RBSE Solutions for Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 5 Vedic Mathematics Exercise 5.1.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 5 |

Chapter Name |
Vedic Mathematics |

Exercise |
Exercise 5.1 |

Number of Questions |
3 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1

Question 1.

Multiply by using Urdhwtirgbyaam formula

(i) 101 x 105

(ii) 11 x 15

(iii) 18 x 81

(iv) 121 x 129

Solution

(i) 101 x 105

Step 1.

Step 2.

Here the number groups = 3 x 2 – 1 = 5

Step 3.

1 x 1 / 1 x 0 + 0 x 1 / 1 x 5 + 1 x 1 + 0 x 0 / 0 x 5 + 1 x 0 / 1 x 5

Step 4.

Therefore, the(RBSESolutions.com)required product of 101 x 105, we get 10605

(ii) 11 x 15

Step 1.

Step 2.

Step 3.

1 x 1 / 1 x 5 + 1 x 1 / 1 x 5

Step 4.

Therefore, the required product of 11 x 15, we get 165

(iii) 18 x 81

Step 1.

Step 2.

Step 3.

1 x 8 / 1 x 1 + 8 x 8 / 8 x 1

Step 4.

Therefore, the(RBSESolutions.com)required product of 18 x 81,

we get 1458

(iv) 121 x 129

Step 1.

Step 2.

Step 3.

1 x 1 / 1 x 2 + 2 x 1 / 1 x 9 + 1 x 1 + 2 x 2 / 2 x 9 + 1 x 2 / 1 x 9

Step 4.

Therefore, the required product of 121 x 129, we get 15609

Question 2.

Multiply by using Nikhilam formula

(i) 48 x 51

(ii) 21 x 29

(iii) 36 x 34

(iv) 18 x 21

(v) 21 x 22 x 23

(vi) 31 x 28 x 27

(vii) 96 x 97 x 95

(viii) 18 x 18 x 18

(ix) 99 x 99 x 99

Solution

(i) 48 x 51

Base = 10

Sub-base = 5 x 10 = 50

Sub-base digit = 50 ÷ 10 = 5

Deviation from Sub-base = 48 – 50 = – 2;

51 – 50 = 1

Therefore, the required product of 48 x 51, we get 2448

(ii) 27 x 29

Base = 10

Sub-base = 2 x 10 = 20

Sub-base digit = 20 ÷ 10 = 2

Deviation from Sub-base = 27 – 20 = 7;

29 – 20 = 9

Therefore, the required product of 27 x 29, we get 783

(iii) 36 x 34

Base = 10

Sub-base = 3 x 10 = 30

Sub-base digit = 30 ÷ 10 = 3

Deviation from Sub-base = 36 – 30 = 6;

34 – 30 = 4

Therefore, the required product of 36 x 34, we get 1224

(iv) 18 x 21

Base = 10

Sub-base = 2 x 10 = 20

Sub-base digit = 20 ÷ 10 = 2

Deviation from Sub-base = 18 – 20 = – 2;

21 – 20 = 1

Therefore, the required product of 18

we get 378

(v) 21 x 22 x 23

Base of 21, 22, 23 = 20

Deviation = 1, 2, 3

Therefore, the required product of 21 x 22 x 23, we get 10626

(vi) 31 x 28 x 27

Step 1. Base of 31, 28, 27 = 30

Deviation = 1,-2,-3

Therefore, the required product of Number

31 x 28 x 27, we get 23436

(vii) 96 x 97 x 95

Step 1. Base of 96, 97, 95 = 90

Deviation = 6, 7, 5

Therefore, the required of product of

Number 96 x 97 x 95, we get 884640

(viii) 18 x 18 x 18

Step 1. Base of 18, 18, 18 = 20

Deviation = – 2, – 2, – 2

Therefore, the required product of(RBSESolutions.com)Number 18 x 18 x 18, we get 5832

(ix) 99 x 99 x 99

Step 1. Base of 99, 99, 99 = 100

Deviation = – 1, – 1, – 1

Therefore, the required(RBSESolutions.com)product of Number, 99 x 99 x 99, we get 970299

Question 3.

Divide by using ‘Dhwajanka’ formula

(i) 3987 ÷ 28

(ii) 5786 ÷ 78

(iii) 7396 ÷ 82

Solution

(i) 3987 ÷ 28

Quotient = 142,

Remainder =11

(ii) 5786 ÷ 78

Quotient = 74,

Remainder = 14

(iii) 7396 ÷ 82

Quotient = 90,

Remainder = 16

We hope the given RBSE Solutions for Class 8 Maths Chapter 5 Vedic Mathematics Ex 5.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 5 Vedic Mathematics Exercise 5.1, drop a comment below and we will get back to you at the earliest.

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