RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1

RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Exercise 3.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 8
Subject	Maths
Chapter	Chapter 3
Chapter Name	Powers and Exponents
Exercise	Exercise 3.1
Number of Questions	10
Category	RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1

Question 1.
Simplify the following

Solution.

Question 2.
Find the values

Solution.
(i) (-5)³
= (-1 × 5)³
= (-1)³ × (5)³
= (-1) × 5 × 5 × 5
= – 125

Question 3.
With the help of Prime factor, change the following into exponent form

Solution.

Question 4.
Find the values

Solution.
(i) 3² × 3³
3²⁺³ = 3⁵ = 3 × 3 × 3 × 3 × 3
= 243

Question 5.
Answer in exponent form-

Solution.
(i) 4⁵ ÷ 4²
= 4⁵ ÷ 4²
= 4^5–2
= 4³
(ii) (- 5)⁷ ÷ (- 5)⁴
= (- 5)^7-4
=(- 5)³

Question 6.
Find the value
(i) (3²)³
(ii) (2³)²
(iii) (5²)²
(iv) (-2⁴)²

Solution.
(i) (3²)³
= (3 x 3)³
=9³
= 9 x 9 x 9 = 729
(ii) (2³)²
= 2³ x 2
= 2⁶
= 2 x 2 x 2 x 2 x 2 x 2=64
(iii) (5²)²
= 5^2×2
= 5⁴
= 5 x 5 x 5 x 5 = 625
(iv) (- 2⁴)²
= (- 2 x 2 x 2 x 2)²
= (- 16)²
= {(- 1) x 16)²
= (- 1)² x (16)²
= 1 x 16 x 16 = 256

Question 7.
Find the value
(i) 3⁰
(ii) 7^5-5
(iii) (-2)^3-3
(iv) \({ \left( \frac { 2 }{ 3 } \right) }^{ 2+3-5 }\)
(v) 2⁰ × 3⁰
(vi) 2⁰ + 5⁰
(vii) \({ \left( \frac { 7 }{ 15 } \right) }^{ 0 }+{ \left( \frac { 1 }{ 7 } \right) }^{ 3-3 }\)
Solution.
(i) 3⁰
3⁰ = 1
(ii) 7^5-5
7^5-5 = 7⁰ = 1
(iii) (- 2)^3-3
(- 2)^3-3 = (- 2)⁰ = 1
(iv) \({ \left( \frac { 2 }{ 3 } \right) }^{ 2+3-5 }\)
\({ \left( \frac { 2 }{ 5 } \right) }^{ 2+3-5 }\)
\({ \left( \frac { 2 }{ 5 } \right) }^{ 0 }=1\)
(v) 2⁰ X 3⁰
2⁰ x 3⁰ = 1 x 1 = 1
(vi)2⁰ + 5⁰
2⁰ + 5⁰ = 1 + 1 = 2

Question 8.
Change into positive exponent numbers
(i) 2^-3
(ii) 3^-5
(iii) a^-4
(iv) (-2)^-5
(v) (-x)^-3
(vi) \(\frac { 1 }{ { 5 }^{ -3 } } \)
(vii) \(\frac { 1 }{ { y }^{ -3 } } \)
(viii) \(\frac { 1 }{ { \left( \frac { 2 }{ 3 } \right) }^{ -3 } } \)
Solution.
(i) 2^-3

Question 9.
Simplify the following ¡n form of exponent

Solution.
(i) (2² x 3³)²
= (2 x 2 x 3 x 3 x 3)²
= (108)²
= 108 X 108
= 11664

Question 10.
Find the values of

Solution.

= (3)² + (2)² + (4)²
=9 + 4 + 16
= 29

We hope the given RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Exercise 3.1, drop a comment below and we will get back to you at the earliest.