RBSE Solutions for Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1

RBSE Solutions for Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1 is part of RBSE Solutions for Class 8 Maths. Here we have given Rajasthan Board RBSE Class 8 Maths Chapter 9 Algebraic Expressions Exercise 9.1.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 8
Subject	Maths
Chapter	Chapter 9
Chapter Name	Algebraic Expressions
Exercise	Exercise 9.1
Number of Questions	4
Category	RBSE Solutions

Rajasthan Board RBSE Class 8 Maths Chapter 9 Algebraic Expressions Ex 9.1

Question 1.
Find the product of the following pairs of monomials.
(i) 3 × 5x
(ii) – 5p, – 2q
(iii) 7l², – 3n²
(iv) 6m, 3n
(v) – 5x², – 2x
Solution
(i) 3 × 5x
= 3 × 5 × x
= 15x
(ii) – 5p,- 2q
= (- 5) × p × (- 2) × q
= (- 5) × (- 2) × p × q
= 10pq
(iii) 7l², – 3n²
= 7 × l² × (- 3) × n²
= 7 × (- 3) × l² × n²
= – 21l²n²
(iv) 6m, 3n
= 6 × m × 3 × n
= 6 × 3 × m × n
= 18 mn
(v) – 5x², – 2x
= (- 5) × x² × (- 2) × x
= (- 5) × (- 2) × x² × x
= 10x³

Question 2.
Complete the table.

X	7	x	y	2z	a	-5b	c
7	49
x
2y
-3a			-3ay
b
y
2x3
a4					a5
z2

Solution

X	7	x	y	2z	a	-5b	c
7	49	7x	7y	14z	7a	-35b	7c
x	7x	x2	xy	2zx	ax	-5bx	cx
2y	14y	2xy	2y2	4yz	2ay	-10by	2cy
-3a	-21a	-3ax	-3ay	-6az	-3a2	15ab	-3ac
b	7b	bx	by	2bz	ab	-5b2	bc
y	7y	xy	y2	2yz	ay	-5by	cy
2x3	143	2x4	2x3y	4x3z	2x3a	-10x3b	2x3c
a4	7a4	a4x	a4y	2a4z	a5	-5a4b	a4c
z2	7z2	xz2	yz2	2z3	az2	-5bz2	cz2

Question 3.
Multiply the following monomials
(i) xy, x²y, xy, x
(ii) m, n, mn, m³n, mn³
(iii) kl, lm, km, klm
Solution
(i) xy, x²y, xy, x
xy × x²y × xy × x
= x × y × x × x × y × x × y × x
= x × x × x × x × x × y × y × y
= x⁵ × y³
= x⁵y³
(ii) m, n, mn, m³n, mn³
m × n × mn × m³n × mn³
= m × n × m × n × m × m × m × n ×m × n × n × n
= m × m × m × m × m × m × n × n × n × n × n × n
= m⁶ × n⁶
= m⁶n⁶
(iii) kl, lm, km, klm
kl × lm × km × klm
= k × l × l × m × k × m × k × l × m
= k × k × k × l × l × l × m × m × m
= k³ × l³ × m³
= k³l³ × m³
= k³l³m³

Question 4.
Find the simple interest = \(\frac { PTR }{ 100 }\), If principal (P) = 4x², time (T) = 5x and rate of interest (R) = 5y.
Solution
Simple Interest = \(\frac { PTR }{ 100 }\)

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