% loss on another. How much profit or gain percentage is(RBSESolutions.com)obtained in whole transaction?
Solution
Selling Price of one dressing table = Rs 7,200
Let cost price = Rs x
gain % = 20%
∴Gain = 20% of x
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-3
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-4
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-5
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-6
Hence total loss % = 4%, for the two dressing tables.

RBSE Solutions

Question 7.
Manoj paid Rs. 6500 as interest on loan of Rs. 52000 after two years. Find percentage interest paid by Manoj.
Solution
Interest of 2 years = Rs 6,500
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-7
= Rs 6.25
Hence, the required of interest is 6.25%.

Question 8.
In what time will principal of Rs. 3200 at rate of 8% become Rs. 3840?
Solution:
Principal(RBSESolutions.com)Amount = Rs 3,200
Amount = Rs 3,840
∴ Simple Interest = Amount – Principal
= 3,840 – 3,200
= Rs 640
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-8
= 2.5 years
= 2 years 6 month
Hence, Required Time = 2 years and 6 months.

RBSE Solutions

Question 9.
Bhupendra took loan of Rs. 6300 at rate of 7% for 2 years and 8 months then tell what amount will be paid by him?
Solution
Principal = Rs 6,300
Time = 2 years & 8 months
= 2 years + 8 months
= 2 years + \(\frac { 8 }{ 12 }\) year
= 2 year + \(\frac { 2 }{ 3 }\) year
RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 img-9
∴ Amount = Principal + Simple(RBSESolutions.com)Interest
= 6,300 + 1,176
= Rs 7,476
Hence, he will pay Rs 7,476.

RBSE Solutions

We hope the given RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.2 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Exercise 13.2, drop a comment below and we will get back to you at the earliest.

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