RBSE Solutions for Class 8 Maths Chapter 8 Visualization of Solids Additional Questions is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 8 Visualization of Solids Additional Questions.
|Chapter Name||Visualization of Solids|
|Number of Questions||37|
Rajasthan Board RBSE Class 8 Maths Chapter 8 Visualization of Solids Additional Questions
I. Objective Type Questions
Plane figures are called
(d) none of the above
Number of vertices in a cuboid are
Every solid shape is made(RBSESolutions.com)up of various two dimensional figures. These are called
Euler’s formula is
(a) F + V = E + 2
(b) F – V = E – 2
(c) V + E = F + 2
(d) V – E = F – 2
The point where the edges of a solid, is called
An example of three dimensional figure is
Number of faces in a cuboid are
Number of edges in a cube are
Number of faces in a cube
II. Fill in the blanks
Cuboid is a___shape.
3D objects will have___views from different angles.
For any polyhedron, F + V =___ is true.
There is no reference or perspective in a ____
___is very important(RBSESolutions.com)for drawing a picture but it is not relevant for a map.
3. E + 2
III. Very Short Answer Type Questions
Write number of edges and faces in a triangular prism.
Number of edges in a triangular prism = 9 and number of faces in a triangular prism = 5.
What are two dimensional shapes?
The plane figures(RBSESolutions.com)having two measurements, length and breadth, are called two dimensional shapes.
Give 3 examples of two dimensional shapes.
Triangle, rectangle circle etc.
Give 3 examples of three dimensional shapes.
Cuboid, sphere, cylinder etc.
What is the definition of Prism?
A prism is a polyhedron(RBSESolutions.com)whose base and top are congruent polygons and whose other faces, i.e., lateral faces are parallelogram in shapes.
What do you mean by pyramid?
A polyhedron having a polygonal base and triangular sides with a common vertex, is called a pyramid.
Find the number of faces in polyhedron having vertices 10 and edges 16.
Number of vertices (V) = 10, Number of edges (E) =16, Number of faces (F) = ?
Euler formula V + F = E + 2
⇒ 10 + F = 16 + 2
or F = 16 + 2 – 10 = 8
Define a regular polyhedrons.
A polyhedron is said to be(RBSESolutions.com)regular if its faces are made up of regular polygons and the same number of faces meet at each vertex.
Is it possible to have a polyhedron with any given number of faces?
Yes, it is possible only if the number of faces are greatest then or equal to four.
Is a square, prism same as a cube? Explain.
Yes, It can be a cube. But it can be a cuboid also.
Can a polyhedron have(RBSESolutions.com)10 faces, 20 edges and 15 vertices?
Since, F + V = E + 2
As 10 + 15 ≠ 20 + 2
∴ A polyhedron cannot have 10 faces, 20 edges and 15 vertices.
IV. Short Answer Type Questions
One vertex of a cube in cut equidistant from her three sides as shown in fig. How many faces and vertices in new fig.
Number of faces (F) = 7
Number of vertices (V) = 10
Can a polyhedron have for its faces
(i) 3 triangles?
(ii) 4 triangles?
(iii) a square and four triangles?
We know that polyhedron is a solid, which is bounded by four or more polygonal faces in such a way that pairs of faces meet along edges and three or more edges meet in each vertex, therefore,
(i) It is not possible(RBSESolutions.com)that a polyhedron has 3 triangles for its faces.
(ii) 4 triangles can be the faces of a polyhedron.
(iii) A square and 4 triangles can be the faces of a polyhedron.
Which are prisms among the following?
We know that a prism is a polyhedron whose base and top are congruent polygons and lateral faces are parallelogram. Therefore,
(i) A nail is not a prism.
(ii) An unsharpened pencil is a prism.
(iii) A table(RBSESolutions.com)weight is not a prism.
(iv) A box is a prism.
(i) How are prisms and cylinders alike?
(ii) How are pyramids and cones alike?
(i) A prism becomes a cylinder provided the number of sides of its base becomes large and larger.
(ii) A pyramid becomes a(RBSESolutions.com)cone provided the number of sides of its base becomes larger and larger.
Using Euler’s formula find the missing numbers.
For A Polyhedron
Number of faces = ?;
Number of vertices = 6,
Number of Edges = 12
By using Euler’s formula
F + V = E + 2
or F = E + 2 – V = 12 + 2 – 6
F = 14 – 6 = 8
∴ Number of faces F = 8
For B Polyhedron
Number of faces = 5;
Number of vertices = ?,
Number of Edges = 9 ,
By using Euler’s formula
F + V = E + 2
or V = E + 2 – F = 9 + 2 – 5 = 6
∴ Number of vertices = 6
Find number of edges in a polyhedron which have 9 vertices and 9 faces.
Number of vertices (V) = 9
Number(RBSESolutions.com)of faces (F) = 9
To Find : Number of edges.
Euler’s formula : V + F = E + 2
Then, 9 + 9 = E + 2
or 9 + 9 – 2 = E
Hence, E = 16
In a polyhedron, number of faces is 5 and number(RBSESolutions.com)of edges is 9. Find the number of vertices.
Number of faces (F) = 5
Number of Edges (E) = 9
Number of Vertices (V) = ?
We know by Euler’s formula
F + V = E + 2
5 + V = 9 + 2
5 + V = 11
V = 11 – 5
V = 6
∴Number of vertices = 6
We hope the given RBSE Solutions for Class 8 Maths Chapter 8 Visualization of Solids Additional Questions will help you. If you have any query regarding Rajasthan Board RBSE Class 8 Maths Chapter 8 Visualization of Solids Additional Questions, drop a comment below and we will get back to you at the earliest.