RBSE Solutions for Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1

RBSE Solutions for Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 5 Vedic Mathematics Exercise 5.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 8
Subject	Maths
Chapter	Chapter 5
Chapter Name	Vedic Mathematics
Exercise	Exercise 5.1
Number of Questions	3
Category	RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1

Question 1.
Multiply by using Urdhwtirgbyaam formula
(i) 101 x 105
(ii) 11 x 15
(iii) 18 x 81
(iv) 121 x 129
Solution
(i) 101 x 105
Step 1.

Step 2.
Here the number groups = 3 x 2 – 1 = 5

Step 3.
1 x 1 / 1 x 0 + 0 x 1 / 1 x 5 + 1 x 1 + 0 x 0 / 0 x 5 + 1 x 0 / 1 x 5
Step 4.

Therefore, the(RBSESolutions.com)required product of 101 x 105, we get 10605

(ii) 11 x 15
Step 1.

Step 2.

Step 3.
1 x 1 / 1 x 5 + 1 x 1 / 1 x 5
Step 4.

Therefore, the required product of 11 x 15, we get 165

(iii) 18 x 81
Step 1.

Step 2.

Step 3.
1 x 8 / 1 x 1 + 8 x 8 / 8 x 1
Step 4.

Therefore, the(RBSESolutions.com)required product of 18 x 81,
we get 1458

(iv) 121 x 129
Step 1.

Step 2.

Step 3.
1 x 1 / 1 x 2 + 2 x 1 / 1 x 9 + 1 x 1 + 2 x 2 / 2 x 9 + 1 x 2 / 1 x 9
Step 4.

Therefore, the required product of 121 x 129, we get 15609

Question 2.
Multiply by using Nikhilam formula
(i) 48 x 51
(ii) 21 x 29
(iii) 36 x 34
(iv) 18 x 21
(v) 21 x 22 x 23
(vi) 31 x 28 x 27
(vii) 96 x 97 x 95
(viii) 18 x 18 x 18
(ix) 99 x 99 x 99
Solution
(i) 48 x 51
Base = 10
Sub-base = 5 x 10 = 50
Sub-base digit = 50 ÷ 10 = 5
Deviation from Sub-base = 48 – 50 = – 2;
51 – 50 = 1

Therefore, the required product of 48 x 51, we get 2448

(ii) 27 x 29
Base = 10
Sub-base = 2 x 10 = 20
Sub-base digit = 20 ÷ 10 = 2
Deviation from Sub-base = 27 – 20 = 7;
29 – 20 = 9

Therefore, the required product of 27 x 29, we get 783

(iii) 36 x 34
Base = 10
Sub-base = 3 x 10 = 30
Sub-base digit = 30 ÷ 10 = 3
Deviation from Sub-base = 36 – 30 = 6;
34 – 30 = 4

Therefore, the required product of 36 x 34, we get 1224

(iv) 18 x 21
Base = 10
Sub-base = 2 x 10 = 20
Sub-base digit = 20 ÷ 10 = 2
Deviation from Sub-base = 18 – 20 = – 2;
21 – 20 = 1

Therefore, the required product of 18
we get 378

(v) 21 x 22 x 23
Base of 21, 22, 23 = 20
Deviation = 1, 2, 3

Therefore, the required product of 21 x 22 x 23, we get 10626

(vi) 31 x 28 x 27
Step 1. Base of 31, 28, 27 = 30
Deviation = 1,-2,-3

Therefore, the required product of Number
31 x 28 x 27, we get 23436

(vii) 96 x 97 x 95
Step 1. Base of 96, 97, 95 = 90
Deviation = 6, 7, 5

Therefore, the required of product of
Number 96 x 97 x 95, we get 884640

(viii) 18 x 18 x 18
Step 1. Base of 18, 18, 18 = 20
Deviation = – 2, – 2, – 2

Therefore, the required product of(RBSESolutions.com)Number 18 x 18 x 18, we get 5832

(ix) 99 x 99 x 99
Step 1. Base of 99, 99, 99 = 100
Deviation = – 1, – 1, – 1

Therefore, the required(RBSESolutions.com)product of Number, 99 x 99 x 99, we get 970299

Question 3.
Divide by using ‘Dhwajanka’ formula
(i) 3987 ÷ 28
(ii) 5786 ÷ 78
(iii) 7396 ÷ 82
Solution
(i) 3987 ÷ 28

Quotient = 142,
Remainder =11
(ii) 5786 ÷ 78

Quotient = 74,
Remainder = 14
(iii) 7396 ÷ 82

Quotient = 90,
Remainder = 16

We hope the given RBSE Solutions for Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 5 Vedic Mathematics Exercise 5.1, drop a comment below and we will get back to you at the earliest.