RBSE Solutions for Class 9 Maths Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2

RBSE Solutions for Class 9 Maths Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2.

Board	RBSE
Textbook	SIERT, Rajasthan
Class	Class 9
Subject	Maths
Chapter	Chapter 14
Chapter Name	Trigonometric Ratios of Acute Angles
Exercise	Exercise 14.2
Number of Questions Solved	10
Category	RBSE Solutions

Rajasthan Board RBSE Class 9 Maths Solutions Chapter 14 Trigonometric Ratios of Acute Angles Ex 14.2

Solve the following by using trigonometric identities (1 to 10)
Question 1.
If cosec A = [latex]\frac { 5 }{ 4 }[/latex], then (RBSESolutions.com) evaluate cot A, sin A and cos A.
Solution.

Question 2.
If tan A = [latex]\frac { 20 }{ 21 }[/latex], then (RBSESolutions.com) evaluate cos A and sin A.
Solution.

Question 3.
If sin A = [latex]\frac { 3 }{ 5 }[/latex], then (RBSESolutions.com) evaluate cos A and tan A.
Solution.

Question 4.
If cos B = [latex]\frac { 1 }{ 4 }[/latex], then find (RBSESolutions.com) the remaining trigonometrical ratios.
Solution.

Question 5.
If sin A = [latex]\frac { 5 }{ 13 }[/latex], then (RBSESolutions.com) evaluate cos A and tan A.
Solution.

Question 6.
If tan A = √2 – 1, then prove that sin A cos A = [latex]\frac { 1 }{ 2\surd 2 }[/latex]
Solution.

Question 7.
If tan A = 2, then (RBSESolutions.com) evaluate sec A . sin A + tan²A – cosec A.
Solution.
tan A = 2 (given)

Question 8.
If sin θ = [latex]\frac { 4 }{ 5 }[/latex] then (RBSESolutions.com) evaluate [latex]\frac { 4tan\theta -5cos\theta }{ sec\theta +4cos\theta }[/latex]
Solution.

Question 9.
If cos θ = [latex]\frac { 1 }{ \surd 2 }[/latex], then (RBSESolutions.com) evaluate sin θ and cot θ
Solution.

Question 10.
If sec θ = 2, then evaluate tan θ, cos θ and sin θ.
Solution.
sec θ = 2 (given)
We know that 1 + tan²θ = sec²θ
tan²θ = sec²θ – 1

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