RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.3 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Exercise 3.3.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 3 |

Chapter Name |
Powers and Exponents |

Exercise |
Exercise 3.3 |

Number of Questions |
3 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Ex 3.3

Question 1.

Change In the standard form

(i) 128000000

(ii) 1680000000

(iii) 0.0005

(iv) 0.00000017

(v) 0.000000000397

(vi) 0.00000004358

Solution

(i) 128000000

= 1.28 x 100000000

= 1.28 x 10^{8}

(ii) 1680000000

= 1.68 x 1000000000

= 1.68 x 10^{9}

Question 2.

Express the following numbers in normal form

(i) 4 × 10^{9}

(ii) 245 × 10^{7}

(iii) 5.61729 × 10^{7}

(iv) 8.5 × 10^{-6}

(v) 3.02 × 10^{-6}

(vi) 7 × 10^{-4}

Solution

(i) 4 x 10^{9} = 4 × 1000000000

= 4000000000

(ii) 245 × 10^{7}

= 245 x 10000000

= 2450000000

(iii) 5.61729 × 10^{7}

= 5.61729 × 10000000

= 56172900

Question 3.

Change the numbers In standard form of the following statements

(i) Diameter of the(RBSESolutions.com)thickness of human hair is 0.0002 cm approx.

(ii) Charge on an electron is 0.000,000,000,000,000,00016 coulomb.

(iii) 1 Micron = [latex]\frac { 1 }{ 1000000 }[/latex] metre.

(iv) Thickness of a paper = 0.0016 cm.

Solution

(i) 0.0002

We hope the given RBSE Solutions for Class 8 Maths Chapter 3 Powers and Exponents Ex 3.3 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 3 Powers and Exponents Exercise 3.3, drop a comment below and we will get back to you at the earliest.

Babu Lal Yadav says

Question no. 4 with example