RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.3

RBSE Solutions for Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.3 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Exercise 13.3.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 8
Subject	Maths
Chapter	Chapter 13
Chapter Name	Comparison of Quantities
Exercise	Exercise 13.3
Number of Questions	9
Category	RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 13 Comparison of Quantities Ex 13.3

Question 1.
Number of visitors on the first day of book fair in the city was 3000 which increased to 3600 on next day. Determine increase in fare visitors. Solution
Number of visitors of First day = 3000
Number of(RBSESolutions.com)visitors on second day = 3600
∴Increase in number of visitors
= 3600 – 3000
= 600
∴ Percentage increase in visitors

= 20%

Question 2.
Price of a television is Rs. 30,000. Value of object decreases (devaluates) by 20% then determine its value after 2 years.
Solution
Cost after 2 years

= Rs 19,200

Question 3.
Kapil took a loan of Rs. 52800 at annual rate of 12% from a bank for purchasing a scooter when accumulated rate is annual. After one year and 6 months(RBSESolutions.com)what amount is to be paid for repaying loan?
Solution
Principal = Rs 52,800
Rate =12% yearly
∴ Amount after 1 year


Hence the required amount to be paid is Rs 62,684.16.

Question 4.
In year 2013 number of road accidents was 10,000. By traffic police awareness programs were run for avoiding road accidents due to which it decreases by 20% then what was the number of road accidents in 2015?
Solution
Initial number = 10,000
Time = 2015 – 2013 = 2 years
Rate of decrease = 20%
∴ Number of road accidents in 2015

Question 5.
Determine compound interest on Rs. 10,000 for 2 years at 8% annual rate if interest is calculated at annual rate.
Solution:

Question 6.
Payal took loan of Rs. 12,000 for parlor from a nationalized bank. How much amount she will repay after 2 years 6 months at annual rate of 8%. When(RBSESolutions.com)interest is accumulated annually.
Solution
Amount after 2 years

∴ Amount to be paid
= 15,595.20 + 1,091.66
= Rs 16,686.86

Question 7.
Calculate compound interest on Rs. 18,000 for \(1\frac { 1 }{ 2 }\) year @ 10% when interest is calculated half yearly.
Solution
\(1\frac { 1 }{ 2 }\) year = 3 half yearly
Principal = Rs 18,000
Rate = 10% yearly
= \(\frac { 10 }{ 2 }\)% half yearly
= 5% half yearly

∴ Compound Interest = Amount – Principal
= 20,837.25 – 18,000
= Rs 2,837.25

Question 8.
Vishnu invested Rs. 80,000 at annual rate of 14% if interest accumulates half yearly then determines what amount he will receive? If time is
(i) 6 months
(ii) 1 year.
Solution
(i) 6 months
Principal (P) = Rs 80,000
Half yearly(RBSESolutions.com)Rate (R) = \(\frac { 14 }{ 2 }\)% = 7%
Time (n) = 6 month
= 1 Half yearly


= Rs 91,592

Question 9.
Kushwant borrowed Rs. 12,500 for 3 years @5% annually on simple interest(RBSESolutions.com)If same amount is borrowed @ 5% annually on compound interest then what extra amount Khushwant has to pay?
Solution

= 14,470.31 – 12,500
= Rs 1,970.31
∴ Khushwant has to pay
= 1,970.31 – 1,875
= Rs 95.31 more when he borrows at compound interest as compared at simple interest.

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