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RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1

March 15, 2019 by Fazal 1 Comment

RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Exercise 7.1.

Board RBSE
Textbook SIERT, Rajasthan
Class Class 8
Subject Maths
Chapter Chapter 7
Chapter Name Construction of Quadrilaterals
Exercise Exercise 7.1
Number of Questions 5
Category RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1

Question 1.
Construct a quadrilateral ABCD in which AB = 4.0 cm., BC = 6.0 cm., CD = DA = 5.2 cm. and AC = 8.0 cm.
Solution
Draw a rough sketch of the given measurements.
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-1
Steps of Construction

  1. First of all we draw a line segment AB of length 4.0 cm.
  2. Draw a arc of length 6.0 cm(RBSESolutions.com)from point B and an arc of radius 8.0 cm from point A. Both arcs cuts each other at point C. Join AC and BC. So, we obtained a triangle ABC.
  3. Two arcs of radius 5.2 cm. each, are drawn from points A and C intersecting each other at point D. Join AD and CD.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-2
    Thus, we obtained a required quadrilateral ABCD.

RBSE Solutions

Question 2.
Construct a quadrilateral JUMP in which JU = 3.5 cm., UM = 4.0 cm., MP = 5.0 cm., PJ = 4.5 cm. and PU = 6.5 cm.
Solution
Draw a rough sketch of the(RBSESolutions.com)given measurements :
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-3
Steps of Construction

  1. First, we draw a line segment of length JU = 3.5 cm.
  2. Draw an arc of radius 6.5 cm. from point U and an arc of radius 4.5 cm. from point J which cuts the first arc at point P. Join UP and JP. So, we obtained a triangle JUP.
  3. Taking P as center draw(RBSESolutions.com)an arc of radius 5.0 cm. draw an arc of radius 4.0 cm. from point U. Both arc intersect each other at M.
  4. Join PM and UM.
  5. Thus, we obtained a required quadrilateral JUMP.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-4

RBSE Solutions

Question 3.
Construct a parallelogram MORE in which MO = 3.6 cm., OR = 4.2 cm., MR = 6.5 cm. Measure the remaining sides and write them in your notebook.
Solution
Draw a rough sketch of the given(RBSESolutions.com)measurements
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-5
Steps of Construction

  1. First of all we draw a line segment MO = 3.6 cm.
  2. Draw an arc of radius 4.2 cm. from point O and an arc of radius 6.5 cm. from point M which intersect each other at R. Join MR and OR. So, we(RBSESolutions.com)obtained a triangle MOR.
  3. Draw an arc of radius 4.2 cm. from point M and an arc of radius 3.6 cm. from R which intersect each other at E. Join ME and ER. Thus, we get a required parallelogram MORE. Measure of remaining sides are RE = 3.6 cm. and ME 4.2 cm.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-6

RBSE Solutions

Question 4.
Construct a rhombus BEST in which BE = 4.5 cm. and ET = 6.0 cm. Then measure the diagonals BS.
Solution
Draw a rough sketch of the given measurements :
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-7
Steps of Construction

  1. First of all we draw a line segment BE = 4.5 cm.
  2. Draw an arc of radius 4.5 cm. from(RBSESolutions.com)point B and an arc of radius 6.5 cm from point E which intersect each other at T. Join BT and ET. So, we obtained a triangle BET.
    RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-8
  3. Draw an arc of radius 4.5 cm. from point T and an arc of radius 4.5 from E which intersect each other at S. Join ES and TS.
    Thus, we obtained a required rhombus BEST.
    The measure of diagonal BS is 6.8 cm.

RBSE Solutions

Question 5.
Construct a quadrilateral PQRS in which PQ = 4.4 cm., QR = 4.0 cm., RS = 6.4 cm., SP = 2.8 cm. and QS = 6.6 cm. Measure the diagonal PR.
Solution
First of all we draw a rough sketch of the given measurements :
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-9
Steps of Construction

  1. First of all we draw a line of segment PQ = 4.4 cm.
  2. Draw an arc of radius 2.8 cm. from point P and an arc of radius 6.6 cm. from point Q which intersect to each other of point S. Join PS and QS. So, we obtained a triangle PQS.
  3. Taking S as centre draw an arc(RBSESolutions.com)of radius 6.4 cm. and taking Q as centre draw an arc of radius 4 cm. which intersect to each other at point R. Join RQ and RS.

Thus, we obtained a required quadrilateral PQRS.
Length of diagonal PR = 6 cm.
RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 img-10

RBSE Solutions

We hope the given RBSE Solutions for Class 8 Maths Chapter 7 Construction of Quadrilaterals Ex 7.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 7 Construction of Quadrilaterals Exercise 7.1, drop a comment below and we will get back to you at the earliest.

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