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RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions

February 21, 2019 by Fazal Leave a Comment

   

RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 5 वैदिक गणित Additional Questions.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 5
Chapter Name वैदिक गणित
Exercise Additional Questions
Number of Questions 13
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 5 वैदिक गणित Additional Questions

I. बहुविकल्पात्मक प्रश्न

प्रश्न 1
दो अंकीय संख्या के दो अंकीय संख्या से गुणा में समूह बनेंगे
(a) 1
(b) 2
(c) 3
(d) 4

प्रश्न 2
तीन अंकीय संख्या के तीन अंकीय संख्या से गुणा में समूह बनेंगे
(a) 3
(b) 5
(c) 6
(d) 9

प्रश्न 3
यदि आधार 10 हो तथा उपाधार(RBSESolutions.com) 30 हो तो उपाधार अंक होगा
(a) 3
(b) 2
(c) 1
(d) 4

RBSE Solutions

प्रश्न 4
54 का उपाधार 50 से विचलन है
(a) 4
(b) – 4
(c) 0
(d) 5

प्रश्न 5
48 का उपाधार 50 से विचलन है
(a) – 1
(b) – 2
(C) – 5
(d) 0

II. लघूत्तरात्मक प्रश्न

प्रश्न 1
निम्न का गुणनफल ज्ञात कीजिए
(i) 98 x 98
(ii) 102 x 102
हल:
(i) 98 x 98
आधार = 10
उपाधार = 9 x 10 = 90
उपाधार(RBSESolutions.com) अंक = 90 ÷ 10 = 9
उपाधार से विचलन = 98 – 90 = + 8
98 – 90 = +8
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2
अतः 98 x 98 का अभीष्ट गुणनफल 9604 होगा।

RBSE Solutions

(ii) 102 x 102
आधार = 10
उपाधार = 10 x 10 = 100
उपाधार(RBSESolutions.com) अंक = 100 ÷ 10 = 10
उपाधार से विचलन = 102 – 100 = + 2
102 – 100 = + 2

RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2B
अतः 102 x 102 का अभीष्ट गुणनफल 10404 होगा।

प्रश्न 2
सूत्र निखिलम् द्वारा 101 x 102 x 103 का मान ज्ञात कीजिए।
हल:
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2C

RBSE Solutions

प्रश्न 3
ऊर्ध्वतिर्यग्भ्याम् विधि से गुणा कीजिए
426 x 351
हल:
426 x 351
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2D
अतः अभीष्ट गुणनफल 426 x 351 = 149526 प्राप्त होता है।

प्रश्न 4
निखिलम सूत्र का उपयोग कर गुणा कीजिए – 22 x 23
हल:
आधार = 10.
उपाधार = 2 x 10 = 20
उपाधार अंक = 20 ÷ 10 = 2
उपाधार से विचलन = 22 – 20 = 2, 23 – 20 = 3
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2E
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2F
अतः 22 x 23 का अभीष्ट गुणनफल 506 होगा।

RBSE Solutions

प्रश्न 5
निखिलम् सूत्र का उपयोग कर गुणा कीजिए
103 x 103 x 103
हल:
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2F5

प्रश्न 6
ध्वजांक विधि का उपयोग कर भाग कीजिए 18542 ÷ 52 हलध्वजांक
हल:
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2F6

प्रश्न 7
ऊर्ध्वतिर्यग्भ्याम् सूत्र का उपयोग करते हुए 415 x 132 का मान ज्ञात कीजिए।
हल:
415 x 132

चरण 1 गुण्य 415 व गुणक 132 है। गुणा के रूप में लिखने पर।
चरण 2 तीन अंकों(RBSESolutions.com) की संख्या में समूहों की संख्या 5 होगी।
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2F7

RBSE Solutions

प्रश्न 8
ध्वजांक विधि द्वारा 3732 ÷ 42 को हल कीजिए।
हल:
3732 ÷ 42
RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions 2F8
संकेत – (i) 37 ÷ 4 भागफल का प्रथम अंक = 8, शेषफल = 5
(ii) नया भाज्य = 53
संशोधित भाज्य = 53 – 8 x 2 = 37
(iii) 37 ÷ 4 भागफल का दूसरा अंक = 8, शेषफल =5
(iv) नया भाज्य = 52
संशोधित(RBSESolutions.com) भाज्य = 52 – 8 x 2
= 36
= अन्तिम शेषफल
अतः भागफल = 88, शेषफल = 36.

We hope the RBSE Solutions for Class 8 Maths Chapter 5 वैदिक गणित Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 5 वैदिक गणित Additional Questions, drop a comment below and we will get back to you at the earliest.

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